Limit Of Infinite Series











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So if an infinite series converges to any real than the limit of the partial sums sequence is equal to 0, right?
Does that mean that the limit of the series is 0 too?
What confuses me is "is the limit of an infinite series equal to it's sum?"



so if the limit of the partial sums sequence is 0, then the sum of the sequence is 0, which allows me to say that the limit of the series is 0, so the series converges to 0?










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    So if an infinite series converges to any real than the limit of the partial sums sequence is equal to 0, right?
    Does that mean that the limit of the series is 0 too?
    What confuses me is "is the limit of an infinite series equal to it's sum?"



    so if the limit of the partial sums sequence is 0, then the sum of the sequence is 0, which allows me to say that the limit of the series is 0, so the series converges to 0?










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      So if an infinite series converges to any real than the limit of the partial sums sequence is equal to 0, right?
      Does that mean that the limit of the series is 0 too?
      What confuses me is "is the limit of an infinite series equal to it's sum?"



      so if the limit of the partial sums sequence is 0, then the sum of the sequence is 0, which allows me to say that the limit of the series is 0, so the series converges to 0?










      share|cite|improve this question













      So if an infinite series converges to any real than the limit of the partial sums sequence is equal to 0, right?
      Does that mean that the limit of the series is 0 too?
      What confuses me is "is the limit of an infinite series equal to it's sum?"



      so if the limit of the partial sums sequence is 0, then the sum of the sequence is 0, which allows me to say that the limit of the series is 0, so the series converges to 0?







      real-analysis sequences-and-series limits






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      asked Nov 22 at 18:04









      YoungDumbBroke

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          What you are saying is not correct. If infinite series converged then partial sum converged to sum. You can say remainder terms goes to zero. Or nth terms tends to zero for large n.






          share|cite|improve this answer




























            up vote
            0
            down vote













            No - the limit of the sequence of partial sums does not have to be $0$.



            For example $$sumlimits_{i=1}^n frac1{2^i} = frac{2^n-1}{2^n} = 1 - frac{1}{2^n}$$ has the partial sums being $frac12,frac34,frac78, cdots$, with an obvious limit of that sequence and of the series being $1$



            It is true that for the series to converge to a finite limit then the individual terms of the series must converge to $0$, though not necessarily the other way round






            share|cite|improve this answer





















            • is the limit of the series equal to it's sum though?
              – YoungDumbBroke
              Nov 22 at 18:12










            • The limit of the series (if it exists) is the limit of the partial sums of the terms of the series
              – Henry
              Nov 22 at 18:17


















            up vote
            0
            down vote













            What you are saying is not correct, recall indeed that by definiton we have



            $$sum_{k=0}^infty a_k = lim _{nto infty} S_n= lim _{nto infty} sum_{k=0}^n a_k$$



            and





            • $sum_{k=0}^infty a_k$ is the (infinite) series


            • $S_n= sum_{k=0}^n a_k$ is the partial sum


            when the series converges, that is $$lim _{nto infty} S_n=Lin mathbb{R}$$ we can derive the necessary condition for convergence



            $$a_n=S_n-S_{n-1} to L-L=0$$






            share|cite|improve this answer




























              up vote
              0
              down vote













              By definition, the sum of an infinite series is the limit of its partial sums:



              $$sum_{i = 0}^{
              infty}a_i := lim_{N to infty}sum_{i = 0}^Na_i$$



              Now, in order for this limit to converge to a real number $L$, it would certainly have to be that the distance between each partial sum and the next gets arbitrarily small - after all, that's a necessary condition for any limit to converge.



              $$sum_{i = 0}^{N + 1}a_i - sum_{i = 0}^Na_i = a_{N + 1}$$



              So the values of $a_N$ must go to zero. That means that it is not correct to say that the limit of the partial sums must be zero, but it is correct to say that the limit of the terms of the series must be zero.



              There is a point of confusion here, though. You keep referring to the limit of a series. That's not typical terminology, because it isn't clear whether you mean the limit of the terms (because you're not mentioning adding things up) or the limit of the partial sums (because you're calling it a "series" and you usually sum series). Generally, we say limit of a sequence and sum of a series. So, to put things as precisely as I can:



              Let $a_0, a_1, ldots, a_i, ldots$ be an infinite sequence. The limit of the sequence is $lim_{i to infty}a_i$. The sum of the series is $sum_{i = 0}^{infty}a_i = lim_{N to infty}sum_{i = 0}^Na_i$. If the sum of the series converges to a real number, then the limit of the sequence must be zero. Because the sum of the series may be nonzero, the limit of the sequence is not necessarily the same as the sum of the series.






