Need a java version of this mathematica code
up vote
-1
down vote
favorite
[https://www.wolframcloud.com/objects/paralesely/Published/a.nb][1]
I am researcher and I find difficulties in studying my research because of my reference paper is written in Mathematica ,Wolfarm language .
Can somebody help me in translating this code in order for me to trace well.
Thanks for your time.
[https://www.wolframcloud.com/objects/paralesely/Published/a.nb][1]
I am researcher and I find difficulties in studying my research because of my reference paper is written in Mathematica ,Wolfarm language .
Can somebody help me in translating this code in order for me to trace well.
Thanks for your time.
Timing[n=8;
board=Table[0,{i,n},{j,n}];
solutions={};
tt=0;tt1={};
For[i=1,i<=n,i++,
For[j=1,j<=n,j++,
If[board[[i,j]]==0,
board[[i,j]]=Q;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]+1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]+1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]+1;k++;l++];
( *rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]+1;k++;l--];
(*====================================*)
];
];
If[i==n,
solution={};
Table[If[MemberQ[board[[row]],Q],posQ=Position[board[[row]],Q][[1]]
[[1]];AppendTo[solution,posQ];];,{row,n}]
;
If[Length@solution==n,AppendTo[solutions,solution]];
];
(*This part stops calculation after queen moved from last column to first
column in the first row*)
If[tt==0,If[board[[1,n]]==Q,tt++]];
If[tt==1&&board[[1,1]]==Q,Break];
(*Backtracking Loop=======================*)
If[i==n,
test=True;
While[test,
If[MemberQ[board[[i]],Q],
pos=Position[board[[i]],Q][[1]][[1]];
board[[i,pos]]=0;
j=pos;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]-1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]-1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]-1;k++;l++];
(*rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]-1;k++;l--];
(*====================================*)
Table[ If[board[[i,iter]]==0,
board[[i,iter]]=Q;
j=iter;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]+1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]+1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]+1;k++;l++];
(*rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]+1;k++;l--];
(*====================================*)
test=False;
];,{iter,pos+1,n}];
i--; If[i==0,Break];
,i--;If[i==0,Break];
];If[i==0,Break];
];
];
];
java wolfram-mathematica
New contributor
add a comment |
up vote
-1
down vote
favorite
[https://www.wolframcloud.com/objects/paralesely/Published/a.nb][1]
I am researcher and I find difficulties in studying my research because of my reference paper is written in Mathematica ,Wolfarm language .
Can somebody help me in translating this code in order for me to trace well.
Thanks for your time.
[https://www.wolframcloud.com/objects/paralesely/Published/a.nb][1]
I am researcher and I find difficulties in studying my research because of my reference paper is written in Mathematica ,Wolfarm language .
Can somebody help me in translating this code in order for me to trace well.
Thanks for your time.
Timing[n=8;
board=Table[0,{i,n},{j,n}];
solutions={};
tt=0;tt1={};
For[i=1,i<=n,i++,
For[j=1,j<=n,j++,
If[board[[i,j]]==0,
board[[i,j]]=Q;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]+1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]+1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]+1;k++;l++];
( *rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]+1;k++;l--];
(*====================================*)
];
];
If[i==n,
solution={};
Table[If[MemberQ[board[[row]],Q],posQ=Position[board[[row]],Q][[1]]
[[1]];AppendTo[solution,posQ];];,{row,n}]
;
If[Length@solution==n,AppendTo[solutions,solution]];
];
(*This part stops calculation after queen moved from last column to first
column in the first row*)
If[tt==0,If[board[[1,n]]==Q,tt++]];
If[tt==1&&board[[1,1]]==Q,Break];
(*Backtracking Loop=======================*)
If[i==n,
test=True;
While[test,
If[MemberQ[board[[i]],Q],
pos=Position[board[[i]],Q][[1]][[1]];
board[[i,pos]]=0;
j=pos;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]-1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]-1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]-1;k++;l++];
(*rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]-1;k++;l--];
(*====================================*)
Table[ If[board[[i,iter]]==0,
board[[i,iter]]=Q;
j=iter;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]+1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]+1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]+1;k++;l++];
(*rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]+1;k++;l--];
(*====================================*)
test=False;
];,{iter,pos+1,n}];
i--; If[i==0,Break];
,i--;If[i==0,Break];
];If[i==0,Break];
];
];
];
java wolfram-mathematica
New contributor
Please read the on-topic and How to Ask pages before posting on a Stack Exchange site.
– janos
22 secs ago
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
[https://www.wolframcloud.com/objects/paralesely/Published/a.nb][1]
I am researcher and I find difficulties in studying my research because of my reference paper is written in Mathematica ,Wolfarm language .
Can somebody help me in translating this code in order for me to trace well.
Thanks for your time.
[https://www.wolframcloud.com/objects/paralesely/Published/a.nb][1]
I am researcher and I find difficulties in studying my research because of my reference paper is written in Mathematica ,Wolfarm language .
Can somebody help me in translating this code in order for me to trace well.
Thanks for your time.
