Am I exceeding the maximum ratings?
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10
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I'm using LMC6482 opamp with +/-15V rail voltages and having weird behavior. This means Vcc is +15V and Vee is -15V in my case.
Am I exceeding the specs? The jargon in the datasheet is not clear or should I say I'm not familiar with it.
op-amp power
add a comment |
up vote
10
down vote
favorite
I'm using LMC6482 opamp with +/-15V rail voltages and having weird behavior. This means Vcc is +15V and Vee is -15V in my case.
Am I exceeding the specs? The jargon in the datasheet is not clear or should I say I'm not familiar with it.
op-amp power
You could do 15V and 0V, but that probably won't meet your needs.
– StainlessSteelRat
2 days ago
add a comment |
up vote
10
down vote
favorite
up vote
10
down vote
favorite
I'm using LMC6482 opamp with +/-15V rail voltages and having weird behavior. This means Vcc is +15V and Vee is -15V in my case.
Am I exceeding the specs? The jargon in the datasheet is not clear or should I say I'm not familiar with it.
op-amp power
I'm using LMC6482 opamp with +/-15V rail voltages and having weird behavior. This means Vcc is +15V and Vee is -15V in my case.
Am I exceeding the specs? The jargon in the datasheet is not clear or should I say I'm not familiar with it.
op-amp power
op-amp power
edited 2 days ago
Transistor
79k777172
79k777172
asked 2 days ago
user164567
663518
663518
You could do 15V and 0V, but that probably won't meet your needs.
– StainlessSteelRat
2 days ago
add a comment |
You could do 15V and 0V, but that probably won't meet your needs.
– StainlessSteelRat
2 days ago
You could do 15V and 0V, but that probably won't meet your needs.
– StainlessSteelRat
2 days ago
You could do 15V and 0V, but that probably won't meet your needs.
– StainlessSteelRat
2 days ago
add a comment |
4 Answers
4
active
oldest
votes
up vote
22
down vote
Yes, you are exceeding the specs. Look at table 6.1 of the DATASHEET on page 3:
It clearly states the maximum difference between the V+ and V- pins is 16V. This means you can have +8V and -8V, as the difference is 16V.
As you have it right now, your difference is 30V, which is almost double the maximum ratings. Chances are, you have damaged the op-amp and it will need to be replaced. You should ALWAYS check the maximum ratings of any IC you are using if you are worried. If you can, try and be within the maximum, so +7.5V and -7.5V would work nicely here, for a total of 15V supply.
3
OP did check the maximum ratings, but was confused. And it seems to be guaranteed to function well for a 15 volt supply, so ±7.5 would be nice.
– pipe
2 days ago
8
"The jargon in the datasheet is not clear" sounds to me like he actually read it but did not understand it.
– pipe
2 days ago
4
Also worth noting that the chip is designed for a nominal supply voltage of 3V, 5V, or 15V. 16V is the absolute maximum but it should not be the design voltage. We never design to absolute maximums - we usually design with safety margins specifically to avoid them.
– J...
2 days ago
7
"You should ALWAYS check the maximum ratings" - NO NO NO. You should check the (recommended) operating conditions! Please don't point anyone (especially not newbies) at the absolute maxima.
– Wouter van Ooijen
2 days ago
1
I would think it's a given that you don't go all the way to the maximum. That's why you check them. You should always check the maximum to make sure you stay within them
– MCG
2 days ago
|
show 5 more comments
up vote
11
down vote
Figure 1. Vmax.
This line of the datasheet is stating that the maximum voltage difference between V+ and V- is 16 V.
You have probably damaged the op-amp.
Oh I thought it is +16 to -16. :(( And it is damaged yes it doesn't function as it supposed to.
– user164567
2 days ago
1
I've never seen it written that way before but I take it to mean you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other. Sorry for your loss!
– Transistor
2 days ago
1
"you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other." Absolute maximum ratings should not be used for normal operation, so 0/15V or .15/0 V or -7/+7 V or a lower voltage.
– Uwe
yesterday
add a comment |
up vote
8
down vote
I read your question as "yes I've read the datasheet, but its unclear". So let's address how to read the supply voltage range specification as the manufacturer Texas Instruments write it in their original product data sheet:
Supply Voltage (V+ - V-)... MAX 16V
You have a V+ of 15V and a V- of -15V.