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                4 Answers
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                active

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                up vote
                1
                down vote













                What you are saying is not correct. If infinite series converged then partial sum converged to sum. You can say remainder terms goes to zero. Or nth terms tends to zero for large n.






                share|cite|improve this answer

























                  up vote
                  1
                  down vote













                  What you are saying is not correct. If infinite series converged then partial sum converged to sum. You can say remainder terms goes to zero. Or nth terms tends to zero for large n.






                  share|cite|improve this answer























                    up vote
                    1
                    down vote










                    up vote
                    1
                    down vote









                    What you are saying is not correct. If infinite series converged then partial sum converged to sum. You can say remainder terms goes to zero. Or nth terms tends to zero for large n.






                    share|cite|improve this answer












                    What you are saying is not correct. If infinite series converged then partial sum converged to sum. You can say remainder terms goes to zero. Or nth terms tends to zero for large n.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Nov 22 at 18:09









                    Shubham

                    1,5921519




                    1,5921519






















                        up vote
                        0
                        down vote













                        No - the limit of the sequence of partial sums does not have to be $0$.



                        For example $$sumlimits_{i=1}^n frac1{2^i} = frac{2^n-1}{2^n} = 1 - frac{1}{2^n}$$ has the partial sums being $frac12,frac34,frac78, cdots$, with an obvious limit of that sequence and of the series being $1$



                        It is true that for the series to converge to a finite limit then the individual terms of the series must converge to $0$, though not necessarily the other way round






                        share|cite|improve this answer





















                        • is the limit of the series equal to it's sum though?
                          – YoungDumbBroke
                          Nov 22 at 18:12










                        • The limit of the series (if it exists) is the limit of the partial sums of the terms of the series
                          – Henry
                          Nov 22 at 18:17















                        up vote
                        0
                        down vote













                        No - the limit of the sequence of partial sums does not have to be $0$.



                        For example $$sumlimits_{i=1}^n frac1{2^i} = frac{2^n-1}{2^n} = 1 - frac{1}{2^n}$$ has the partial sums being $frac12,frac34,frac78, cdots$, with an obvious limit of that sequence and of the series being $1$



                        It is true that for the series to converge to a finite limit then the individual terms of the series must converge to $0$, though not necessarily the other way round






                        share|cite|improve this answer





















                        • is the limit of the series equal to it's sum though?
                          – YoungDumbBroke
                          Nov 22 at 18:12










                        • The limit of the series (if it exists) is the limit of the partial sums of the terms of the series
                          – Henry
                          Nov 22 at 18:17













                        up vote
                        0
                        down vote










                        up vote
                        0
                        down vote









                        No - the limit of the sequence of partial sums does not have to be $0$.



                        For example $$sumlimits_{i=1}^n frac1{2^i} = frac{2^n-1}{2^n} = 1 - frac{1}{2^n}$$ has the partial sums being $frac12,frac34,frac78, cdots$, with an obvious limit of that sequence and of the series being $1$



                        It is true that for the series to converge to a finite limit then the individual terms of the series must converge to $0$, though not necessarily the other way round






                        share|cite|improve this answer












                        No - the limit of the sequence of partial sums does not have to be $0$.



                        For example $$sumlimits_{i=1}^n frac1{2^i} = frac{2^n-1}{2^n} = 1 - frac{1}{2^n}$$ has the partial sums being $frac12,frac34,frac78, cdots$, with an obvious limit of that sequence and of the series being $1$



                        It is true that for the series to converge to a finite limit then the individual terms of the series must converge to $0$, though not necessarily the other way round







                        share|cite|improve this answer












                        share|cite|improve this answer



                        share|cite|improve this answer










                        answered Nov 22 at 18:10









                        Henry

                        97.9k475158




                        97.9k475158












                        • is the limit of the series equal to it's sum though?
                          – YoungDumbBroke
                          Nov 22 at 18:12










                        • The limit of the series (if it exists) is the limit of the partial sums of the terms of the series
                          – Henry
                          Nov 22 at 18:17


















                        • is the limit of the series equal to it's sum though?
                          – YoungDumbBroke
                          Nov 22 at 18:12










                        • The limit of the series (if it exists) is the limit of the partial sums of the terms of the series
                          – Henry
                          Nov 22 at 18:17
















                        is the limit of the series equal to it's sum though?
                        – YoungDumbBroke
                        Nov 22 at 18:12




                        is the limit of the series equal to it's sum though?
                        – YoungDumbBroke
                        Nov 22 at 18:12












                        The limit of the series (if it exists) is the limit of the partial sums of the terms of the series
                        – Henry
                        Nov 22 at 18:17




