Linearly change the step size in a table
up vote
4
down vote
favorite
I am trying to create a table of points, where the size of the step would change linearly from a certain value to another. Bellow is a simple code to demonstrate a table of points with a constant step in X and Y direction.
MasterMesh=Flatten[Table[{XX , YY, 0}, {XX, -1/2, 1/2, 0.2}, {YY, -1/2, 1/2, 0.2}], 1];
ListPointPlot3D[MasterMesh]
My goal would ultimately be, to create a raster of point that is something like shown in the figure bellow (drawn clumsily), where the distances between the new points (marked red bellow) are supposed to change linearly in a way that L1:L2:L3:L4:L5=1:2:3:4:5.
Any help will be much appreciated!
list-manipulation table data
asked Nov 22 at 8:40
marko
756
add a comment |
up vote
4
down vote
favorite
I am trying to create a table of points, where the size of the step would change linearly from a certain value to another. Bellow is a simple code to demonstrate a table of points with a constant step in X and Y direction.
MasterMesh=Flatten[Table[{XX , YY, 0}, {XX, -1/2, 1/2, 0.2}, {YY, -1/2, 1/2, 0.2}], 1];
ListPointPlot3D[MasterMesh]
My goal would ultimately be, to create a raster of point that is something like shown in the figure bellow (drawn clumsily), where the distances between the new points (marked red bellow) are supposed to change linearly in a way that L1:L2:L3:L4:L5=1:2:3:4:5.
Any help will be much appreciated!
list-manipulation table data
asked Nov 22 at 8:40
marko
756
add a comment |
up vote
4
down vote
favorite
up vote
4
down vote
favorite
I am trying to create a table of points, where the size of the step would change linearly from a certain value to another. Bellow is a simple code to demonstrate a table of points with a constant step in X and Y direction.
MasterMesh=Flatten[Table[{XX , YY, 0}, {XX, -1/2, 1/2, 0.2}, {YY, -1/2, 1/2, 0.2}], 1];
ListPointPlot3D[MasterMesh]
My goal would ultimately be, to create a raster of point that is something like shown in the figure bellow (drawn clumsily), where the distances between the new points (marked red bellow) are supposed to change linearly in a way that L1:L2:L3:L4:L5=1:2:3:4:5.
Any help will be much appreciated!
list-manipulation table data
asked Nov 22 at 8:40
marko
756
I am trying to create a table of points, where the size of the step would change linearly from a certain value to another. Bellow is a simple code to demonstrate a table of points with a constant step in X and Y direction.
MasterMesh=Flatten[Table[{XX , YY, 0}, {XX, -1/2, 1/2, 0.2}, {YY, -1/2, 1/2, 0.2}], 1];
ListPointPlot3D[MasterMesh]
My goal would ultimately be, to create a raster of point that is something like shown in the figure bellow (drawn clumsily), where the distances between the new points (marked red bellow) are supposed to change linearly in a way that L1:L2:L3:L4:L5=1:2:3:4:5.
Any help will be much appreciated!
list-manipulation table data
list-manipulation table data
asked Nov 22 at 8:40
marko
756
asked Nov 22 at 8:40
marko
756
asked Nov 22 at 8:40
marko
756
asked Nov 22 at 8:40
marko
756
asked Nov 22 at 8:40
marko
756
756
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
up vote
4
down vote
accepted
g1 = Prepend[Accumulate@Range[5], 0]
(* {0, 1, 3, 6, 10, 15} *)
g2 = Prepend[Accumulate@Reverse@Range[5], 0]
(* {0, 5, 9, 12, 14, 15} *)
Join @@ MapIndexed[{First[#2], #1, 0} &,
Subdivide[g1, g2, 5],
{2}
] // ListPointPlot3D
answered Nov 22 at 9:33
Szabolcs
158k13432926
Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
– marko
Nov 22 at 10:19
@marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
– Szabolcs
Nov 22 at 10:21
Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
– marko
Nov 22 at 10:29
@marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of{First[#2], #1, 0}inMapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
– Szabolcs
Nov 22 at 10:39
Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid)NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
– marko
Nov 22 at 12:35
add a comment |
up vote
2
down vote
MasterMesh =
Flatten[Table[{1.7^x, 1.7^y, 0},
{x, 1, 2, .1},
{y, 1, 2, .1}], 1];
ListPointPlot3D[MasterMesh]
answered Nov 22 at 8:51
David G. Stork
22.9k22051
Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
– marko
Nov 22 at 9:25
add a comment |
up vote
2
down vote
You can change n and range
n = 5
range = .5
d = 2 range/n
x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]
n=12 and range=2
answered Nov 22 at 12:13
J42161217
3,712220
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
g1 = Prepend[Accumulate@Range[5], 0]
(* {0, 1, 3, 6, 10, 15} *)
g2 = Prepend[Accumulate@Reverse@Range[5], 0]
(* {0, 5, 9, 12, 14, 15} *)
Join @@ MapIndexed[{First[#2], #1, 0} &,
Subdivide[g1, g2, 5],
{2}
] // ListPointPlot3D