Now we use the formula from the data sheet and get:
(15 - (-15)) = 15 + 15 = 30V
That's the way to interpret this voltage range specification. So yes, you are exceeding specified maximum supply voltage range by 14V.
add a comment |
up vote
8
down vote
Other answers mentione the asbsolute maximum ratings, which is NOT what youy should look for when designing a functional system. Instead, you should use the recommended operating conditions. In this case, those specify 15.5V.
In your case, you could check the absolute maxima to find out whether your chip had a chance of survival. As others have pointed out, that is not the case.
2
Finally the only one answer using the recommended operating conditions! So the opamp may be used with very low voltages too, for instance -2/+2 V or 0/4 V. When reading a datasheet it is very important to look for both absolute maximum ratings and recommended operating conditions and read and respect them both. When using -7.5/+7.5 V, spikes on supply voltages should not exceed 0.25 V.
– Uwe
yesterday
add a comment |
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
22
down vote
Yes, you are exceeding the specs. Look at table 6.1 of the DATASHEET on page 3:
It clearly states the maximum difference between the V+ and V- pins is 16V. This means you can have +8V and -8V, as the difference is 16V.
As you have it right now, your difference is 30V, which is almost double the maximum ratings. Chances are, you have damaged the op-amp and it will need to be replaced. You should ALWAYS check the maximum ratings of any IC you are using if you are worried. If you can, try and be within the maximum, so +7.5V and -7.5V would work nicely here, for a total of 15V supply.
3
OP did check the maximum ratings, but was confused. And it seems to be guaranteed to function well for a 15 volt supply, so ±7.5 would be nice.
– pipe
2 days ago
8
"The jargon in the datasheet is not clear" sounds to me like he actually read it but did not understand it.
– pipe
2 days ago
4
Also worth noting that the chip is designed for a nominal supply voltage of 3V, 5V, or 15V. 16V is the absolute maximum but it should not be the design voltage. We never design to absolute maximums - we usually design with safety margins specifically to avoid them.
– J...
2 days ago
7
"You should ALWAYS check the maximum ratings" - NO NO NO. You should check the (recommended) operating conditions! Please don't point anyone (especially not newbies) at the absolute maxima.
– Wouter van Ooijen
2 days ago
1
I would think it's a given that you don't go all the way to the maximum. That's why you check them. You should always check the maximum to make sure you stay within them
– MCG
2 days ago
|
show 5 more comments
up vote
22
down vote
Yes, you are exceeding the specs. Look at table 6.1 of the DATASHEET on page 3:
It clearly states the maximum difference between the V+ and V- pins is 16V. This means you can have +8V and -8V, as the difference is 16V.
As you have it right now, your difference is 30V, which is almost double the maximum ratings. Chances are, you have damaged the op-amp and it will need to be replaced. You should ALWAYS check the maximum ratings of any IC you are using if you are worried. If you can, try and be within the maximum, so +7.5V and -7.5V would work nicely here, for a total of 15V supply.
3
OP did check the maximum ratings, but was confused. And it seems to be guaranteed to function well for a 15 volt supply, so ±7.5 would be nice.
– pipe
2 days ago
8
"The jargon in the datasheet is not clear" sounds to me like he actually read it but did not understand it.
– pipe
2 days ago
4
Also worth noting that the chip is designed for a nominal supply voltage of 3V, 5V, or 15V. 16V is the absolute maximum but it should not be the design voltage. We never design to absolute maximums - we usually design with safety margins specifically to avoid them.
– J...
2 days ago
7
"You should ALWAYS check the maximum ratings" - NO NO NO. You should check the (recommended) operating conditions! Please don't point anyone (especially not newbies) at the absolute maxima.
– Wouter van Ooijen
2 days ago
1
I would think it's a given that you don't go all the way to the maximum. That's why you check them. You should always check the maximum to make sure you stay within them
– MCG
2 days ago
|
show 5 more comments
up vote
22
down vote
up vote
22
down vote
Yes, you are exceeding the specs. Look at table 6.1 of the DATASHEET on page 3:
It clearly states the maximum difference between the V+ and V- pins is 16V. This means you can have +8V and -8V, as the difference is 16V.
As you have it right now, your difference is 30V, which is almost double the maximum ratings. Chances are, you have damaged the op-amp and it will need to be replaced. You should ALWAYS check the maximum ratings of any IC you are using if you are worried. If you can, try and be within the maximum, so +7.5V and -7.5V would work nicely here, for a total of 15V supply.
Yes, you are exceeding the specs. Look at table 6.1 of the DATASHEET on page 3:
It clearly states the maximum difference between the V+ and V- pins is 16V. This means you can have +8V and -8V, as the difference is 16V.
