Swift permutations of the digits of an Integer
up vote
2
down vote
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I want to return all of the permutations of an integer in Swift.
var outputArray = [[Int]]()
func perms ( _ input: [Int], _ output: [Int]) {
if input.count == 0 {
outputArray.append( [ Int( output.map{ String($0) }.joined() )! ] )
}
else {
for i in 0..<input.count {
let current = [input[i]]
let before = Array( input [0..<i] )
let after = Array( input [(i + 1) ..< input.count] )
perms(before + after, current + output)
}
}
}
func permsOfInteger(_ input: Int) -> [[Int]] {
var inp = input
var inpArray = [Int]()
while inp > 0 {
inpArray.append(inp % 10)
inp = inp / 10
}
perms(inpArray, )
return (outputArray)
}
( permsOfInteger(5432) )
I don't want to switch the algorithm (I'm aware of Heap's algorithm) but rather improve my implementation here. Any advice?
swift
edited 3 mins ago
janos
96.8k12124350
asked 6 hours ago
stevenpcurtis
1111
New contributor
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
2
down vote
favorite
I want to return all of the permutations of an integer in Swift.
var outputArray = [[Int]]()
func perms ( _ input: [Int], _ output: [Int]) {
if input.count == 0 {
outputArray.append( [ Int( output.map{ String($0) }.joined() )! ] )
}
else {
for i in 0..<input.count {
let current = [input[i]]
let before = Array( input [0..<i] )
let after = Array( input [(i + 1) ..< input.count] )
perms(before + after, current + output)
}
}
}
func permsOfInteger(_ input: Int) -> [[Int]] {
var inp = input
var inpArray = [Int]()
while inp > 0 {
inpArray.append(inp % 10)
inp = inp / 10
}
perms(inpArray, )
return (outputArray)
}
( permsOfInteger(5432) )
I don't want to switch the algorithm (I'm aware of Heap's algorithm) but rather improve my implementation here. Any advice?
swift
edited 3 mins ago
janos
96.8k12124350
asked 6 hours ago
stevenpcurtis
1111
New contributor
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Just a quick clarification - can you elaborate on what it means to permute an integer? Do you mean generate all the permutations of the numerals that make up the number? Like the number 123 would generate "123", "132", "213", "231", "312", "321"?
– user1118321
4 hours ago
Exactly. That is correct.
– stevenpcurtis
4 hours ago
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I want to return all of the permutations of an integer in Swift.
var outputArray = [[Int]]()
func perms ( _ input: [Int], _ output: [Int]) {
if input.count == 0 {
outputArray.append( [ Int( output.map{ String($0) }.joined() )! ] )
}
else {
for i in 0..<input.count {
let current = [input[i]]
let before = Array( input [0..<i] )
let after = Array( input [(i + 1) ..< input.count] )
perms(before + after, current + output)
}
}
}
func permsOfInteger(_ input: Int) -> [[Int]] {
var inp = input
var inpArray = [Int]()
while inp > 0 {
inpArray.append(inp % 10)
inp = inp / 10
}
perms(inpArray, )
return (outputArray)
}
( permsOfInteger(5432) )
I don't want to switch the algorithm (I'm aware of Heap's algorithm) but rather improve my implementation here. Any advice?
swift
edited 3 mins ago
janos
96.8k12124350
asked 6 hours ago
stevenpcurtis
1111
New contributor
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I want to return all of the permutations of an integer in Swift.
var outputArray = [[Int]]()
func perms ( _ input: [Int], _ output: [Int]) {
if input.count == 0 {
outputArray.append( [ Int( output.map{ String($0) }.joined() )! ] )
}
else {
for i in 0..<input.count {
let current = [input[i]]
let before = Array( input [0..<i] )
let after = Array( input [(i + 1) ..< input.count] )
perms(before + after, current + output)
}
}
}
func permsOfInteger(_ input: Int) -> [[Int]] {
var inp = input
var inpArray = [Int]()
while inp > 0 {
inpArray.append(inp % 10)
inp = inp / 10
}
perms(inpArray, )
return (outputArray)
}
( permsOfInteger(5432) )
I don't want to switch the algorithm (I'm aware of Heap's algorithm) but rather improve my implementation here. Any advice?
swift
swift
edited 3 mins ago
janos
96.8k12124350
asked 6 hours ago
stevenpcurtis
1111
New contributor
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 mins ago
janos
96.8k12124350
asked 6 hours ago
stevenpcurtis
1111
New contributor
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 mins ago
janos
96.8k12124350
edited 3 mins ago
janos
96.8k12124350
edited 3 mins ago
janos
96.8k12124350
96.8k12124350
asked 6 hours ago
stevenpcurtis
1111
New contributor
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 6 hours ago
stevenpcurtis
1111
asked 6 hours ago
stevenpcurtis
1111
1111
New contributor
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
stevenpcurtis is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Just a quick clarification - can you elaborate on what it means to permute an integer? Do you mean generate all the permutations of the numerals that make up the number? Like the number 123 would generate "123", "132", "213", "231", "312", "321"?
– user1118321
4 hours ago
Exactly. That is correct.
– stevenpcurtis
4 hours ago
add a comment |
1
Just a quick clarification - can you elaborate on what it means to permute an integer? Do you mean generate all the permutations of the numerals that make up the number? Like the number 123 would generate "123", "132", "213", "231", "312", "321"?
– user1118321
4 hours ago
Exactly. That is correct.
– stevenpcurtis
4 hours ago
1
1
Just a quick clarification - can you elaborate on what it means to permute an integer? Do you mean generate all the permutations of the numerals that make up the number? Like the number 123 would generate "123", "132", "213", "231", "312", "321"?
– user1118321
4 hours ago
Just a quick clarification - can you elaborate on what it means to permute an integer? Do you mean generate all the permutations of the numerals that make up the number? Like the number 123 would generate "123", "132", "213", "231", "312", "321"?
– user1118321
4 hours ago
Exactly. That is correct.
– stevenpcurtis
4 hours ago
Exactly. That is correct.
– stevenpcurtis
4 hours ago
add a comment |
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1
Just a quick clarification - can you elaborate on what it means to permute an integer? Do you mean generate all the permutations of the numerals that make up the number? Like the number 123 would generate "123", "132", "213", "231", "312", "321"?
– user1118321
4 hours ago
Exactly. That is correct.
– stevenpcurtis
4 hours ago