Sparse recovery with L1 shrinkage iteration for higher denominational image classification











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For 2 months I have been studying sparse recovery and its applications for image classification and I have found that it's a broad area in mathematics which gives rise to a wide variety of regularization techniques. However, I am struggling to understand and implement the sparse recovery of the sparse vector by $L_1$ shrinkage iteration based on prior knowledge of labels.



Actually, I have a dictionary size $200 times 58000$ (fat matrix) which constructed by a prior knowledge of classes (which needs to be redundant), and I have the knowledge of labels and I try to find the $L^1$ optimal solution using soft-shrinkage iteration which is as follows:



We have the linear combination.
$$y = Dx$$
and we use the least squares method to minimize $x$



$$|y - Dx|^2 + lambda|x|_1tomin_x$$



My question is, how to compute the $x$ first and then create an iterative method to update its quantity?



Or should I initialize $x$ to e.g $0$ and then wrap it with an iterative method to be updated? if so, how to formulate that particular iterative method?



Appreciate your help and response.



Edited



Is the following equation the derivation of least squire with $L_1$?
How can I end up to the following equation?



Note: Of course the superscripts denote the number of iterations.



$$x^{n+1} = Slambda /2(x^n + D^T(y - D x^n)) $$










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    up vote
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    down vote

    favorite












    For 2 months I have been studying sparse recovery and its applications for image classification and I have found that it's a broad area in mathematics which gives rise to a wide variety of regularization techniques. However, I am struggling to understand and implement the sparse recovery of the sparse vector by $L_1$ shrinkage iteration based on prior knowledge of labels.



    Actually, I have a dictionary size $200 times 58000$ (fat matrix) which constructed by a prior knowledge of classes (which needs to be redundant), and I have the knowledge of labels and I try to find the $L^1$ optimal solution using soft-shrinkage iteration which is as follows:



    We have the linear combination.
    $$y = Dx$$
    and we use the least squares method to minimize $x$



    $$|y - Dx|^2 + lambda|x|_1tomin_x$$



    My question is, how to compute the $x$ first and then create an iterative method to update its quantity?



    Or should I initialize $x$ to e.g $0$ and then wrap it with an iterative method to be updated? if so, how to formulate that particular iterative method?



    Appreciate your help and response.



    Edited



    Is the following equation the derivation of least squire with $L_1$?
    How can I end up to the following equation?



    Note: Of course the superscripts denote the number of iterations.



    $$x^{n+1} = Slambda /2(x^n + D^T(y - D x^n)) $$










    share|cite|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      For 2 months I have been studying sparse recovery and its applications for image classification and I have found that it's a broad area in mathematics which gives rise to a wide variety of regularization techniques. However, I am struggling to understand and implement the sparse recovery of the sparse vector by $L_1$ shrinkage iteration based on prior knowledge of labels.



      Actually, I have a dictionary size $200 times 58000$ (fat matrix) which constructed by a prior knowledge of classes (which needs to be redundant), and I have the knowledge of labels and I try to find the $L^1$ optimal solution using soft-shrinkage iteration which is as follows:



      We have the linear combination.
      $$y = Dx$$
      and we use the least squares method to minimize $x$



      $$|y - Dx|^2 + lambda|x|_1tomin_x$$



      My question is, how to compute the $x$ first and then create an iterative method to update its quantity?



      Or should I initialize $x$ to e.g $0$ and then wrap it with an iterative method to be updated? if so, how to formulate that particular iterative method?



      Appreciate your help and response.



      Edited



      Is the following equation the derivation of least squire with $L_1$?
      How can I end up to the following equation?



      Note: Of course the superscripts denote the number of iterations.



      $$x^{n+1} = Slambda /2(x^n + D^T(y - D x^n)) $$










      share|cite|improve this question















      For 2 months I have been studying sparse recovery and its applications for image classification and I have found that it's a broad area in mathematics which gives rise to a wide variety of regularization techniques. However, I am struggling to understand and implement the sparse recovery of the sparse vector by $L_1$ shrinkage iteration based on prior knowledge of labels.