As you have it right now, your difference is 30V, which is almost double the maximum ratings. Chances are, you have damaged the op-amp and it will need to be replaced. You should ALWAYS check the maximum ratings of any IC you are using if you are worried. If you can, try and be within the maximum, so +7.5V and -7.5V would work nicely here, for a total of 15V supply.
edited 2 days ago
answered 2 days ago
MCG
5,62731443
5,62731443
3
OP did check the maximum ratings, but was confused. And it seems to be guaranteed to function well for a 15 volt supply, so ±7.5 would be nice.
– pipe
2 days ago
8
"The jargon in the datasheet is not clear" sounds to me like he actually read it but did not understand it.
– pipe
2 days ago
4
Also worth noting that the chip is designed for a nominal supply voltage of 3V, 5V, or 15V. 16V is the absolute maximum but it should not be the design voltage. We never design to absolute maximums - we usually design with safety margins specifically to avoid them.
– J...
2 days ago
7
"You should ALWAYS check the maximum ratings" - NO NO NO. You should check the (recommended) operating conditions! Please don't point anyone (especially not newbies) at the absolute maxima.
– Wouter van Ooijen
2 days ago
1
I would think it's a given that you don't go all the way to the maximum. That's why you check them. You should always check the maximum to make sure you stay within them
– MCG
2 days ago
|
show 5 more comments
3
OP did check the maximum ratings, but was confused. And it seems to be guaranteed to function well for a 15 volt supply, so ±7.5 would be nice.
– pipe
2 days ago
8
"The jargon in the datasheet is not clear" sounds to me like he actually read it but did not understand it.
– pipe
2 days ago
4
Also worth noting that the chip is designed for a nominal supply voltage of 3V, 5V, or 15V. 16V is the absolute maximum but it should not be the design voltage. We never design to absolute maximums - we usually design with safety margins specifically to avoid them.
– J...
2 days ago
7
"You should ALWAYS check the maximum ratings" - NO NO NO. You should check the (recommended) operating conditions! Please don't point anyone (especially not newbies) at the absolute maxima.
– Wouter van Ooijen
2 days ago
1
I would think it's a given that you don't go all the way to the maximum. That's why you check them. You should always check the maximum to make sure you stay within them
– MCG
2 days ago
3
3
OP did check the maximum ratings, but was confused. And it seems to be guaranteed to function well for a 15 volt supply, so ±7.5 would be nice.
– pipe
2 days ago
OP did check the maximum ratings, but was confused. And it seems to be guaranteed to function well for a 15 volt supply, so ±7.5 would be nice.
– pipe
2 days ago
8
8
"The jargon in the datasheet is not clear" sounds to me like he actually read it but did not understand it.
– pipe
2 days ago
"The jargon in the datasheet is not clear" sounds to me like he actually read it but did not understand it.
– pipe
2 days ago
4
4
Also worth noting that the chip is designed for a nominal supply voltage of 3V, 5V, or 15V. 16V is the absolute maximum but it should not be the design voltage. We never design to absolute maximums - we usually design with safety margins specifically to avoid them.
– J...
2 days ago
Also worth noting that the chip is designed for a nominal supply voltage of 3V, 5V, or 15V. 16V is the absolute maximum but it should not be the design voltage. We never design to absolute maximums - we usually design with safety margins specifically to avoid them.
– J...
2 days ago
7
7
"You should ALWAYS check the maximum ratings" - NO NO NO. You should check the (recommended) operating conditions! Please don't point anyone (especially not newbies) at the absolute maxima.
– Wouter van Ooijen
2 days ago
"You should ALWAYS check the maximum ratings" - NO NO NO. You should check the (recommended) operating conditions! Please don't point anyone (especially not newbies) at the absolute maxima.
– Wouter van Ooijen
2 days ago
1
1
I would think it's a given that you don't go all the way to the maximum. That's why you check them. You should always check the maximum to make sure you stay within them
– MCG
2 days ago
I would think it's a given that you don't go all the way to the maximum. That's why you check them. You should always check the maximum to make sure you stay within them
– MCG
2 days ago
|
show 5 more comments
up vote
11
down vote
Figure 1. Vmax.
This line of the datasheet is stating that the maximum voltage difference between V+ and V- is 16 V.
You have probably damaged the op-amp.
Oh I thought it is +16 to -16. :(( And it is damaged yes it doesn't function as it supposed to.