                        The limit of the series (if it exists) is the limit of the partial sums of the terms of the series
                        – Henry
                        Nov 22 at 18:17










                        up vote
                        0
                        down vote













                        What you are saying is not correct, recall indeed that by definiton we have



                        $$sum_{k=0}^infty a_k = lim _{nto infty} S_n= lim _{nto infty} sum_{k=0}^n a_k$$



                        and





                        • $sum_{k=0}^infty a_k$ is the (infinite) series


                        • $S_n= sum_{k=0}^n a_k$ is the partial sum


                        when the series converges, that is $$lim _{nto infty} S_n=Lin mathbb{R}$$ we can derive the necessary condition for convergence



                        $$a_n=S_n-S_{n-1} to L-L=0$$






                        share|cite|improve this answer

























                          up vote
                          0
                          down vote













                          What you are saying is not correct, recall indeed that by definiton we have



                          $$sum_{k=0}^infty a_k = lim _{nto infty} S_n= lim _{nto infty} sum_{k=0}^n a_k$$



                          and





                          • $sum_{k=0}^infty a_k$ is the (infinite) series


                          • $S_n= sum_{k=0}^n a_k$ is the partial sum


                          when the series converges, that is $$lim _{nto infty} S_n=Lin mathbb{R}$$ we can derive the necessary condition for convergence



                          $$a_n=S_n-S_{n-1} to L-L=0$$






                          share|cite|improve this answer























                            up vote
                            0
                            down vote










                            up vote
                            0
                            down vote









                            What you are saying is not correct, recall indeed that by definiton we have



                            $$sum_{k=0}^infty a_k = lim _{nto infty} S_n= lim _{nto infty} sum_{k=0}^n a_k$$



                            and





                            • $sum_{k=0}^infty a_k$ is the (infinite) series


                            • $S_n= sum_{k=0}^n a_k$ is the partial sum


                            when the series converges, that is $$lim _{nto infty} S_n=Lin mathbb{R}$$ we can derive the necessary condition for convergence



                            $$a_n=S_n-S_{n-1} to L-L=0$$






                            share|cite|improve this answer












                            What you are saying is not correct, recall indeed that by definiton we have



                            $$sum_{k=0}^infty a_k = lim _{nto infty} S_n= lim _{nto infty} sum_{k=0}^n a_k$$



                            and





                            • $sum_{k=0}^infty a_k$ is the (infinite) series


                            • $S_n= sum_{k=0}^n a_k$ is the partial sum


                            when the series converges, that is $$lim _{nto infty} S_n=Lin mathbb{R}$$ we can derive the necessary condition for convergence



                            $$a_n=S_n-S_{n-1} to L-L=0$$







                            share|cite|improve this answer












                            share|cite|improve this answer



                            share|cite|improve this answer










                            answered Nov 22 at 18:18









                            gimusi

                            92.7k94495




                            92.7k94495






















                                up vote
                                0
                                down vote













                                By definition, the sum of an infinite series is the limit of its partial sums:



                                $$sum_{i = 0}^{
                                infty}a_i := lim_{N to infty}sum_{i = 0}^Na_i$$



                                Now, in order for this limit to converge to a real number $L$, it would certainly have to be that the distance between each partial sum and the next gets arbitrarily small - after all, that's a necessary condition for any limit to converge.



                                $$sum_{i = 0}^{N + 1}a_i - sum_{i = 0}^Na_i = a_{N + 1}$$



                                So the values of $a_N$ must go to zero. That means that it is not correct to say that the limit of the partial sums must be zero, but it is correct to say that the limit of the terms of the series must be zero.



                                There is a point of confusion here, though. You keep referring to the limit of a series. That's not typical terminology, because it isn't clear whether you mean the limit of the terms (because you're not mentioning adding things up) or the limit of the partial sums (because you're calling it a "series" and you usually sum series). Generally, we say limit of a sequence and sum of a series. So, to put things as precisely as I can:



                                Let $a_0, a_1, ldots, a_i, ldots$ be an infinite sequence. The limit of the sequence is $lim_{i to infty}a_i$. The sum of the series is $sum_{i = 0}^{infty}a_i = lim_{N to infty}sum_{i = 0}^Na_i$. If the sum of the series converges to a real number, then the limit of the sequence must be zero. Because the sum of the series may be nonzero, the limit of the sequence is not necessarily the same as the sum of the series.






