Is it possible to automatically stringify in Javascript?
up vote
6
down vote
favorite
I know I can create a toString() function on an object, so that every time it's printed or treated like a string it will first stringify the object with that function.
Is it possible to do that directly so I can use String object functions on the object?
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) // error
Is it possible to do so that the object "behaves" like a string when a String function is called on it?
In other words, I'd like objInstance.split() to have the same result as ("" + objInstance).split(''), and also objInstance.length or objInstance.match(/something/) etc. etc.
javascript
asked 3 hours ago
simone
1,37811324
add a comment |
up vote
6
down vote
favorite
I know I can create a toString() function on an object, so that every time it's printed or treated like a string it will first stringify the object with that function.
Is it possible to do that directly so I can use String object functions on the object?
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) // error
Is it possible to do so that the object "behaves" like a string when a String function is called on it?
In other words, I'd like objInstance.split() to have the same result as ("" + objInstance).split(''), and also objInstance.length or objInstance.match(/something/) etc. etc.
javascript
asked 3 hours ago
simone
1,37811324
add a comment |
up vote
6
down vote
favorite
up vote
6
down vote
favorite
I know I can create a toString() function on an object, so that every time it's printed or treated like a string it will first stringify the object with that function.
Is it possible to do that directly so I can use String object functions on the object?
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) // error
Is it possible to do so that the object "behaves" like a string when a String function is called on it?
In other words, I'd like objInstance.split() to have the same result as ("" + objInstance).split(''), and also objInstance.length or objInstance.match(/something/) etc. etc.
javascript
asked 3 hours ago
simone
1,37811324
I know I can create a toString() function on an object, so that every time it's printed or treated like a string it will first stringify the object with that function.
Is it possible to do that directly so I can use String object functions on the object?
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) // error
Is it possible to do so that the object "behaves" like a string when a String function is called on it?
In other words, I'd like objInstance.split() to have the same result as ("" + objInstance).split(''), and also objInstance.length or objInstance.match(/something/) etc. etc.
javascript
javascript
asked 3 hours ago
simone
1,37811324
asked 3 hours ago
simone
1,37811324
edited 2 hours ago
asked 3 hours ago
simone
1,37811324
asked 3 hours ago
simone
1,37811324
asked 3 hours ago
simone
1,37811324
1,37811324
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
up vote
9
down vote
One option would be to return a Proxy that checks whether the property exists on String.prototype, and if it does, calls that property with the string that represents the object:
var SomeObject = function(a, b) {
this.a = a;
this.b = b
return new Proxy(this, {
get: (_, prop) => {
if (this[prop] !== undefined) {
return this[prop];
}
if (String.prototype[prop]) {
return String.prototype[prop].bind(this.a + ' ' + this.b);
}
}
});
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance.split());
console.log(objInstance.trim());
console.log(objInstance.includes('this'));
console.log(objInstance.includes('somethingelse'));answered 2 hours ago
CertainPerformance
72.5k143453
This options is really good, +1
– Just code
2 hours ago
+1. Remark: this definition is only available in ecmascript 6 or later. Reference
– devildelta
2 hours ago
I would recommend to declare the handler object outside of the constructor function, for the same reason that you should define methods on the prototype. Then you'd also use thetargetargument instead of closing overthis.
– Bergi
8 mins ago
add a comment |
up vote
2
down vote
You can let your objects inherit from String so that all string methods become available:
class SomeObject extends String {
constructor(a, b) {
super(a + " " + b);
this.a = a;
this.b = b;
}
}
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));No need to use complicated Proxy solutions :-)
All the String.prototype methods (except for .toString, .valueOf and [Symbol.iterator]) are "intentionally generic; [they do] not require that its this value be a String object. Therefore, [they] can be transferred to other kinds of objects for use as a method." You can call them on any value, they will coerce it to a string (using .toString() or .valueOf as usual).
You don't even need to use ES6 class extends to inherit from builtins, it works in ES5 as well:
function SomeObject(a, b) {
this.a = a;
this.b = b;
}
SomeObject.prototype = Object.create(String.prototype);
SomeObject.prototype.constructor = SomeObject;
SomeObject.prototype.toString = function() {
return this.a + " " + this.b;
};
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));answered 22 mins ago
Bergi
361k57537858
add a comment |
up vote
1
down vote
One option to extend the SomeObject too, something like this.
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
SomeObject.prototype.split = function(){
return this.toString().split('');
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
//console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) answered 2 hours ago
Just code
7,69642966
Interesting thought. I was thinking about doing this programmatically by doing it for all functions - but is there a way to lost all functions of an object?