– user164567
2 days ago
1
I've never seen it written that way before but I take it to mean you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other. Sorry for your loss!
– Transistor
2 days ago
1
"you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other." Absolute maximum ratings should not be used for normal operation, so 0/15V or .15/0 V or -7/+7 V or a lower voltage.
– Uwe
yesterday
add a comment |
up vote
11
down vote
Figure 1. Vmax.
This line of the datasheet is stating that the maximum voltage difference between V+ and V- is 16 V.
You have probably damaged the op-amp.
Oh I thought it is +16 to -16. :(( And it is damaged yes it doesn't function as it supposed to.
– user164567
2 days ago
1
I've never seen it written that way before but I take it to mean you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other. Sorry for your loss!
– Transistor
2 days ago
1
"you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other." Absolute maximum ratings should not be used for normal operation, so 0/15V or .15/0 V or -7/+7 V or a lower voltage.
– Uwe
yesterday
add a comment |
up vote
11
down vote
up vote
11
down vote
Figure 1. Vmax.
This line of the datasheet is stating that the maximum voltage difference between V+ and V- is 16 V.
You have probably damaged the op-amp.
Figure 1. Vmax.
This line of the datasheet is stating that the maximum voltage difference between V+ and V- is 16 V.
You have probably damaged the op-amp.
answered 2 days ago
Transistor
79k777172
79k777172
Oh I thought it is +16 to -16. :(( And it is damaged yes it doesn't function as it supposed to.
– user164567
2 days ago
1
I've never seen it written that way before but I take it to mean you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other. Sorry for your loss!
– Transistor
2 days ago
1
"you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other." Absolute maximum ratings should not be used for normal operation, so 0/15V or .15/0 V or -7/+7 V or a lower voltage.
– Uwe
yesterday
add a comment |
Oh I thought it is +16 to -16. :(( And it is damaged yes it doesn't function as it supposed to.
– user164567
2 days ago
1
I've never seen it written that way before but I take it to mean you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other. Sorry for your loss!
– Transistor
2 days ago
1
"you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other." Absolute maximum ratings should not be used for normal operation, so 0/15V or .15/0 V or -7/+7 V or a lower voltage.
– Uwe
yesterday
Oh I thought it is +16 to -16. :(( And it is damaged yes it doesn't function as it supposed to.
– user164567
2 days ago
Oh I thought it is +16 to -16. :(( And it is damaged yes it doesn't function as it supposed to.
– user164567
2 days ago
1
1
I've never seen it written that way before but I take it to mean you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other. Sorry for your loss!
– Transistor
2 days ago
I've never seen it written that way before but I take it to mean you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other. Sorry for your loss!
– Transistor
2 days ago
1
1
"you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other." Absolute maximum ratings should not be used for normal operation, so 0/15V or .15/0 V or -7/+7 V or a lower voltage.
– Uwe
yesterday
"you can run it 0/16V or -16/0 V or -5/+5 or any other combination provided that it's 16 V max from one to the other." Absolute maximum ratings should not be used for normal operation, so 0/15V or .15/0 V or -7/+7 V or a lower voltage.
– Uwe
yesterday
add a comment |
up vote
8
down vote
I read your question as "yes I've read the datasheet, but its unclear". So let's address how to read the supply voltage range specification as the manufacturer Texas Instruments write it in their original product data sheet:
Supply Voltage (V+ - V-)... MAX 16V
You have a V+ of 15V and a V- of -15V.
Now we use the formula from the data sheet and get:
(15 - (-15)) = 15 + 15 = 30V
That's the way to interpret this voltage range specification. So yes, you are exceeding specified maximum supply voltage range by 14V.
add a comment |
up vote
8
down vote
I read your question as "yes I've read the datasheet, but its unclear". So let's address how to read the supply voltage range specification as the manufacturer Texas Instruments write it in their original product data sheet:
Supply Voltage (V+ - V-)... MAX 16V
You have a V+ of 15V and a V- of -15V.
Now we use the formula from the data sheet and get:
(15 - (-15)) = 15 + 15 = 30V
That's the way to interpret this voltage range specification. So yes, you are exceeding specified maximum supply voltage range by 14V.
add a comment |
up vote
8
down vote
up vote
8
down vote
I read your question as "yes I've read the datasheet, but its unclear". So let's address how to read the supply voltage range specification as the manufacturer Texas Instruments write it in their original product data sheet:
Supply Voltage (V+ - V-)... MAX 16V
You have a V+ of 15V and a V- of -15V.