answered Nov 22 at 9:33
Szabolcs
158k13432926
Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
– marko
Nov 22 at 10:19
@marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
– Szabolcs
Nov 22 at 10:21
Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
– marko
Nov 22 at 10:29
@marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of{First[#2], #1, 0}inMapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
– Szabolcs
Nov 22 at 10:39
Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid)NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
– marko
Nov 22 at 12:35
add a comment |
up vote
4
down vote
accepted
g1 = Prepend[Accumulate@Range[5], 0]
(* {0, 1, 3, 6, 10, 15} *)
g2 = Prepend[Accumulate@Reverse@Range[5], 0]
(* {0, 5, 9, 12, 14, 15} *)
Join @@ MapIndexed[{First[#2], #1, 0} &,
Subdivide[g1, g2, 5],
{2}
] // ListPointPlot3D
answered Nov 22 at 9:33
Szabolcs
158k13432926
Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
– marko
Nov 22 at 10:19
@marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
– Szabolcs
Nov 22 at 10:21
Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
– marko
Nov 22 at 10:29
@marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of{First[#2], #1, 0}inMapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
– Szabolcs
Nov 22 at 10:39
Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid)NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
– marko
Nov 22 at 12:35
add a comment |
up vote
4
down vote
accepted
up vote
4
down vote
accepted
g1 = Prepend[Accumulate@Range[5], 0]
(* {0, 1, 3, 6, 10, 15} *)
g2 = Prepend[Accumulate@Reverse@Range[5], 0]
(* {0, 5, 9, 12, 14, 15} *)
Join @@ MapIndexed[{First[#2], #1, 0} &,
Subdivide[g1, g2, 5],
{2}
] // ListPointPlot3D
answered Nov 22 at 9:33
Szabolcs
158k13432926
g1 = Prepend[Accumulate@Range[5], 0]
(* {0, 1, 3, 6, 10, 15} *)
g2 = Prepend[Accumulate@Reverse@Range[5], 0]
(* {0, 5, 9, 12, 14, 15} *)
Join @@ MapIndexed[{First[#2], #1, 0} &,
Subdivide[g1, g2, 5],
{2}
] // ListPointPlot3D
answered Nov 22 at 9:33
Szabolcs
158k13432926
answered Nov 22 at 9:33
Szabolcs
158k13432926
answered Nov 22 at 9:33
Szabolcs
158k13432926
answered Nov 22 at 9:33
Szabolcs
158k13432926
158k13432926
Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
– marko
Nov 22 at 10:19
@marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
– Szabolcs
Nov 22 at 10:21
Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
– marko
Nov 22 at 10:29
@marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of{First[#2], #1, 0}inMapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
– Szabolcs
Nov 22 at 10:39
Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid)NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
– marko
Nov 22 at 12:35
add a comment |
Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
– marko
Nov 22 at 10:19
@marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
– Szabolcs
Nov 22 at 10:21
Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
– marko
Nov 22 at 10:29
@marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of{First[#2], #1, 0}inMapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)
– Szabolcs
Nov 22 at 10:39
Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid)NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D
– marko
Nov 22 at 12:35
Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
– marko
Nov 22 at 10:19
Thank you for this answer. In a way, this code does what I asked in the question. The only drawback is that I need the distance between the first and last point in X or Y direction to be controlled independently and not related to the number of subdivisions. As is stands now, if I want 5 subdivisions in Y direction, I get the min and max Y coordinate of 1 and 6 respectively. Changing the number of subdivisions to 10, makes them 1 and 11.
– marko
Nov 22 at 10:19
@marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
– Szabolcs
Nov 22 at 10:21
@marko I don't understand your comment. In my code, the mesh size is set independently in the two directions. I also do not understand which direction you are referring to as $x$ and $y$.
– Szabolcs
Nov 22 at 10:21
Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
– marko
Nov 22 at 10:29
Sorry for the unclear comment. As it stands now, the number of subdivisions (set to 5) defined in Subdivide[g1, g2, 5] defines also the length of the mesh in this direction (the direction I called "Y"). Setting the number of divisions to 10, will change the length of the mesh to 10. Is there a way to keep this constant? Similarly, I wish to keep the length of the mesh in the other direction constant (now it is 15), regardless of the number of divisions. Let's say that I wish the mesh to be of length 10 in both directions. Hopefully this is more clear.
