Iteration of a Matrix











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I want to update "matrix1" 100 times. "matrix3" will be new "matrix1" and it will iterate 100 times. Should I use a loop or function? First iteration is:



matrix1 = ( {

    {1, 2, 3},

    {4, 5, 6},

    {7, 8, 9}

   } );

matrix2 = matrix1*2 - 1;

matrix3 = matrix2 + 5;

matrix3


Output (First iteration):



{{6, 8, 10}, {12, 14, 16}, {18, 20, 22}}


matrix3 will be new matrix1



matrix1 = ( {

    {6, 8, 10},

    {12, 14, 16},

    {18, 20, 22}

   } );

matrix2 = matrix1*2 - 1;

matrix3 = matrix2 + 5;

matrix3


Output (Second iteration):



{{16, 20, 24}, {28, 32, 36}, {40, 44, 48}}


And, It will repeat 100 times.






matrix education iteration







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    up vote
    2
    down vote

    favorite












    I want to update "matrix1" 100 times. "matrix3" will be new "matrix1" and it will iterate 100 times. Should I use a loop or function? First iteration is:



    matrix1 = ( {
    
    {1, 2, 3},
    
    {4, 5, 6},
    
    {7, 8, 9}
    
   } );
    
matrix2 = matrix1*2 - 1;
    
matrix3 = matrix2 + 5;
    
matrix3


    Output (First iteration):



    {{6, 8, 10}, {12, 14, 16}, {18, 20, 22}}


    matrix3 will be new matrix1



    matrix1 = ( {
    
    {6, 8, 10},
    
    {12, 14, 16},
    
    {18, 20, 22}
    
   } );
    
matrix2 = matrix1*2 - 1;
    
matrix3 = matrix2 + 5;
    
matrix3


    Output (Second iteration):



    {{16, 20, 24}, {28, 32, 36}, {40, 44, 48}}


    And, It will repeat 100 times.






    matrix education iteration







    share|improve this question
























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I want to update "matrix1" 100 times. "matrix3" will be new "matrix1" and it will iterate 100 times. Should I use a loop or function? First iteration is:



      matrix1 = ( {
      
    {1, 2, 3},
      
    {4, 5, 6},
      
    {7, 8, 9}
      
   } );
      
matrix2 = matrix1*2 - 1;
      
matrix3 = matrix2 + 5;
      
matrix3


      Output (First iteration):



      {{6, 8, 10}, {12, 14, 16}, {18, 20, 22}}


      matrix3 will be new matrix1



      matrix1 = ( {
      
    {6, 8, 10},
      
    {12, 14, 16},
      
    {18, 20, 22}
      
   } );
      
matrix2 = matrix1*2 - 1;
      
matrix3 = matrix2 + 5;
      
matrix3


      Output (Second iteration):



      {{16, 20, 24}, {28, 32, 36}, {40, 44, 48}}


      And, It will repeat 100 times.






      matrix education iteration







      share|improve this question













      I want to update "matrix1" 100 times. "matrix3" will be new "matrix1" and it will iterate 100 times. Should I use a loop or function? First iteration is:



      matrix1 = ( {
      
    {1, 2, 3},
      
    {4, 5, 6},
      
    {7, 8, 9}
      
   } );
      
matrix2 = matrix1*2 - 1;
      
matrix3 = matrix2 + 5;
      
matrix3


      Output (First iteration):



      {{6, 8, 10}, {12, 14, 16}, {18, 20, 22}}


      matrix3 will be new matrix1



      matrix1 = ( {
      
    {6, 8, 10},
      
    {12, 14, 16},
      
    {18, 20, 22}
      
   } );
      
matrix2 = matrix1*2 - 1;
      
matrix3 = matrix2 + 5;
      
matrix3


      Output (Second iteration):



      {{16, 20, 24}, {28, 32, 36}, {40, 44, 48}}


      And, It will repeat 100 times.






      matrix education iteration




      matrix education iteration






      share|improve this question













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      share|improve this question










      asked 1 hour ago









      ithilquessirr

      594




      594






















          2 Answers
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          up vote
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          down vote



          accepted










          NestList[x [Function] 2 x + 4, {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}, 100]





          share|improve this answer




























            up vote
            1
            down vote













            Just for illustration and learning reasons, three examples with Fold, Do and Table. Define



            matrix1 := {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}


            Then



            Table[matrix1 = 2*matrix1 + 4, {100}]


            prints all intermediate matrices



            Do[matrix1 = 2*matrix1 + 4, {2}]
            
matrix1


            and



            Fold[f[#1] &, matrix1, Range[100]]


            print the last result.






            share|improve this answer





















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              2 Answers
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              active

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              2 Answers
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              active

              oldest

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              active

              oldest

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              active

              oldest

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              up vote
              5
              down vote



              accepted










              NestList[x [Function] 2 x + 4, {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}, 100]





              share|improve this answer

























                up vote
                5
                down vote



                accepted










                NestList[x [Function] 2 x + 4, {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}, 100]





                share|improve this answer























                  up vote
                  5
                  down vote



                  accepted







                  up vote
                  5
                  down vote



                  accepted






                  NestList[x [Function] 2 x + 4, {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}, 100]





                  share|improve this answer












                  NestList[x [Function] 2 x + 4, {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}, 100]






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 1 hour ago









                  Henrik Schumacher

                  47.6k466134




                  47.6k466134






















                      up vote
                      1
                      down vote













                      Just for illustration and learning reasons, three examples with Fold, Do and Table. Define



                      matrix1 := {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}


                      Then



                      Table[matrix1 = 2*matrix1 + 4, {100}]


                      prints all intermediate matrices



                      Do[matrix1 = 2*matrix1 + 4, {2}]
                      
matrix1


                      and



                      Fold[f[#1] &, matrix1, Range[100]]


                      print the last result.






                      share|improve this answer

























                        up vote
                        1
                        down vote













                        Just for illustration and learning reasons, three examples with Fold, Do and Table. Define



                        matrix1 := {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}


                        Then



                        Table[matrix1 = 2*matrix1 + 4, {100}]


                        prints all intermediate matrices



                        Do[matrix1 = 2*matrix1 + 4, {2}]
                        
matrix1


                        and



                        Fold[f[#1] &, matrix1, Range[100]]


                        print the last result.






                        share|improve this answer























                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          Just for illustration and learning reasons, three examples with Fold, Do and Table. Define



                          matrix1 := {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}


                          Then



                          Table[matrix1 = 2*matrix1 + 4, {100}]


                          prints all intermediate matrices



                          Do[matrix1 = 2*matrix1 + 4, {2}]
                          
matrix1


                          and



                          Fold[f[#1] &, matrix1, Range[100]]


                          print the last result.






                          share|improve this answer












                          Just for illustration and learning reasons, three examples with Fold, Do and Table. Define



                          matrix1 := {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}


                          Then



                          Table[matrix1 = 2*matrix1 + 4, {100}]


                          prints all intermediate matrices



                          Do[matrix1 = 2*matrix1 + 4, {2}]
                          
matrix1


                          and



                          Fold[f[#1] &, matrix1, Range[100]]


                          print the last result.







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 1 hour ago









                          Titus

                          520317




                          520317






























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