Iterative Fibonacci sequence
up vote
3
down vote
favorite
I implemented a function that prints all the numbers from the Fibonacci sequence until max_num. The minimum value allowed is 0 (so, fib(0) prints 1). It works until 92, and I want to know how to improve the code, in general.
void fib(unsigned int max_num)
{
unsigned long fib_num = 1;
unsigned long fib_temp = 0;
size_t count = 0;
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
for (; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
}
beginner c fibonacci-sequence
asked Aug 22 '16 at 21:40
Lúcio Cardoso
447314
add a comment |
up vote
3
down vote
favorite
I implemented a function that prints all the numbers from the Fibonacci sequence until max_num. The minimum value allowed is 0 (so, fib(0) prints 1). It works until 92, and I want to know how to improve the code, in general.
void fib(unsigned int max_num)
{
unsigned long fib_num = 1;
unsigned long fib_temp = 0;
size_t count = 0;
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
for (; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
}
beginner c fibonacci-sequence
asked Aug 22 '16 at 21:40
Lúcio Cardoso
447314
add a comment |
up vote
3
down vote
favorite
up vote
3
down vote
favorite
I implemented a function that prints all the numbers from the Fibonacci sequence until max_num. The minimum value allowed is 0 (so, fib(0) prints 1). It works until 92, and I want to know how to improve the code, in general.
void fib(unsigned int max_num)
{
unsigned long fib_num = 1;
unsigned long fib_temp = 0;
size_t count = 0;
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
for (; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
}
beginner c fibonacci-sequence
asked Aug 22 '16 at 21:40
Lúcio Cardoso
447314
I implemented a function that prints all the numbers from the Fibonacci sequence until max_num. The minimum value allowed is 0 (so, fib(0) prints 1). It works until 92, and I want to know how to improve the code, in general.
void fib(unsigned int max_num)
{
unsigned long fib_num = 1;
unsigned long fib_temp = 0;
size_t count = 0;
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
for (; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
}
beginner c fibonacci-sequence
beginner c fibonacci-sequence
asked Aug 22 '16 at 21:40
Lúcio Cardoso
447314
asked Aug 22 '16 at 21:40
Lúcio Cardoso
447314
asked Aug 22 '16 at 21:40
Lúcio Cardoso
447314
asked Aug 22 '16 at 21:40
Lúcio Cardoso
447314
asked Aug 22 '16 at 21:40
Lúcio Cardoso
447314
447314
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
6
down vote
accepted
Consider documenting this function with something like doxygen. At a quick glance, your function can be interpreted two different ways: Print out fib(0), fib(1), ..., or print out all Fibonacci numbers less than or equal to max_num. Documentation will clarify that.
max_num will never be negative. It is defined as an unsigned int, which means it can never hold a negative value. So this:
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
will never happen. (Try calling fib(-2), see what happens)
(Optional) Put size_t count = 0 inside the loop if you can? (You may have to add -std=c99 or something like that to make it work)
for (size_t count = 0; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
edited 7 mins ago
albert
1071
answered Aug 22 '16 at 23:18
Dair
4,417729
Thanks a lot for the answer! I heard some people saying I should stick to the c89 mode. In your opinion, which one is the best?
– Lúcio Cardoso
Aug 23 '16 at 0:33
1
It has a lot to do with how much of the market supports the language... It may have been at the time a better idea to use C89 over C99 because very few compilers supported C99. This isn't true anymore. It might even be better to use C11. (Which I believe is-std=c11). A large part is do you need to support C89? C99? If not, I would just do C99, thefor-loop syntax for C89 is particularly annoying to me.
– Dair
Aug 23 '16 at 0:50
For reference there are answers here: stackoverflow.com/a/11926008/667648 That coincide with my comment.
– Dair
Aug 23 '16 at 0:53
@LúcioCardoso The only more or less relevant compiler not supporting C99 is VS C compiler afaik. But C is mostly broken under Windows, similar to OpenGL. It works, with a few quirks, but it's not for serious development.