Timing[n=8;
board=Table[0,{i,n},{j,n}];
solutions={};
tt=0;tt1={};
For[i=1,i<=n,i++,
For[j=1,j<=n,j++,
If[board[[i,j]]==0,
board[[i,j]]=Q;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]+1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]+1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]+1;k++;l++];
( *rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]+1;k++;l--];
(*====================================*)
];
];
If[i==n,
solution={};
Table[If[MemberQ[board[[row]],Q],posQ=Position[board[[row]],Q][[1]]
[[1]];AppendTo[solution,posQ];];,{row,n}]
;
If[Length@solution==n,AppendTo[solutions,solution]];
];
(*This part stops calculation after queen moved from last column to first
column in the first row*)
If[tt==0,If[board[[1,n]]==Q,tt++]];
If[tt==1&&board[[1,1]]==Q,Break];
(*Backtracking Loop=======================*)
If[i==n,
test=True;
While[test,
If[MemberQ[board[[i]],Q],
pos=Position[board[[i]],Q][[1]][[1]];
board[[i,pos]]=0;
j=pos;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]-1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]-1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]-1;k++;l++];
(*rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]-1;k++;l--];
(*====================================*)
Table[ If[board[[i,iter]]==0,
board[[i,iter]]=Q;
j=iter;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]+1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]+1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]+1;k++;l++];
(*rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]+1;k++;l--];
(*====================================*)
test=False;
];,{iter,pos+1,n}];
i--; If[i==0,Break];
,i--;If[i==0,Break];
];If[i==0,Break];
];
];
];
java wolfram-mathematica
New contributor
[https://www.wolframcloud.com/objects/paralesely/Published/a.nb][1]
I am researcher and I find difficulties in studying my research because of my reference paper is written in Mathematica ,Wolfarm language .
Can somebody help me in translating this code in order for me to trace well.
Thanks for your time.
[https://www.wolframcloud.com/objects/paralesely/Published/a.nb][1]
I am researcher and I find difficulties in studying my research because of my reference paper is written in Mathematica ,Wolfarm language .
Can somebody help me in translating this code in order for me to trace well.
Thanks for your time.
Timing[n=8;
board=Table[0,{i,n},{j,n}];
solutions={};
tt=0;tt1={};
For[i=1,i<=n,i++,
For[j=1,j<=n,j++,
If[board[[i,j]]==0,
board[[i,j]]=Q;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]+1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]+1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]+1;k++;l++];
( *rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]+1;k++;l--];
(*====================================*)
];
];
If[i==n,
solution={};
Table[If[MemberQ[board[[row]],Q],posQ=Position[board[[row]],Q][[1]]
[[1]];AppendTo[solution,posQ];];,{row,n}]
;
If[Length@solution==n,AppendTo[solutions,solution]];
];
(*This part stops calculation after queen moved from last column to first
column in the first row*)
If[tt==0,If[board[[1,n]]==Q,tt++]];
If[tt==1&&board[[1,1]]==Q,Break];
(*Backtracking Loop=======================*)
If[i==n,
test=True;
While[test,
If[MemberQ[board[[i]],Q],
pos=Position[board[[i]],Q][[1]][[1]];
board[[i,pos]]=0;
j=pos;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]-1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]-1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]-1;k++;l++];
(*rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]-1;k++;l--];
(*====================================*)
Table[ If[board[[i,iter]]==0,
board[[i,iter]]=Q;
j=iter;
(*Row*)Table[If[k!=j,board[[i,k]]=board[[i,k]]+1],{k,1,n}];
(*Column*)Table[If[k!=i ,board[[k,j]]=board[[k,j]]+1],{k,1,n}];
(*lDiagonalLower======================*)
k=i+1;
l=j+1;
While[k!=n+1&&l!=n+1,board[[k,l]]=board[[k,l]]+1;k++;l++];
(*rDiagonalLower======================*)
k=i+1;
l=j-1;
While[k<= n&&l>= 1,board[[k,l]]=board[[k,l]]+1;k++;l--];
(*====================================*)
test=False;
];,{iter,pos+1,n}];
i--; If[i==0,Break];
,i--;If[i==0,Break];
];If[i==0,Break];
];
];
];
java wolfram-mathematica
java wolfram-mathematica
New contributor
New contributor
New contributor
asked 12 mins ago
Thuriya Thwin
1
1
New contributor
New contributor
Please read the on-topic and How to Ask pages before posting on a Stack Exchange site.
– janos
22 secs ago
add a comment |
Please read the on-topic and How to Ask pages before posting on a Stack Exchange site.
– janos
22 secs ago
Please read the on-topic and How to Ask pages before posting on a Stack Exchange site.
– janos
22 secs ago
Please read the on-topic and How to Ask pages before posting on a Stack Exchange site.
– janos
22 secs ago
add a comment |
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Thuriya Thwin is a new contributor. Be nice, and check out our Code of Conduct.
Thuriya Thwin is a new contributor. Be nice, and check out our Code of Conduct.
Thuriya Thwin is a new contributor. Be nice, and check out our Code of Conduct.
Thuriya Thwin is a new contributor. Be nice, and check out our Code of Conduct.
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