                                share|cite|improve this answer

























                                  up vote
                                  0
                                  down vote













                                  By definition, the sum of an infinite series is the limit of its partial sums:



                                  $$sum_{i = 0}^{
                                  infty}a_i := lim_{N to infty}sum_{i = 0}^Na_i$$



                                  Now, in order for this limit to converge to a real number $L$, it would certainly have to be that the distance between each partial sum and the next gets arbitrarily small - after all, that's a necessary condition for any limit to converge.



                                  $$sum_{i = 0}^{N + 1}a_i - sum_{i = 0}^Na_i = a_{N + 1}$$



                                  So the values of $a_N$ must go to zero. That means that it is not correct to say that the limit of the partial sums must be zero, but it is correct to say that the limit of the terms of the series must be zero.



                                  There is a point of confusion here, though. You keep referring to the limit of a series. That's not typical terminology, because it isn't clear whether you mean the limit of the terms (because you're not mentioning adding things up) or the limit of the partial sums (because you're calling it a "series" and you usually sum series). Generally, we say limit of a sequence and sum of a series. So, to put things as precisely as I can:



                                  Let $a_0, a_1, ldots, a_i, ldots$ be an infinite sequence. The limit of the sequence is $lim_{i to infty}a_i$. The sum of the series is $sum_{i = 0}^{infty}a_i = lim_{N to infty}sum_{i = 0}^Na_i$. If the sum of the series converges to a real number, then the limit of the sequence must be zero. Because the sum of the series may be nonzero, the limit of the sequence is not necessarily the same as the sum of the series.






                                  share|cite|improve this answer























                                    up vote
                                    0
                                    down vote










                                    up vote
                                    0
                                    down vote









                                    By definition, the sum of an infinite series is the limit of its partial sums:



                                    $$sum_{i = 0}^{
                                    infty}a_i := lim_{N to infty}sum_{i = 0}^Na_i$$



                                    Now, in order for this limit to converge to a real number $L$, it would certainly have to be that the distance between each partial sum and the next gets arbitrarily small - after all, that's a necessary condition for any limit to converge.



                                    $$sum_{i = 0}^{N + 1}a_i - sum_{i = 0}^Na_i = a_{N + 1}$$



                                    So the values of $a_N$ must go to zero. That means that it is not correct to say that the limit of the partial sums must be zero, but it is correct to say that the limit of the terms of the series must be zero.



                                    There is a point of confusion here, though. You keep referring to the limit of a series. That's not typical terminology, because it isn't clear whether you mean the limit of the terms (because you're not mentioning adding things up) or the limit of the partial sums (because you're calling it a "series" and you usually sum series). Generally, we say limit of a sequence and sum of a series. So, to put things as precisely as I can:



                                    Let $a_0, a_1, ldots, a_i, ldots$ be an infinite sequence. The limit of the sequence is $lim_{i to infty}a_i$. The sum of the series is $sum_{i = 0}^{infty}a_i = lim_{N to infty}sum_{i = 0}^Na_i$. If the sum of the series converges to a real number, then the limit of the sequence must be zero. Because the sum of the series may be nonzero, the limit of the sequence is not necessarily the same as the sum of the series.






                                    share|cite|improve this answer












                                    By definition, the sum of an infinite series is the limit of its partial sums:



                                    $$sum_{i = 0}^{
                                    infty}a_i := lim_{N to infty}sum_{i = 0}^Na_i$$



                                    Now, in order for this limit to converge to a real number $L$, it would certainly have to be that the distance between each partial sum and the next gets arbitrarily small - after all, that's a necessary condition for any limit to converge.



                                    $$sum_{i = 0}^{N + 1}a_i - sum_{i = 0}^Na_i = a_{N + 1}$$



                                    So the values of $a_N$ must go to zero. That means that it is not correct to say that the limit of the partial sums must be zero, but it is correct to say that the limit of the terms of the series must be zero.



                                    There is a point of confusion here, though. You keep referring to the limit of a series. That's not typical terminology, because it isn't clear whether you mean the limit of the terms (because you're not mentioning adding things up) or the limit of the partial sums (because you're calling it a "series" and you usually sum series). Generally, we say limit of a sequence and sum of a series. So, to put things as precisely as I can:



                                    Let $a_0, a_1, ldots, a_i, ldots$ be an infinite sequence. The limit of the sequence is $lim_{i to infty}a_i$. The sum of the series is $sum_{i = 0}^{infty}a_i = lim_{N to infty}sum_{i = 0}^Na_i$. If the sum of the series converges to a real number, then the limit of the sequence must be zero. Because the sum of the series may be nonzero, the limit of the sequence is not necessarily the same as the sum of the series.







                                    share|cite|improve this answer












                                    share|cite|improve this answer



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                                    answered Nov 22 at 18:20









                                    Reese

                                    15k11136




                                    15k11136






























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