– larkey
Aug 24 '16 at 10:23
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
accepted
Consider documenting this function with something like doxygen. At a quick glance, your function can be interpreted two different ways: Print out fib(0), fib(1), ..., or print out all Fibonacci numbers less than or equal to max_num. Documentation will clarify that.
max_num will never be negative. It is defined as an unsigned int, which means it can never hold a negative value. So this:
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
will never happen. (Try calling fib(-2), see what happens)
(Optional) Put size_t count = 0 inside the loop if you can? (You may have to add -std=c99 or something like that to make it work)
for (size_t count = 0; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
edited 7 mins ago
albert
1071
answered Aug 22 '16 at 23:18
Dair
4,417729
Thanks a lot for the answer! I heard some people saying I should stick to the c89 mode. In your opinion, which one is the best?
– Lúcio Cardoso
Aug 23 '16 at 0:33
1
It has a lot to do with how much of the market supports the language... It may have been at the time a better idea to use C89 over C99 because very few compilers supported C99. This isn't true anymore. It might even be better to use C11. (Which I believe is-std=c11). A large part is do you need to support C89? C99? If not, I would just do C99, thefor-loop syntax for C89 is particularly annoying to me.
– Dair
Aug 23 '16 at 0:50
For reference there are answers here: stackoverflow.com/a/11926008/667648 That coincide with my comment.
– Dair
Aug 23 '16 at 0:53
@LúcioCardoso The only more or less relevant compiler not supporting C99 is VS C compiler afaik. But C is mostly broken under Windows, similar to OpenGL. It works, with a few quirks, but it's not for serious development.
– larkey
Aug 24 '16 at 10:23
add a comment |
up vote
6
down vote
accepted
Consider documenting this function with something like doxygen. At a quick glance, your function can be interpreted two different ways: Print out fib(0), fib(1), ..., or print out all Fibonacci numbers less than or equal to max_num. Documentation will clarify that.
max_num will never be negative. It is defined as an unsigned int, which means it can never hold a negative value. So this:
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
will never happen. (Try calling fib(-2), see what happens)
(Optional) Put size_t count = 0 inside the loop if you can? (You may have to add -std=c99 or something like that to make it work)
for (size_t count = 0; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
edited 7 mins ago
albert
1071
answered Aug 22 '16 at 23:18
Dair
4,417729
Thanks a lot for the answer! I heard some people saying I should stick to the c89 mode. In your opinion, which one is the best?
– Lúcio Cardoso
Aug 23 '16 at 0:33
1
It has a lot to do with how much of the market supports the language... It may have been at the time a better idea to use C89 over C99 because very few compilers supported C99. This isn't true anymore. It might even be better to use C11. (Which I believe is-std=c11). A large part is do you need to support C89? C99? If not, I would just do C99, thefor-loop syntax for C89 is particularly annoying to me.
– Dair
Aug 23 '16 at 0:50
For reference there are answers here: stackoverflow.com/a/11926008/667648 That coincide with my comment.
– Dair
Aug 23 '16 at 0:53
@LúcioCardoso The only more or less relevant compiler not supporting C99 is VS C compiler afaik. But C is mostly broken under Windows, similar to OpenGL. It works, with a few quirks, but it's not for serious development.
– larkey
Aug 24 '16 at 10:23
add a comment |
up vote
6
down vote
accepted
up vote
6
down vote
accepted
Consider documenting this function with something like doxygen. At a quick glance, your function can be interpreted two different ways: Print out fib(0), fib(1), ..., or print out all Fibonacci numbers less than or equal to max_num. Documentation will clarify that.
max_num will never be negative. It is defined as an unsigned int, which means it can never hold a negative value. So this:
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
will never happen. (Try calling fib(-2), see what happens)
(Optional) Put size_t count = 0 inside the loop if you can? (You may have to add -std=c99 or something like that to make it work)
for (size_t count = 0; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
edited 7 mins ago
albert
1071
answered Aug 22 '16 at 23:18
Dair
4,417729
Consider documenting this function with something like doxygen. At a quick glance, your function can be interpreted two different ways: Print out fib(0), fib(1), ..., or print out all Fibonacci numbers less than or equal to max_num. Documentation will clarify that.
max_num will never be negative. It is defined as an unsigned int, which means it can never hold a negative value. So this:
if (max_num < 0)
{
fprintf(stderr, "Please, enter a non-negative numbern");
return;
}
will never happen. (Try calling fib(-2), see what happens)
(Optional) Put size_t count = 0 inside the loop if you can? (You may have to add -std=c99 or something like that to make it work)
for (size_t count = 0; count <= max_num; count++)
{
printf("%lun", fib_num);
fib_num += fib_temp;
fib_temp = fib_num - fib_temp;
}
edited 7 mins ago
albert
1071
answered Aug 22 '16 at 23:18
Dair
4,417729
edited 7 mins ago
albert
1071
edited 7 mins ago
albert
1071
edited 7 mins ago
albert
1071
1071
answered Aug 22 '16 at 23:18
Dair
4,417729
answered Aug 22 '16 at 23:18
Dair
4,417729
answered Aug 22 '16 at 23:18
Dair
4,417729
4,417729
Thanks a lot for the answer! I heard some people saying I should stick to the c89 mode. In your opinion, which one is the best?
