Python: Optimizing a generator











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For large v_max and v_max_n, the generator below yields very slow when I have 750000000 and 500000000, respectively. I have been trying different ways for days and cannot seem to figure this out.



from itertools import product

n = 15 * 10 ** 8
v_max = math.floor(n / 2 - 1 / (2 * n))
v_max_n = n // 3

(i for i in product(range(2, v_max_n + 1, 2),
range(2, v_max + 1, 2),
range(3, v_max + 1))
if i[0] <= i[1] and i[1] <= i[2] and sum(i) <= n and
i[0] ** 2 + i[1] ** 2 == i[2] ** 2 - 1)


I have tried using it as map(lambda x: x, gen), nested for loops, and have generally been racking my brain to no avail.










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  • For me this does not even fit into memory (16 GB). Which is weird, since product should not make any intermediate lists and neither should range...
    – Graipher
    15 mins ago










  • @Graipher you should just get a generator object when you initialize the generator which shouldn't use any memory
    – dustin
    12 mins ago










  • I agree. Yet it does consume memory on my machine (even with Python 3.6.3).
    – Graipher
    11 mins ago












  • @Graipher I am on 3.6.6 Anaconda on Mac. Only 8 GBs of RAM, I checked my memory when creating the object but didn't have that problem.
    – dustin
    9 mins ago






  • 1




    @Graipher sum(i) <= n. Added the variable definitions.
    – dustin
    7 mins ago

















up vote
1
down vote

favorite












For large v_max and v_max_n, the generator below yields very slow when I have 750000000 and 500000000, respectively. I have been trying different ways for days and cannot seem to figure this out.



from itertools import product

n = 15 * 10 ** 8
v_max = math.floor(n / 2 - 1 / (2 * n))
v_max_n = n // 3

(i for i in product(range(2, v_max_n + 1, 2),
range(2, v_max + 1, 2),
range(3, v_max + 1))
if i[0] <= i[1] and i[1] <= i[2] and sum(i) <= n and
i[0] ** 2 + i[1] ** 2 == i[2] ** 2 - 1)


I have tried using it as map(lambda x: x, gen), nested for loops, and have generally been racking my brain to no avail.










share|improve this question
























  • For me this does not even fit into memory (16 GB). Which is weird, since product should not make any intermediate lists and neither should range...
    – Graipher
    15 mins ago










  • @Graipher you should just get a generator object when you initialize the generator which shouldn't use any memory
    – dustin
    12 mins ago










  • I agree. Yet it does consume memory on my machine (even with Python 3.6.3).
    – Graipher
    11 mins ago












  • @Graipher I am on 3.6.6 Anaconda on Mac. Only 8 GBs of RAM, I checked my memory when creating the object but didn't have that problem.
    – dustin
    9 mins ago






  • 1




    @Graipher sum(i) <= n. Added the variable definitions.
    – dustin
    7 mins ago















up vote
1
down vote

favorite









up vote
1
down vote

favorite











For large v_max and v_max_n, the generator below yields very slow when I have 750000000 and 500000000, respectively. I have been trying different ways for days and cannot seem to figure this out.



from itertools import product

n = 15 * 10 ** 8
v_max = math.floor(n / 2 - 1 / (2 * n))
v_max_n = n // 3

(i for i in product(range(2, v_max_n + 1, 2),
range(2, v_max + 1, 2),
range(3, v_max + 1))
if i[0] <= i[1] and i[1] <= i[2] and sum(i) <= n and
i[0] ** 2 + i[1] ** 2 == i[2] ** 2 - 1)


I have tried using it as map(lambda x: x, gen), nested for loops, and have generally been racking my brain to no avail.










share|improve this question















For large v_max and v_max_n, the generator below yields very slow when I have 750000000 and 500000000, respectively. I have been trying different ways for days and cannot seem to figure this out.



from itertools import product

n = 15 * 10 ** 8
v_max = math.floor(n / 2 - 1 / (2 * n))
v_max_n = n // 3

(i for i in product(range(2, v_max_n + 1, 2),
range(2, v_max + 1, 2),
range(3, v_max + 1))
if i[0] <= i[1] and i[1] <= i[2] and sum(i) <= n and
i[0] ** 2 + i[1] ** 2 == i[2] ** 2 - 1)


I have tried using it as map(lambda x: x, gen), nested for loops, and have generally been racking my brain to no avail.







python performance iterator generator






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 7 mins ago

























asked 24 mins ago









dustin

366




366












  • For me this does not even fit into memory (16 GB). Which is weird, since product should not make any intermediate lists and neither should range...
    – Graipher
    15 mins ago










  • @Graipher you should just get a generator object when you initialize the generator which shouldn't use any memory
    – dustin
    12 mins ago










  • I agree. Yet it does consume memory on my machine (even with Python 3.6.3).
    – Graipher
    11 mins ago












  • @Graipher I am on 3.6.6 Anaconda on Mac. Only 8 GBs of RAM, I checked my memory when creating the object but didn't have that problem.
    – dustin
    9 mins ago






  • 1




    @Graipher sum(i) <= n. Added the variable definitions.
    – dustin
    7 mins ago




















  • For me this does not even fit into memory (16 GB). Which is weird, since product should not make any intermediate lists and neither should range...
    – Graipher
    15 mins ago










  • @Graipher you should just get a generator object when you initialize the generator which shouldn't use any memory
    – dustin
    12 mins ago










  • I agree. Yet it does consume memory on my machine (even with Python 3.6.3).
    – Graipher
    11 mins ago












  • @Graipher I am on 3.6.6 Anaconda on Mac. Only 8 GBs of RAM, I checked my memory when creating the object but didn't have that problem.
    – dustin
    9 mins ago






  • 1




    @Graipher sum(i) <= n. Added the variable definitions.
    – dustin
    7 mins ago


















For me this does not even fit into memory (16 GB). Which is weird, since product should not make any intermediate lists and neither should range...
– Graipher
15 mins ago




For me this does not even fit into memory (16 GB). Which is weird, since product should not make any intermediate lists and neither should range...
– Graipher
15 mins ago












@Graipher you should just get a generator object when you initialize the generator which shouldn't use any memory
– dustin
12 mins ago




@Graipher you should just get a generator object when you initialize the generator which shouldn't use any memory
– dustin
12 mins ago












I agree. Yet it does consume memory on my machine (even with Python 3.6.3).
– Graipher
11 mins ago






I agree. Yet it does consume memory on my machine (even with Python 3.6.3).
– Graipher
11 mins ago














@Graipher I am on 3.6.6 Anaconda on Mac. Only 8 GBs of RAM, I checked my memory when creating the object but didn't have that problem.
– dustin
9 mins ago




@Graipher I am on 3.6.6 Anaconda on Mac. Only 8 GBs of RAM, I checked my memory when creating the object but didn't have that problem.
– dustin
9 mins ago




1




1




@Graipher sum(i) <= n. Added the variable definitions.
– dustin
7 mins ago






@Graipher sum(i) <= n. Added the variable definitions.
– dustin
7 mins ago

















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