– marko
Nov 22 at 10:29
@marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of
{First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)– Szabolcs
Nov 22 at 10:39
@marko You can scale the mesh by inserting the required scaling factor in front of the first or second element of
{First[#2], #1, 0} in MapIndexed. A bit inconvenient, as you'd need to sync the factor with the value in Range and Subdivide, but it will work :-)– Szabolcs
Nov 22 at 10:39
Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid)
NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D– marko
Nov 22 at 12:35
Thank you. I managed to get it working, using the code bellow, where I define number of elements in both directions and the length (for a hyperbolic paraboloid)
NumElements1 = 16; NumElements2 = 10; len = 2; g1 = Prepend[Accumulate@Range[NumElements2], 0]; g2 = Prepend[Accumulate@Reverse@Range[NumElements2], 0]; Flatten[MapIndexed[{len/ Last[g1]*#1, (len/(NumElements1 + 1))*(First[#2] - 1), (len/Last[g1]*#1 - len/2)^2 - ((len/(NumElements1 + 1))*(First[#2] - 1) - len/2)^2} &, Subdivide[g1, g2, NumElements1], {2}], 1] // ListPointPlot3D– marko
Nov 22 at 12:35
add a comment |
up vote
2
down vote
MasterMesh =
Flatten[Table[{1.7^x, 1.7^y, 0},
{x, 1, 2, .1},
{y, 1, 2, .1}], 1];
ListPointPlot3D[MasterMesh]
answered Nov 22 at 8:51
David G. Stork
22.9k22051
Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
– marko
Nov 22 at 9:25
add a comment |
up vote
2
down vote
MasterMesh =
Flatten[Table[{1.7^x, 1.7^y, 0},
{x, 1, 2, .1},
{y, 1, 2, .1}], 1];
ListPointPlot3D[MasterMesh]
answered Nov 22 at 8:51
David G. Stork
22.9k22051
Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
– marko
Nov 22 at 9:25
add a comment |
up vote
2
down vote
up vote
2
down vote
MasterMesh =
Flatten[Table[{1.7^x, 1.7^y, 0},
{x, 1, 2, .1},
{y, 1, 2, .1}], 1];
ListPointPlot3D[MasterMesh]
answered Nov 22 at 8:51
David G. Stork
22.9k22051
MasterMesh =
Flatten[Table[{1.7^x, 1.7^y, 0},
{x, 1, 2, .1},
{y, 1, 2, .1}], 1];
ListPointPlot3D[MasterMesh]
answered Nov 22 at 8:51
David G. Stork
22.9k22051
answered Nov 22 at 8:51
David G. Stork
22.9k22051
answered Nov 22 at 8:51
David G. Stork
22.9k22051
answered Nov 22 at 8:51
David G. Stork
22.9k22051
22.9k22051
Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
– marko
Nov 22 at 9:25
add a comment |
Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
– marko
Nov 22 at 9:25
Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
– marko
Nov 22 at 9:25
Your code indeed produces something similar to what I would need, but the step length is not increasing in a way that I wish. For the set of data that you provided, it goes: L1=0.19, L2=0.21, L3=0.24. Also the max distance in X or Y direction, location of the first point and the step change seem to be all dependable on each other.
– marko
Nov 22 at 9:25
add a comment |
up vote
2
down vote
You can change n and range
n = 5
range = .5
d = 2 range/n
x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]
n=12 and range=2
answered Nov 22 at 12:13
J42161217
3,712220
add a comment |
up vote
2
down vote
You can change n and range
n = 5
range = .5
d = 2 range/n
x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]
n=12 and range=2
answered Nov 22 at 12:13
J42161217
3,712220
add a comment |
up vote
2
down vote
up vote
2
down vote
You can change n and range
n = 5
range = .5
d = 2 range/n
x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]
n=12 and range=2
answered Nov 22 at 12:13
J42161217
3,712220
You can change n and range
n = 5
range = .5
d = 2 range/n
x = FoldList[# + 1/(n*(n + 1)/2)*#2*2 range &, -range, Range@n];
h = Table[{x[[i]], j, 0}, {i, n + 1}, {j, -range, range, d}];
g = Table[Diagonal@Table[{i, k, 0}, {i, x[[j]], -x[[-j]],
Abs[x[[j]] + x[[-j]]]/(n + 1)}, {k, -range, range, d}], {j, 2, n}];
ListPointPlot3D[Join[{h[[1]]}, g, {h[[n + 1]]}],PlotStyle -> PointSize[Large]]
n=12 and range=2
answered Nov 22 at 12:13
J42161217
3,712220
edited Nov 22 at 14:34
answered Nov 22 at 12:13
J42161217
3,712220
answered Nov 22 at 12:13
J42161217
3,712220
answered Nov 22 at 12:13
J42161217
3,712220
3,712220
add a comment |
add a comment |
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