– simone
2 hours ago
@simonelost all functions of an objectyou mean? Do it only if you have custom requirements, doesn't makes sense if you do it for all the functions.
– Just code
2 hours ago
"lost" should have been "list" - list all functions of an object
– simone
2 hours ago
@simone to handle all the functions of an object, you can use certainperformance's solution.
– Just code
2 hours ago
I was wondering about performance in using Proxy. Same as in setting the prototype in a deleted solution. But both look quite interesting...
– simone
2 hours ago
|
show 1 more comment
up vote
0
down vote
If I understand correctly then you can use spread syntax to achieve this
let a = 'this'; let b = 'that';
const merged = [...a, ...b];
console.log({merged});answered 3 hours ago
diEcho
37k26123197
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53809965%2fis-it-possible-to-automatically-stringify-in-javascript%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
9
down vote
One option would be to return a Proxy that checks whether the property exists on String.prototype, and if it does, calls that property with the string that represents the object:
var SomeObject = function(a, b) {
this.a = a;
this.b = b
return new Proxy(this, {
get: (_, prop) => {
if (this[prop] !== undefined) {
return this[prop];
}
if (String.prototype[prop]) {
return String.prototype[prop].bind(this.a + ' ' + this.b);
}
}
});
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance.split());
console.log(objInstance.trim());
console.log(objInstance.includes('this'));
console.log(objInstance.includes('somethingelse'));answered 2 hours ago
CertainPerformance
72.5k143453
This options is really good, +1
– Just code
2 hours ago
+1. Remark: this definition is only available in ecmascript 6 or later. Reference
– devildelta
2 hours ago
I would recommend to declare the handler object outside of the constructor function, for the same reason that you should define methods on the prototype. Then you'd also use thetargetargument instead of closing overthis.
– Bergi
8 mins ago
add a comment |
up vote
9
down vote
One option would be to return a Proxy that checks whether the property exists on String.prototype, and if it does, calls that property with the string that represents the object:
var SomeObject = function(a, b) {
this.a = a;
this.b = b
return new Proxy(this, {
get: (_, prop) => {
if (this[prop] !== undefined) {
return this[prop];
}
if (String.prototype[prop]) {
return String.prototype[prop].bind(this.a + ' ' + this.b);
}
}
});
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance.split());
console.log(objInstance.trim());
console.log(objInstance.includes('this'));
console.log(objInstance.includes('somethingelse'));answered 2 hours ago
CertainPerformance
72.5k143453
This options is really good, +1
– Just code
2 hours ago
+1. Remark: this definition is only available in ecmascript 6 or later. Reference
– devildelta
2 hours ago
I would recommend to declare the handler object outside of the constructor function, for the same reason that you should define methods on the prototype. Then you'd also use thetargetargument instead of closing overthis.
– Bergi
8 mins ago
add a comment |
up vote
9
down vote
up vote
9
down vote
One option would be to return a Proxy that checks whether the property exists on String.prototype, and if it does, calls that property with the string that represents the object:
var SomeObject = function(a, b) {
this.a = a;
this.b = b
return new Proxy(this, {
get: (_, prop) => {
if (this[prop] !== undefined) {
return this[prop];
}
if (String.prototype[prop]) {
return String.prototype[prop].bind(this.a + ' ' + this.b);
}
}
});
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance.split());
console.log(objInstance.trim());
console.log(objInstance.includes('this'));
console.log(objInstance.includes('somethingelse'));answered 2 hours ago
CertainPerformance
72.5k143453
One option would be to return a Proxy that checks whether the property exists on String.prototype, and if it does, calls that property with the string that represents the object:
var SomeObject = function(a, b) {
this.a = a;
this.b = b
return new Proxy(this, {
get: (_, prop) => {
if (this[prop] !== undefined) {
return this[prop];
}
if (String.prototype[prop]) {
return String.prototype[prop].bind(this.a + ' ' + this.b);
}
}
});
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance.split());
console.log(objInstance.trim());
console.log(objInstance.includes('this'));
console.log(objInstance.includes('somethingelse'));var SomeObject = function(a, b) {
this.a = a;
this.b = b
return new Proxy(this, {
get: (_, prop) => {
if (this[prop] !== undefined) {
return this[prop];
}
if (String.prototype[prop]) {
return String.prototype[prop].bind(this.a + ' ' + this.b);
}
}
});
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance.split());
console.log(objInstance.trim());
console.log(objInstance.includes('this'));
console.log(objInstance.includes('somethingelse'));var SomeObject = function(a, b) {
this.a = a;
this.b = b
return new Proxy(this, {
get: (_, prop) => {
if (this[prop] !== undefined) {
return this[prop];
}
if (String.prototype[prop]) {
return String.prototype[prop].bind(this.a + ' ' + this.b);
}
}
});
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance.split());
console.log(objInstance.trim());
console.log(objInstance.includes('this'));
console.log(objInstance.includes('somethingelse'));answered 2 hours ago
CertainPerformance
72.5k143453
answered 2 hours ago
CertainPerformance
72.5k143453
answered 2 hours ago
CertainPerformance
72.5k143453
answered 2 hours ago
CertainPerformance
72.5k143453
72.5k143453
This options is really good, +1
– Just code
2 hours ago
+1. Remark: this definition is only available in ecmascript 6 or later. Reference
– devildelta
2 hours ago
I would recommend to declare the handler object outside of the constructor function, for the same reason that you should define methods on the prototype. Then you'd also use thetargetargument instead of closing overthis.
