How to explort content from file into variable? [duplicate]
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How do I assign the output of a command to a variable?
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I need save into variable the file content (json string).
I try several methods, in particular:
#!/bin/bash
myjson=cat patch/file.jsn
but nothing not work.
How to correctly implement this task?
bash environment-variables
asked Nov 17 at 9:34
Valentyn Hruzytskyi
2009
marked as duplicate by muru bash
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Nov 17 at 9:42
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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This question already has an answer here:
How do I assign the output of a command to a variable?
1 answer
I need save into variable the file content (json string).
I try several methods, in particular:
#!/bin/bash
myjson=cat patch/file.jsn
but nothing not work.
How to correctly implement this task?
bash environment-variables
asked Nov 17 at 9:34
Valentyn Hruzytskyi
2009
marked as duplicate by muru bash
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Nov 17 at 9:42
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
– guiverc
Nov 17 at 9:38
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favorite
up vote
0
down vote
favorite
This question already has an answer here:
How do I assign the output of a command to a variable?
1 answer
I need save into variable the file content (json string).
I try several methods, in particular:
#!/bin/bash
myjson=cat patch/file.jsn
but nothing not work.
How to correctly implement this task?
bash environment-variables
asked Nov 17 at 9:34
Valentyn Hruzytskyi
2009
This question already has an answer here:
How do I assign the output of a command to a variable?
1 answer
I need save into variable the file content (json string).
I try several methods, in particular:
#!/bin/bash
myjson=cat patch/file.jsn
but nothing not work.
How to correctly implement this task?
This question already has an answer here:
How do I assign the output of a command to a variable?
1 answer
bash environment-variables
bash environment-variables
asked Nov 17 at 9:34
Valentyn Hruzytskyi
2009
asked Nov 17 at 9:34
Valentyn Hruzytskyi
2009
asked Nov 17 at 9:34
Valentyn Hruzytskyi
2009
asked Nov 17 at 9:34
Valentyn Hruzytskyi
2009
asked Nov 17 at 9:34
Valentyn Hruzytskyi
2009
2009
marked as duplicate by muru bash
Users with the bash badge can single-handedly close bash questions as duplicates and reopen them as needed.
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Nov 17 at 9:42
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Nov 17 at 9:42
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
– guiverc
Nov 17 at 9:38
add a comment |
1
mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
– guiverc
Nov 17 at 9:38
1
1
mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
– guiverc
Nov 17 at 9:38
mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
– guiverc
Nov 17 at 9:38
add a comment |
1 Answer
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You can try this:
#!/bin/bash
myjson=$(cat patch/file.jsn)
answered Nov 17 at 9:39
kukulo
1,235417
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1 Answer
1
active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
You can try this:
#!/bin/bash
myjson=$(cat patch/file.jsn)
answered Nov 17 at 9:39
kukulo
1,235417
add a comment |
up vote
1
down vote
You can try this:
#!/bin/bash
myjson=$(cat patch/file.jsn)
answered Nov 17 at 9:39
kukulo
1,235417
add a comment |
up vote
1
down vote
up vote
1
down vote
You can try this:
#!/bin/bash
myjson=$(cat patch/file.jsn)
answered Nov 17 at 9:39
kukulo
1,235417
You can try this:
#!/bin/bash
myjson=$(cat patch/file.jsn)
answered Nov 17 at 9:39
kukulo
1,235417
answered Nov 17 at 9:39
kukulo
1,235417
answered Nov 17 at 9:39
kukulo
1,235417
answered Nov 17 at 9:39
kukulo
1,235417
1,235417
add a comment |
add a comment |
1
mjson=`cat patch/file.jsn` (backticks cause the command's output to replace the command)
– guiverc
Nov 17 at 9:38