Physics Conservation of Energy Problem
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In the figure below, a block is released from rest at height $d = 24 ; text{cm}$ and slides down a frictionless ramp and onto a first plateau, which has length $d$ and where the coefficient of kinetic friction is $0.50$. If the block is still moving, it then slides down a second frictionless ramp through a height of $d/2$ and onto a lower plateau, which has length $d/2$ and where the coefficient of kinetic friction is again $0.50$. If the block is still moving, it then slides up a frictionless ramp until it (momentarily) stops.
(b) Give the stopping point of the block, either as a distance along the first or second plateau (this would be a final stop) or as a height on the ramp at the right (this would be a momentary stop because the block will slide back down the ramp).
I cannot figure this problem out at all, please help!
physics
edited Apr 24 '14 at 6:25
Mark Fantini
4,83041935
asked Oct 11 '13 at 4:31
user72195
589722
add a comment |
up vote
0
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In the figure below, a block is released from rest at height $d = 24 ; text{cm}$ and slides down a frictionless ramp and onto a first plateau, which has length $d$ and where the coefficient of kinetic friction is $0.50$. If the block is still moving, it then slides down a second frictionless ramp through a height of $d/2$ and onto a lower plateau, which has length $d/2$ and where the coefficient of kinetic friction is again $0.50$. If the block is still moving, it then slides up a frictionless ramp until it (momentarily) stops.
(b) Give the stopping point of the block, either as a distance along the first or second plateau (this would be a final stop) or as a height on the ramp at the right (this would be a momentary stop because the block will slide back down the ramp).
I cannot figure this problem out at all, please help!
physics
edited Apr 24 '14 at 6:25
Mark Fantini
4,83041935
asked Oct 11 '13 at 4:31
user72195
589722
See how far you can get with my advice below. If you get stuck again just post your progress on here and we can work from there.
– Spencer
Oct 11 '13 at 4:40
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
In the figure below, a block is released from rest at height $d = 24 ; text{cm}$ and slides down a frictionless ramp and onto a first plateau, which has length $d$ and where the coefficient of kinetic friction is $0.50$. If the block is still moving, it then slides down a second frictionless ramp through a height of $d/2$ and onto a lower plateau, which has length $d/2$ and where the coefficient of kinetic friction is again $0.50$. If the block is still moving, it then slides up a frictionless ramp until it (momentarily) stops.
(b) Give the stopping point of the block, either as a distance along the first or second plateau (this would be a final stop) or as a height on the ramp at the right (this would be a momentary stop because the block will slide back down the ramp).
I cannot figure this problem out at all, please help!
physics
edited Apr 24 '14 at 6:25
Mark Fantini
4,83041935
asked Oct 11 '13 at 4:31
user72195
589722
In the figure below, a block is released from rest at height $d = 24 ; text{cm}$ and slides down a frictionless ramp and onto a first plateau, which has length $d$ and where the coefficient of kinetic friction is $0.50$. If the block is still moving, it then slides down a second frictionless ramp through a height of $d/2$ and onto a lower plateau, which has length $d/2$ and where the coefficient of kinetic friction is again $0.50$. If the block is still moving, it then slides up a frictionless ramp until it (momentarily) stops.
(b) Give the stopping point of the block, either as a distance along the first or second plateau (this would be a final stop) or as a height on the ramp at the right (this would be a momentary stop because the block will slide back down the ramp).
I cannot figure this problem out at all, please help!
physics
physics
edited Apr 24 '14 at 6:25
Mark Fantini
4,83041935
asked Oct 11 '13 at 4:31
user72195
589722
edited Apr 24 '14 at 6:25
Mark Fantini
4,83041935
asked Oct 11 '13 at 4:31
user72195
589722
edited Apr 24 '14 at 6:25
Mark Fantini
4,83041935
edited Apr 24 '14 at 6:25
Mark Fantini
4,83041935
edited Apr 24 '14 at 6:25
Mark Fantini
4,83041935
4,83041935
asked Oct 11 '13 at 4:31
user72195
589722
asked Oct 11 '13 at 4:31
user72195
589722
asked Oct 11 '13 at 4:31
user72195
589722
589722
See how far you can get with my advice below. If you get stuck again just post your progress on here and we can work from there.
– Spencer
Oct 11 '13 at 4:40
add a comment |
See how far you can get with my advice below. If you get stuck again just post your progress on here and we can work from there.
– Spencer
Oct 11 '13 at 4:40
See how far you can get with my advice below. If you get stuck again just post your progress on here and we can work from there.
– Spencer
Oct 11 '13 at 4:40
See how far you can get with my advice below. If you get stuck again just post your progress on here and we can work from there.
– Spencer
Oct 11 '13 at 4:40
add a comment |
1 Answer
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Based on the title of your question I assume you know that energy conservation is going to play a role.
You've only described a situation and not an actual question so I don't know what you are trying to compute. But here is some general advice.
Look at the initial state of the block. What are its potential and kinetic energies? This should give you an initial value for the energy.
At each stage its hits a horizontal surface with friction. This means energy isn't conserved right? How does the friction change the energy. How do forces in general change energy? Hint: Read up on the work energy theorem.
This should be enough to get you started.
This might help: $Delta E = $Work Done$ = F cdot d$
answered Oct 11 '13 at 4:37
Spencer
8,44012055
sorry! i forgot to add the question, I just edited it in though
– user72195
Oct 11 '13 at 4:39
Potential energy = mgh and its kinetic energy would be 0 so the initial value would be mgh correct? I dont know what else to do
– user72195
Oct 11 '13 at 4:50
That is correct the initial energy is mgh. Now ask yourself how much energy will be lost when it passes over the first friction pad. You know the force of friction and you know how far it travels.