      Actually, I have a dictionary size $200 times 58000$ (fat matrix) which constructed by a prior knowledge of classes (which needs to be redundant), and I have the knowledge of labels and I try to find the $L^1$ optimal solution using soft-shrinkage iteration which is as follows:



      We have the linear combination.
      $$y = Dx$$
      and we use the least squares method to minimize $x$



      $$|y - Dx|^2 + lambda|x|_1tomin_x$$



      My question is, how to compute the $x$ first and then create an iterative method to update its quantity?



      Or should I initialize $x$ to e.g $0$ and then wrap it with an iterative method to be updated? if so, how to formulate that particular iterative method?



      Appreciate your help and response.



      Edited



      Is the following equation the derivation of least squire with $L_1$?
      How can I end up to the following equation?



      Note: Of course the superscripts denote the number of iterations.



      $$x^{n+1} = Slambda /2(x^n + D^T(y - D x^n)) $$







      least-squares regularization sparse-matrices sparsity






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      edited 2 days ago

























      asked Nov 15 at 23:56









      morteza

      35




      35






















          1 Answer
          1






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          oldest

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          up vote
          0
          down vote



          accepted










          You may solve the minimisation problem



          $$|y-Dx|+lambda|x|_1tomin_x$$



          using the so-called Fast Iterative Shrinkage Thresholding Algorithm (FISTA).



          It's an iterative method which essentially consists of setting of setting the step size $L$ as the largest eigenvalue of $D^ast D$, the initial values as $z_1=x_0$, $t_1=1$ and iterating



          $$z_k=operatorname{prox}_{Lfrac{1}{lambda}|cdot|_1}(y-D^ast(y-Dx_k)),$$
          $$t_{k+1}=frac{1+sqrt{1+4t^2_k}}{2},$$
          $$x_{k+1}=z_k+left(frac{t_k-1}{t_{k-1}}right)(z_k-z_{k-1}).$$



          Note that the nice property of the $|cdot|_1$ regularisation term is that it has a closed form proximal mapping operator:



          $$operatorname{prox}_{alpha|cdot|_1}(x)=operatorname{sign}(x_i)max{|x_i|-alpha,0},$$
          which is just the soft thresholding operator.



          You can read more about FISTA here: FISTA






          share|cite|improve this answer





















          • Dear Kemal, I do appreciate you for the answer. I have found it helpful. BTW, I have added an Edited part which tells the point which I want.
            – morteza
            2 days ago











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          1 Answer
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          active

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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

          oldest

          votes








          up vote
          0
          down vote



          accepted










          You may solve the minimisation problem



          $$|y-Dx|+lambda|x|_1tomin_x$$



          using the so-called Fast Iterative Shrinkage Thresholding Algorithm (FISTA).



          It's an iterative method which essentially consists of setting of setting the step size $L$ as the largest eigenvalue of $D^ast D$, the initial values as $z_1=x_0$, $t_1=1$ and iterating



          $$z_k=operatorname{prox}_{Lfrac{1}{lambda}|cdot|_1}(y-D^ast(y-Dx_k)),$$
          $$t_{k+1}=frac{1+sqrt{1+4t^2_k}}{2},$$
          $$x_{k+1}=z_k+left(frac{t_k-1}{t_{k-1}}right)(z_k-z_{k-1}).$$



          Note that the nice property of the $|cdot|_1$ regularisation term is that it has a closed form proximal mapping operator:



          $$operatorname{prox}_{alpha|cdot|_1}(x)=operatorname{sign}(x_i)max{|x_i|-alpha,0},$$
          which is just the soft thresholding operator.



          You can read more about FISTA here: FISTA






          share|cite|improve this answer





















          • Dear Kemal, I do appreciate you for the answer. I have found it helpful. BTW, I have added an Edited part which tells the point which I want.
            – morteza
            2 days ago















          up vote
          0
          down vote



          accepted










          You may solve the minimisation problem



          $$|y-Dx|+lambda|x|_1tomin_x$$



          using the so-called Fast Iterative Shrinkage Thresholding Algorithm (FISTA).



