Integral with Bessel function and sine.












0












$begingroup$


How to evaluate the integral with Bessel function:



$int_0^{2pi}J_1(xsintheta)sin^2theta dtheta$



Thank you in advance.










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$endgroup$












  • $begingroup$
    It is $0$. $ $ $ $
    $endgroup$
    – Kemono Chen
    Dec 5 '18 at 3:23












  • $begingroup$
    Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
    $endgroup$
    – Nosrati
    Dec 5 '18 at 4:18
















0












$begingroup$


How to evaluate the integral with Bessel function:



$int_0^{2pi}J_1(xsintheta)sin^2theta dtheta$



Thank you in advance.










share|cite|improve this question









$endgroup$












  • $begingroup$
    It is $0$. $ $ $ $
    $endgroup$
    – Kemono Chen
    Dec 5 '18 at 3:23












  • $begingroup$
    Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
    $endgroup$
    – Nosrati
    Dec 5 '18 at 4:18














0












0








0





$begingroup$


How to evaluate the integral with Bessel function:



$int_0^{2pi}J_1(xsintheta)sin^2theta dtheta$



Thank you in advance.










share|cite|improve this question









$endgroup$




How to evaluate the integral with Bessel function:



$int_0^{2pi}J_1(xsintheta)sin^2theta dtheta$



Thank you in advance.







definite-integrals bessel-functions






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 5 '18 at 2:49









ecookecook

109110




109110












  • $begingroup$
    It is $0$. $ $ $ $
    $endgroup$
    – Kemono Chen
    Dec 5 '18 at 3:23












  • $begingroup$
    Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
    $endgroup$
    – Nosrati
    Dec 5 '18 at 4:18


















  • $begingroup$
    It is $0$. $ $ $ $
    $endgroup$
    – Kemono Chen
    Dec 5 '18 at 3:23












  • $begingroup$
    Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
    $endgroup$
    – Nosrati
    Dec 5 '18 at 4:18
















$begingroup$
It is $0$. $ $ $ $
$endgroup$
– Kemono Chen
Dec 5 '18 at 3:23






$begingroup$
It is $0$. $ $ $ $
$endgroup$
– Kemono Chen
Dec 5 '18 at 3:23














$begingroup$
Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
$endgroup$
– Nosrati
Dec 5 '18 at 4:18




$begingroup$
Use the series form of $J_1$ and change the sum and integral, then prove $$int_0^{2pi}sin^{2k+3}t dt=0$$
$endgroup$
– Nosrati
Dec 5 '18 at 4:18










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