– Spencer
Oct 11 '13 at 5:22
add a comment |
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1 Answer
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Based on the title of your question I assume you know that energy conservation is going to play a role.
You've only described a situation and not an actual question so I don't know what you are trying to compute. But here is some general advice.
Look at the initial state of the block. What are its potential and kinetic energies? This should give you an initial value for the energy.
At each stage its hits a horizontal surface with friction. This means energy isn't conserved right? How does the friction change the energy. How do forces in general change energy? Hint: Read up on the work energy theorem.
This should be enough to get you started.
This might help: $Delta E = $Work Done$ = F cdot d$
answered Oct 11 '13 at 4:37
Spencer
8,44012055
sorry! i forgot to add the question, I just edited it in though
– user72195
Oct 11 '13 at 4:39
Potential energy = mgh and its kinetic energy would be 0 so the initial value would be mgh correct? I dont know what else to do
– user72195
Oct 11 '13 at 4:50
That is correct the initial energy is mgh. Now ask yourself how much energy will be lost when it passes over the first friction pad. You know the force of friction and you know how far it travels.
– Spencer
Oct 11 '13 at 5:22
add a comment |
up vote
1
down vote
Based on the title of your question I assume you know that energy conservation is going to play a role.
You've only described a situation and not an actual question so I don't know what you are trying to compute. But here is some general advice.
Look at the initial state of the block. What are its potential and kinetic energies? This should give you an initial value for the energy.
At each stage its hits a horizontal surface with friction. This means energy isn't conserved right? How does the friction change the energy. How do forces in general change energy? Hint: Read up on the work energy theorem.
This should be enough to get you started.
This might help: $Delta E = $Work Done$ = F cdot d$
answered Oct 11 '13 at 4:37
Spencer
8,44012055
sorry! i forgot to add the question, I just edited it in though
– user72195
Oct 11 '13 at 4:39
Potential energy = mgh and its kinetic energy would be 0 so the initial value would be mgh correct? I dont know what else to do
– user72195
Oct 11 '13 at 4:50
That is correct the initial energy is mgh. Now ask yourself how much energy will be lost when it passes over the first friction pad. You know the force of friction and you know how far it travels.
– Spencer
Oct 11 '13 at 5:22
add a comment |
up vote
1
down vote
up vote
1
down vote
Based on the title of your question I assume you know that energy conservation is going to play a role.
You've only described a situation and not an actual question so I don't know what you are trying to compute. But here is some general advice.
Look at the initial state of the block. What are its potential and kinetic energies? This should give you an initial value for the energy.
At each stage its hits a horizontal surface with friction. This means energy isn't conserved right? How does the friction change the energy. How do forces in general change energy? Hint: Read up on the work energy theorem.
This should be enough to get you started.
This might help: $Delta E = $Work Done$ = F cdot d$
answered Oct 11 '13 at 4:37
Spencer
8,44012055
Based on the title of your question I assume you know that energy conservation is going to play a role.
You've only described a situation and not an actual question so I don't know what you are trying to compute. But here is some general advice.
Look at the initial state of the block. What are its potential and kinetic energies? This should give you an initial value for the energy.
At each stage its hits a horizontal surface with friction. This means energy isn't conserved right? How does the friction change the energy. How do forces in general change energy? Hint: Read up on the work energy theorem.
This should be enough to get you started.
This might help: $Delta E = $Work Done$ = F cdot d$
answered Oct 11 '13 at 4:37
Spencer
8,44012055
edited Oct 11 '13 at 5:23
answered Oct 11 '13 at 4:37
Spencer
8,44012055
answered Oct 11 '13 at 4:37
Spencer
8,44012055
answered Oct 11 '13 at 4:37
Spencer
8,44012055
8,44012055
sorry! i forgot to add the question, I just edited it in though
– user72195
Oct 11 '13 at 4:39
Potential energy = mgh and its kinetic energy would be 0 so the initial value would be mgh correct? I dont know what else to do
– user72195
Oct 11 '13 at 4:50
That is correct the initial energy is mgh. Now ask yourself how much energy will be lost when it passes over the first friction pad. You know the force of friction and you know how far it travels.
– Spencer
Oct 11 '13 at 5:22
add a comment |
sorry! i forgot to add the question, I just edited it in though
– user72195
Oct 11 '13 at 4:39
Potential energy = mgh and its kinetic energy would be 0 so the initial value would be mgh correct? I dont know what else to do
– user72195
Oct 11 '13 at 4:50
That is correct the initial energy is mgh. Now ask yourself how much energy will be lost when it passes over the first friction pad. You know the force of friction and you know how far it travels.
– Spencer
Oct 11 '13 at 5:22
sorry! i forgot to add the question, I just edited it in though
– user72195
Oct 11 '13 at 4:39
sorry! i forgot to add the question, I just edited it in though
– user72195
Oct 11 '13 at 4:39
Potential energy = mgh and its kinetic energy would be 0 so the initial value would be mgh correct? I dont know what else to do
– user72195
Oct 11 '13 at 4:50
Potential energy = mgh and its kinetic energy would be 0 so the initial value would be mgh correct? I dont know what else to do
– user72195
Oct 11 '13 at 4:50
That is correct the initial energy is mgh. Now ask yourself how much energy will be lost when it passes over the first friction pad. You know the force of friction and you know how far it travels.
– Spencer
Oct 11 '13 at 5:22
That is correct the initial energy is mgh. Now ask yourself how much energy will be lost when it passes over the first friction pad. You know the force of friction and you know how far it travels.
– Spencer
Oct 11 '13 at 5:22
add a comment |
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See how far you can get with my advice below. If you get stuck again just post your progress on here and we can work from there.
– Spencer
Oct 11 '13 at 4:40