          It's an iterative method which essentially consists of setting of setting the step size $L$ as the largest eigenvalue of $D^ast D$, the initial values as $z_1=x_0$, $t_1=1$ and iterating



          $$z_k=operatorname{prox}_{Lfrac{1}{lambda}|cdot|_1}(y-D^ast(y-Dx_k)),$$
          $$t_{k+1}=frac{1+sqrt{1+4t^2_k}}{2},$$
          $$x_{k+1}=z_k+left(frac{t_k-1}{t_{k-1}}right)(z_k-z_{k-1}).$$



          Note that the nice property of the $|cdot|_1$ regularisation term is that it has a closed form proximal mapping operator:



          $$operatorname{prox}_{alpha|cdot|_1}(x)=operatorname{sign}(x_i)max{|x_i|-alpha,0},$$
          which is just the soft thresholding operator.



          You can read more about FISTA here: FISTA






          share|cite|improve this answer





















          • Dear Kemal, I do appreciate you for the answer. I have found it helpful. BTW, I have added an Edited part which tells the point which I want.
            – morteza
            2 days ago













          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          You may solve the minimisation problem



          $$|y-Dx|+lambda|x|_1tomin_x$$



          using the so-called Fast Iterative Shrinkage Thresholding Algorithm (FISTA).



          It's an iterative method which essentially consists of setting of setting the step size $L$ as the largest eigenvalue of $D^ast D$, the initial values as $z_1=x_0$, $t_1=1$ and iterating



          $$z_k=operatorname{prox}_{Lfrac{1}{lambda}|cdot|_1}(y-D^ast(y-Dx_k)),$$
          $$t_{k+1}=frac{1+sqrt{1+4t^2_k}}{2},$$
          $$x_{k+1}=z_k+left(frac{t_k-1}{t_{k-1}}right)(z_k-z_{k-1}).$$



          Note that the nice property of the $|cdot|_1$ regularisation term is that it has a closed form proximal mapping operator:



          $$operatorname{prox}_{alpha|cdot|_1}(x)=operatorname{sign}(x_i)max{|x_i|-alpha,0},$$
          which is just the soft thresholding operator.



          You can read more about FISTA here: FISTA






          share|cite|improve this answer












          You may solve the minimisation problem



          $$|y-Dx|+lambda|x|_1tomin_x$$



          using the so-called Fast Iterative Shrinkage Thresholding Algorithm (FISTA).



          It's an iterative method which essentially consists of setting of setting the step size $L$ as the largest eigenvalue of $D^ast D$, the initial values as $z_1=x_0$, $t_1=1$ and iterating



          $$z_k=operatorname{prox}_{Lfrac{1}{lambda}|cdot|_1}(y-D^ast(y-Dx_k)),$$
          $$t_{k+1}=frac{1+sqrt{1+4t^2_k}}{2},$$
          $$x_{k+1}=z_k+left(frac{t_k-1}{t_{k-1}}right)(z_k-z_{k-1}).$$



          Note that the nice property of the $|cdot|_1$ regularisation term is that it has a closed form proximal mapping operator:



          $$operatorname{prox}_{alpha|cdot|_1}(x)=operatorname{sign}(x_i)max{|x_i|-alpha,0},$$
          which is just the soft thresholding operator.



          You can read more about FISTA here: FISTA







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 18 at 16:52









          Kemal Raik

          304




          304












          • Dear Kemal, I do appreciate you for the answer. I have found it helpful. BTW, I have added an Edited part which tells the point which I want.
            – morteza
            2 days ago


















          • Dear Kemal, I do appreciate you for the answer. I have found it helpful. BTW, I have added an Edited part which tells the point which I want.
            – morteza
            2 days ago
















          Dear Kemal, I do appreciate you for the answer. I have found it helpful. BTW, I have added an Edited part which tells the point which I want.
          – morteza
          2 days ago




          Dear Kemal, I do appreciate you for the answer. I have found it helpful. BTW, I have added an Edited part which tells the point which I want.
          – morteza
          2 days ago


















           

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