– Lúcio Cardoso
Aug 23 '16 at 0:33
1
It has a lot to do with how much of the market supports the language... It may have been at the time a better idea to use C89 over C99 because very few compilers supported C99. This isn't true anymore. It might even be better to use C11. (Which I believe is-std=c11). A large part is do you need to support C89? C99? If not, I would just do C99, thefor-loop syntax for C89 is particularly annoying to me.
– Dair
Aug 23 '16 at 0:50
For reference there are answers here: stackoverflow.com/a/11926008/667648 That coincide with my comment.
– Dair
Aug 23 '16 at 0:53
@LúcioCardoso The only more or less relevant compiler not supporting C99 is VS C compiler afaik. But C is mostly broken under Windows, similar to OpenGL. It works, with a few quirks, but it's not for serious development.
– larkey
Aug 24 '16 at 10:23
add a comment |
Thanks a lot for the answer! I heard some people saying I should stick to the c89 mode. In your opinion, which one is the best?
– Lúcio Cardoso
Aug 23 '16 at 0:33
1
It has a lot to do with how much of the market supports the language... It may have been at the time a better idea to use C89 over C99 because very few compilers supported C99. This isn't true anymore. It might even be better to use C11. (Which I believe is-std=c11). A large part is do you need to support C89? C99? If not, I would just do C99, thefor-loop syntax for C89 is particularly annoying to me.
– Dair
Aug 23 '16 at 0:50
For reference there are answers here: stackoverflow.com/a/11926008/667648 That coincide with my comment.
– Dair
Aug 23 '16 at 0:53
@LúcioCardoso The only more or less relevant compiler not supporting C99 is VS C compiler afaik. But C is mostly broken under Windows, similar to OpenGL. It works, with a few quirks, but it's not for serious development.
– larkey
Aug 24 '16 at 10:23
Thanks a lot for the answer! I heard some people saying I should stick to the c89 mode. In your opinion, which one is the best?
– Lúcio Cardoso
Aug 23 '16 at 0:33
Thanks a lot for the answer! I heard some people saying I should stick to the c89 mode. In your opinion, which one is the best?
– Lúcio Cardoso
Aug 23 '16 at 0:33
1
1
It has a lot to do with how much of the market supports the language... It may have been at the time a better idea to use C89 over C99 because very few compilers supported C99. This isn't true anymore. It might even be better to use C11. (Which I believe is
-std=c11). A large part is do you need to support C89? C99? If not, I would just do C99, the for-loop syntax for C89 is particularly annoying to me.– Dair
Aug 23 '16 at 0:50
It has a lot to do with how much of the market supports the language... It may have been at the time a better idea to use C89 over C99 because very few compilers supported C99. This isn't true anymore. It might even be better to use C11. (Which I believe is
-std=c11). A large part is do you need to support C89? C99? If not, I would just do C99, the for-loop syntax for C89 is particularly annoying to me.– Dair
Aug 23 '16 at 0:50
For reference there are answers here: stackoverflow.com/a/11926008/667648 That coincide with my comment.
– Dair
Aug 23 '16 at 0:53
For reference there are answers here: stackoverflow.com/a/11926008/667648 That coincide with my comment.
– Dair
Aug 23 '16 at 0:53
@LúcioCardoso The only more or less relevant compiler not supporting C99 is VS C compiler afaik. But C is mostly broken under Windows, similar to OpenGL. It works, with a few quirks, but it's not for serious development.
– larkey
Aug 24 '16 at 10:23
@LúcioCardoso The only more or less relevant compiler not supporting C99 is VS C compiler afaik. But C is mostly broken under Windows, similar to OpenGL. It works, with a few quirks, but it's not for serious development.
– larkey
Aug 24 '16 at 10:23
add a comment |
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