– Bergi
8 mins ago
add a comment |
This options is really good, +1
– Just code
2 hours ago
+1. Remark: this definition is only available in ecmascript 6 or later. Reference
– devildelta
2 hours ago
I would recommend to declare the handler object outside of the constructor function, for the same reason that you should define methods on the prototype. Then you'd also use thetargetargument instead of closing overthis.
– Bergi
8 mins ago
This options is really good, +1
– Just code
2 hours ago
This options is really good, +1
– Just code
2 hours ago
+1. Remark: this definition is only available in ecmascript 6 or later. Reference
– devildelta
2 hours ago
+1. Remark: this definition is only available in ecmascript 6 or later. Reference
– devildelta
2 hours ago
I would recommend to declare the handler object outside of the constructor function, for the same reason that you should define methods on the prototype. Then you'd also use the
target argument instead of closing over this.– Bergi
8 mins ago
I would recommend to declare the handler object outside of the constructor function, for the same reason that you should define methods on the prototype. Then you'd also use the
target argument instead of closing over this.– Bergi
8 mins ago
add a comment |
up vote
2
down vote
You can let your objects inherit from String so that all string methods become available:
class SomeObject extends String {
constructor(a, b) {
super(a + " " + b);
this.a = a;
this.b = b;
}
}
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));No need to use complicated Proxy solutions :-)
All the String.prototype methods (except for .toString, .valueOf and [Symbol.iterator]) are "intentionally generic; [they do] not require that its this value be a String object. Therefore, [they] can be transferred to other kinds of objects for use as a method." You can call them on any value, they will coerce it to a string (using .toString() or .valueOf as usual).
You don't even need to use ES6 class extends to inherit from builtins, it works in ES5 as well:
function SomeObject(a, b) {
this.a = a;
this.b = b;
}
SomeObject.prototype = Object.create(String.prototype);
SomeObject.prototype.constructor = SomeObject;
SomeObject.prototype.toString = function() {
return this.a + " " + this.b;
};
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));answered 22 mins ago
Bergi
361k57537858
add a comment |
up vote
2
down vote
You can let your objects inherit from String so that all string methods become available:
class SomeObject extends String {
constructor(a, b) {
super(a + " " + b);
this.a = a;
this.b = b;
}
}
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));No need to use complicated Proxy solutions :-)
All the String.prototype methods (except for .toString, .valueOf and [Symbol.iterator]) are "intentionally generic; [they do] not require that its this value be a String object. Therefore, [they] can be transferred to other kinds of objects for use as a method." You can call them on any value, they will coerce it to a string (using .toString() or .valueOf as usual).
You don't even need to use ES6 class extends to inherit from builtins, it works in ES5 as well:
function SomeObject(a, b) {
this.a = a;
this.b = b;
}
SomeObject.prototype = Object.create(String.prototype);
SomeObject.prototype.constructor = SomeObject;
SomeObject.prototype.toString = function() {
return this.a + " " + this.b;
};
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));answered 22 mins ago
Bergi
361k57537858
add a comment |
up vote
2
down vote
up vote
2
down vote
You can let your objects inherit from String so that all string methods become available:
class SomeObject extends String {
constructor(a, b) {
super(a + " " + b);
this.a = a;
this.b = b;
}
}
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));No need to use complicated Proxy solutions :-)
All the String.prototype methods (except for .toString, .valueOf and [Symbol.iterator]) are "intentionally generic; [they do] not require that its this value be a String object. Therefore, [they] can be transferred to other kinds of objects for use as a method." You can call them on any value, they will coerce it to a string (using .toString() or .valueOf as usual).