Now we use the formula from the data sheet and get:
(15 - (-15)) = 15 + 15 = 30V
That's the way to interpret this voltage range specification. So yes, you are exceeding specified maximum supply voltage range by 14V.
I read your question as "yes I've read the datasheet, but its unclear". So let's address how to read the supply voltage range specification as the manufacturer Texas Instruments write it in their original product data sheet:
Supply Voltage (V+ - V-)... MAX 16V
You have a V+ of 15V and a V- of -15V.
Now we use the formula from the data sheet and get:
(15 - (-15)) = 15 + 15 = 30V
That's the way to interpret this voltage range specification. So yes, you are exceeding specified maximum supply voltage range by 14V.
answered 2 days ago
dlatikay
501210
501210
add a comment |
add a comment |
up vote
8
down vote
Other answers mentione the asbsolute maximum ratings, which is NOT what youy should look for when designing a functional system. Instead, you should use the recommended operating conditions. In this case, those specify 15.5V.
In your case, you could check the absolute maxima to find out whether your chip had a chance of survival. As others have pointed out, that is not the case.
2
Finally the only one answer using the recommended operating conditions! So the opamp may be used with very low voltages too, for instance -2/+2 V or 0/4 V. When reading a datasheet it is very important to look for both absolute maximum ratings and recommended operating conditions and read and respect them both. When using -7.5/+7.5 V, spikes on supply voltages should not exceed 0.25 V.
– Uwe
yesterday
add a comment |
up vote
8
down vote
Other answers mentione the asbsolute maximum ratings, which is NOT what youy should look for when designing a functional system. Instead, you should use the recommended operating conditions. In this case, those specify 15.5V.
In your case, you could check the absolute maxima to find out whether your chip had a chance of survival. As others have pointed out, that is not the case.
2
Finally the only one answer using the recommended operating conditions! So the opamp may be used with very low voltages too, for instance -2/+2 V or 0/4 V. When reading a datasheet it is very important to look for both absolute maximum ratings and recommended operating conditions and read and respect them both. When using -7.5/+7.5 V, spikes on supply voltages should not exceed 0.25 V.
– Uwe
yesterday
add a comment |
up vote
8
down vote
up vote
8
down vote
Other answers mentione the asbsolute maximum ratings, which is NOT what youy should look for when designing a functional system. Instead, you should use the recommended operating conditions. In this case, those specify 15.5V.
In your case, you could check the absolute maxima to find out whether your chip had a chance of survival. As others have pointed out, that is not the case.
Other answers mentione the asbsolute maximum ratings, which is NOT what youy should look for when designing a functional system. Instead, you should use the recommended operating conditions. In this case, those specify 15.5V.
In your case, you could check the absolute maxima to find out whether your chip had a chance of survival. As others have pointed out, that is not the case.
answered 2 days ago
Wouter van Ooijen
44k150117
44k150117
2
Finally the only one answer using the recommended operating conditions! So the opamp may be used with very low voltages too, for instance -2/+2 V or 0/4 V. When reading a datasheet it is very important to look for both absolute maximum ratings and recommended operating conditions and read and respect them both. When using -7.5/+7.5 V, spikes on supply voltages should not exceed 0.25 V.
– Uwe
yesterday
add a comment |
2
Finally the only one answer using the recommended operating conditions! So the opamp may be used with very low voltages too, for instance -2/+2 V or 0/4 V. When reading a datasheet it is very important to look for both absolute maximum ratings and recommended operating conditions and read and respect them both. When using -7.5/+7.5 V, spikes on supply voltages should not exceed 0.25 V.
– Uwe
yesterday
2
2
Finally the only one answer using the recommended operating conditions! So the opamp may be used with very low voltages too, for instance -2/+2 V or 0/4 V. When reading a datasheet it is very important to look for both absolute maximum ratings and recommended operating conditions and read and respect them both. When using -7.5/+7.5 V, spikes on supply voltages should not exceed 0.25 V.
– Uwe
yesterday
Finally the only one answer using the recommended operating conditions! So the opamp may be used with very low voltages too, for instance -2/+2 V or 0/4 V. When reading a datasheet it is very important to look for both absolute maximum ratings and recommended operating conditions and read and respect them both. When using -7.5/+7.5 V, spikes on supply voltages should not exceed 0.25 V.
– Uwe
yesterday
add a comment |
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You could do 15V and 0V, but that probably won't meet your needs.
– StainlessSteelRat
2 days ago