Integral with Bessel function and sine.
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How to evaluate the integral with Bessel function:
$int_0^{2pi}J_1(xsintheta)sin^2theta dtheta$
Thank you in advance.
definite-integrals bessel-functions
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add a comment |
$begingroup$
How to evaluate the integral with Bessel function:
$int_0^{2pi}J_1(xsintheta)sin^2theta dtheta$
Thank you in advance.
definite-integrals bessel-functions
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It is $0$. $ $ $ $
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– Kemono Chen
Dec 5 '18 at 3:23
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Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
$endgroup$
– Nosrati
Dec 5 '18 at 4:18
add a comment |
$begingroup$
How to evaluate the integral with Bessel function:
$int_0^{2pi}J_1(xsintheta)sin^2theta dtheta$
Thank you in advance.
definite-integrals bessel-functions
$endgroup$
How to evaluate the integral with Bessel function:
$int_0^{2pi}J_1(xsintheta)sin^2theta dtheta$
Thank you in advance.
definite-integrals bessel-functions
definite-integrals bessel-functions
asked Dec 5 '18 at 2:49
ecookecook
109110
109110
$begingroup$
It is $0$. $ $ $ $
$endgroup$
– Kemono Chen
Dec 5 '18 at 3:23
$begingroup$
Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
$endgroup$
– Nosrati
Dec 5 '18 at 4:18
add a comment |
$begingroup$
It is $0$. $ $ $ $
$endgroup$
– Kemono Chen
Dec 5 '18 at 3:23
$begingroup$
Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
$endgroup$
– Nosrati
Dec 5 '18 at 4:18
$begingroup$
It is $0$. $ $ $ $
$endgroup$
– Kemono Chen
Dec 5 '18 at 3:23
$begingroup$
It is $0$. $ $ $ $
$endgroup$
– Kemono Chen
Dec 5 '18 at 3:23
$begingroup$
Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
$endgroup$
– Nosrati
Dec 5 '18 at 4:18
$begingroup$
Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
$endgroup$
– Nosrati
Dec 5 '18 at 4:18
add a comment |
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$begingroup$
It is $0$. $ $ $ $
$endgroup$
– Kemono Chen
Dec 5 '18 at 3:23
$begingroup$
Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
$endgroup$
– Nosrati
Dec 5 '18 at 4:18