You don't even need to use ES6 class extends to inherit from builtins, it works in ES5 as well:
function SomeObject(a, b) {
this.a = a;
this.b = b;
}
SomeObject.prototype = Object.create(String.prototype);
SomeObject.prototype.constructor = SomeObject;
SomeObject.prototype.toString = function() {
return this.a + " " + this.b;
};
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));answered 22 mins ago
Bergi
361k57537858
You can let your objects inherit from String so that all string methods become available:
class SomeObject extends String {
constructor(a, b) {
super(a + " " + b);
this.a = a;
this.b = b;
}
}
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));No need to use complicated Proxy solutions :-)
All the String.prototype methods (except for .toString, .valueOf and [Symbol.iterator]) are "intentionally generic; [they do] not require that its this value be a String object. Therefore, [they] can be transferred to other kinds of objects for use as a method." You can call them on any value, they will coerce it to a string (using .toString() or .valueOf as usual).
You don't even need to use ES6 class extends to inherit from builtins, it works in ES5 as well:
function SomeObject(a, b) {
this.a = a;
this.b = b;
}
SomeObject.prototype = Object.create(String.prototype);
SomeObject.prototype.constructor = SomeObject;
SomeObject.prototype.toString = function() {
return this.a + " " + this.b;
};
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));class SomeObject extends String {
constructor(a, b) {
super(a + " " + b);
this.a = a;
this.b = b;
}
}
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));class SomeObject extends String {
constructor(a, b) {
super(a + " " + b);
this.a = a;
this.b = b;
}
}
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));function SomeObject(a, b) {
this.a = a;
this.b = b;
}
SomeObject.prototype = Object.create(String.prototype);
SomeObject.prototype.constructor = SomeObject;
SomeObject.prototype.toString = function() {
return this.a + " " + this.b;
};
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));function SomeObject(a, b) {
this.a = a;
this.b = b;
}
SomeObject.prototype = Object.create(String.prototype);
SomeObject.prototype.constructor = SomeObject;
SomeObject.prototype.toString = function() {
return this.a + " " + this.b;
};
var obj = new SomeObject('this', 'that');
console.log(obj.split(""));answered 22 mins ago
Bergi
361k57537858
edited 7 mins ago
answered 22 mins ago
Bergi
361k57537858
answered 22 mins ago
Bergi
361k57537858
answered 22 mins ago
Bergi
361k57537858
361k57537858
add a comment |
add a comment |
up vote
1
down vote
One option to extend the SomeObject too, something like this.
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
SomeObject.prototype.split = function(){
return this.toString().split('');
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
//console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) answered 2 hours ago
Just code
7,69642966
Interesting thought. I was thinking about doing this programmatically by doing it for all functions - but is there a way to lost all functions of an object?
– simone
2 hours ago
@simonelost all functions of an objectyou mean? Do it only if you have custom requirements, doesn't makes sense if you do it for all the functions.
– Just code
2 hours ago
"lost" should have been "list" - list all functions of an object
– simone
2 hours ago
@simone to handle all the functions of an object, you can use certainperformance's solution.
– Just code
2 hours ago
I was wondering about performance in using Proxy. Same as in setting the prototype in a deleted solution. But both look quite interesting...
– simone
2 hours ago
|
show 1 more comment
up vote
1
down vote
One option to extend the SomeObject too, something like this.
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
SomeObject.prototype.split = function(){
return this.toString().split('');
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
//console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) answered 2 hours ago
Just code
7,69642966
Interesting thought. I was thinking about doing this programmatically by doing it for all functions - but is there a way to lost all functions of an object?
– simone
2 hours ago
@simonelost all functions of an objectyou mean? Do it only if you have custom requirements, doesn't makes sense if you do it for all the functions.
– Just code
2 hours ago
"lost" should have been "list" - list all functions of an object
– simone
2 hours ago
@simone to handle all the functions of an object, you can use certainperformance's solution.
– Just code
2 hours ago
I was wondering about performance in using Proxy. Same as in setting the prototype in a deleted solution. But both look quite interesting...
– simone
2 hours ago
|
show 1 more comment
up vote
1
down vote
up vote
1
down vote
One option to extend the SomeObject too, something like this.
