Finding the definite integral $int_1^e frac{dx}{xsqrt{1+ln^2x}}$
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So I have the following problem: $$int_1^{e} frac{1}{xsqrt{1+ln^2x}}dx $$ Can somebody comfirm that the integral of this is $$ln|sqrt{1+ln^2x}+ ln x|+C$$ and I that the anwser is $$ln |sqrt{2}+1|$$ that is aproximately 0.8814 Does anyone else got the same anwser?
calculus integration definite-integrals closed-form
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edited yesterday
asked Nov 18 at 0:30
Student123
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