When running a command on a file, is there anyway to reference the file without typing the entire name?
up vote
1
down vote
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For example:
tar xvf test.tar.gz ; rm test.tar.gz
Is there a faster way to reference the file name on the second execution?
I was thinking something like this (which is invalid):
tar xvf test.tar.gz ; rm $1
Anything possible?
I'm fully aware of wildcards.
bash
New contributor
add a comment |
up vote
1
down vote
favorite
For example:
tar xvf test.tar.gz ; rm test.tar.gz
Is there a faster way to reference the file name on the second execution?
I was thinking something like this (which is invalid):
tar xvf test.tar.gz ; rm $1
Anything possible?
I'm fully aware of wildcards.
bash
New contributor
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
For example:
tar xvf test.tar.gz ; rm test.tar.gz
Is there a faster way to reference the file name on the second execution?
I was thinking something like this (which is invalid):
tar xvf test.tar.gz ; rm $1
Anything possible?
I'm fully aware of wildcards.
bash
New contributor
For example:
tar xvf test.tar.gz ; rm test.tar.gz
Is there a faster way to reference the file name on the second execution?
I was thinking something like this (which is invalid):
tar xvf test.tar.gz ; rm $1
Anything possible?
I'm fully aware of wildcards.
bash
bash
New contributor
New contributor
New contributor
asked 3 hours ago
user327021
61
61
New contributor
New contributor
add a comment |
add a comment |
1 Answer
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up vote
4
down vote
You could assign the file name to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_
special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
As an aside, you may want to consider using tar ... && rm ...
, i.e. with the &&
operator instead of a semicolon. That way, the rm
will not run if the first command fails.
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
1 hour ago
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
You could assign the file name to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_
special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
As an aside, you may want to consider using tar ... && rm ...
, i.e. with the &&
operator instead of a semicolon. That way, the rm
will not run if the first command fails.
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
1 hour ago
add a comment |
up vote
4
down vote
You could assign the file name to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_
special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
As an aside, you may want to consider using tar ... && rm ...
, i.e. with the &&
operator instead of a semicolon. That way, the rm
will not run if the first command fails.
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
1 hour ago
add a comment |
up vote
4
down vote
up vote
4
down vote
You could assign the file name to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_
special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
As an aside, you may want to consider using tar ... && rm ...
, i.e. with the &&
operator instead of a semicolon. That way, the rm
will not run if the first command fails.
You could assign the file name to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_
special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
As an aside, you may want to consider using tar ... && rm ...
, i.e. with the &&
operator instead of a semicolon. That way, the rm
will not run if the first command fails.
answered 3 hours ago
ilkkachu
54.8k782148
54.8k782148
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
1 hour ago
add a comment |
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
1 hour ago
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
1 hour ago
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
1 hour ago
add a comment |
user327021 is a new contributor. Be nice, and check out our Code of Conduct.
user327021 is a new contributor. Be nice, and check out our Code of Conduct.
user327021 is a new contributor. Be nice, and check out our Code of Conduct.
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