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
SomeObject.prototype.split = function(){
return this.toString().split('');
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
//console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) answered 2 hours ago
Just code
7,69642966
One option to extend the SomeObject too, something like this.
var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
SomeObject.prototype.split = function(){
return this.toString().split('');
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
//console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
SomeObject.prototype.split = function(){
return this.toString().split('');
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
//console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) var SomeObject = function(a, b){
this.a = a;
this.b = b
}
SomeObject.prototype.toString = function(){
return [ this.a, this.b ].join(' ')
}
SomeObject.prototype.split = function(){
return this.toString().split('');
}
var objInstance = new SomeObject('this', 'that');
console.log(objInstance + '') // this that
//console.log(("" + objInstance).split('')) // [ 't', 'h', 'i', 's', ' ', 't', 'h', 'a', 't' ]
console.log(objInstance.split()) answered 2 hours ago
Just code
7,69642966
answered 2 hours ago
Just code
7,69642966
answered 2 hours ago
Just code
7,69642966
answered 2 hours ago
Just code
7,69642966
7,69642966
Interesting thought. I was thinking about doing this programmatically by doing it for all functions - but is there a way to lost all functions of an object?
– simone
2 hours ago
@simonelost all functions of an objectyou mean? Do it only if you have custom requirements, doesn't makes sense if you do it for all the functions.
– Just code
2 hours ago
"lost" should have been "list" - list all functions of an object
– simone
2 hours ago
@simone to handle all the functions of an object, you can use certainperformance's solution.
– Just code
2 hours ago
I was wondering about performance in using Proxy. Same as in setting the prototype in a deleted solution. But both look quite interesting...
– simone
2 hours ago
|
show 1 more comment
Interesting thought. I was thinking about doing this programmatically by doing it for all functions - but is there a way to lost all functions of an object?
– simone
2 hours ago
@simonelost all functions of an objectyou mean? Do it only if you have custom requirements, doesn't makes sense if you do it for all the functions.
– Just code
2 hours ago
"lost" should have been "list" - list all functions of an object
– simone
2 hours ago
@simone to handle all the functions of an object, you can use certainperformance's solution.
– Just code
2 hours ago
I was wondering about performance in using Proxy. Same as in setting the prototype in a deleted solution. But both look quite interesting...
– simone
2 hours ago
Interesting thought. I was thinking about doing this programmatically by doing it for all functions - but is there a way to lost all functions of an object?
– simone
2 hours ago
Interesting thought. I was thinking about doing this programmatically by doing it for all functions - but is there a way to lost all functions of an object?
– simone
2 hours ago
@simone
lost all functions of an object you mean? Do it only if you have custom requirements, doesn't makes sense if you do it for all the functions.– Just code
2 hours ago
@simone
lost all functions of an object you mean? Do it only if you have custom requirements, doesn't makes sense if you do it for all the functions.– Just code
2 hours ago
"lost" should have been "list" - list all functions of an object
– simone
2 hours ago
"lost" should have been "list" - list all functions of an object
– simone
2 hours ago
@simone to handle all the functions of an object, you can use certainperformance's solution.
– Just code
2 hours ago
@simone to handle all the functions of an object, you can use certainperformance's solution.
– Just code
2 hours ago
I was wondering about performance in using Proxy. Same as in setting the prototype in a deleted solution. But both look quite interesting...
– simone
2 hours ago
I was wondering about performance in using Proxy. Same as in setting the prototype in a deleted solution. But both look quite interesting...
– simone
2 hours ago
|
show 1 more comment
up vote
0
down vote
If I understand correctly then you can use spread syntax to achieve this
let a = 'this'; let b = 'that';
const merged = [...a, ...b];
console.log({merged});answered 3 hours ago
diEcho
37k26123197
add a comment |
up vote
0
down vote
If I understand correctly then you can use spread syntax to achieve this
let a = 'this'; let b = 'that';
const merged = [...a, ...b];
console.log({merged});answered 3 hours ago
diEcho
37k26123197
add a comment |
up vote
0
down vote
up vote
0
down vote
If I understand correctly then you can use spread syntax to achieve this
let a = 'this'; let b = 'that';
const merged = [...a, ...b];
console.log({merged});answered 3 hours ago
diEcho
37k26123197
If I understand correctly then you can use spread syntax to achieve this
let a = 'this'; let b = 'that';
const merged = [...a, ...b];
console.log({merged}); let a = 'this'; let b = 'that';
const merged = [...a, ...b];
console.log({merged}); let a = 'this'; let b = 'that';
const merged = [...a, ...b];
console.log({merged});answered 3 hours ago
diEcho
37k26123197
answered 3 hours ago
diEcho
37k26123197
answered 3 hours ago
diEcho
37k26123197
answered 3 hours ago
diEcho
37k26123197
37k26123197
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53809965%2fis-it-possible-to-automatically-stringify-in-javascript%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
