Shift sign $y=frac x{|x|}$ function horizontally
up vote
0
down vote
favorite
I know how to shift linear and quadratic functions but is there a way to shift a sign or $$y=frac x{|x|}$$ function?
graphing-functions
edited Nov 22 at 17:32
idea
2,00331024
asked Nov 22 at 17:26
Oliver Tušla
31
add a comment |
up vote
0
down vote
favorite
I know how to shift linear and quadratic functions but is there a way to shift a sign or $$y=frac x{|x|}$$ function?
graphing-functions
edited Nov 22 at 17:32
idea
2,00331024
asked Nov 22 at 17:26
Oliver Tušla
31
One can in general shift $y=f(x)$. See for instance this note: math.utah.edu/~giessing/notes/ch3.6b.pdf and also math.berkeley.edu/~qiuyi/m1af14/EER4_Notes.pdf
– user587192
Nov 22 at 17:37
Do you mean something different from simply replacing every $x$ in the expression by $x-c$ for some $c$ being the distance you want to shift the graph?
– Henning Makholm
Nov 22 at 17:41
No, I didn't mean anything else. Thank you for the resources.
– Oliver Tušla
Nov 22 at 18:45
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I know how to shift linear and quadratic functions but is there a way to shift a sign or $$y=frac x{|x|}$$ function?
graphing-functions
edited Nov 22 at 17:32
idea
2,00331024
asked Nov 22 at 17:26
Oliver Tušla
31
I know how to shift linear and quadratic functions but is there a way to shift a sign or $$y=frac x{|x|}$$ function?
graphing-functions
graphing-functions
edited Nov 22 at 17:32
idea
2,00331024
asked Nov 22 at 17:26
Oliver Tušla
31
edited Nov 22 at 17:32
idea
2,00331024
asked Nov 22 at 17:26
Oliver Tušla
31
edited Nov 22 at 17:32
idea
2,00331024
edited Nov 22 at 17:32
idea
2,00331024
edited Nov 22 at 17:32
idea
2,00331024
2,00331024
asked Nov 22 at 17:26
Oliver Tušla
31
asked Nov 22 at 17:26
Oliver Tušla
31
asked Nov 22 at 17:26
Oliver Tušla
31
31
One can in general shift $y=f(x)$. See for instance this note: math.utah.edu/~giessing/notes/ch3.6b.pdf and also math.berkeley.edu/~qiuyi/m1af14/EER4_Notes.pdf
– user587192
Nov 22 at 17:37
Do you mean something different from simply replacing every $x$ in the expression by $x-c$ for some $c$ being the distance you want to shift the graph?
– Henning Makholm
Nov 22 at 17:41
No, I didn't mean anything else. Thank you for the resources.
– Oliver Tušla
Nov 22 at 18:45
add a comment |
One can in general shift $y=f(x)$. See for instance this note: math.utah.edu/~giessing/notes/ch3.6b.pdf and also math.berkeley.edu/~qiuyi/m1af14/EER4_Notes.pdf
– user587192
Nov 22 at 17:37
Do you mean something different from simply replacing every $x$ in the expression by $x-c$ for some $c$ being the distance you want to shift the graph?
– Henning Makholm
Nov 22 at 17:41
No, I didn't mean anything else. Thank you for the resources.
– Oliver Tušla
Nov 22 at 18:45
One can in general shift $y=f(x)$. See for instance this note: math.utah.edu/~giessing/notes/ch3.6b.pdf and also math.berkeley.edu/~qiuyi/m1af14/EER4_Notes.pdf
– user587192
Nov 22 at 17:37
One can in general shift $y=f(x)$. See for instance this note: math.utah.edu/~giessing/notes/ch3.6b.pdf and also math.berkeley.edu/~qiuyi/m1af14/EER4_Notes.pdf
– user587192
Nov 22 at 17:37
Do you mean something different from simply replacing every $x$ in the expression by $x-c$ for some $c$ being the distance you want to shift the graph?
– Henning Makholm
Nov 22 at 17:41
Do you mean something different from simply replacing every $x$ in the expression by $x-c$ for some $c$ being the distance you want to shift the graph?
– Henning Makholm
Nov 22 at 17:41
No, I didn't mean anything else. Thank you for the resources.
– Oliver Tušla
Nov 22 at 18:45
No, I didn't mean anything else. Thank you for the resources.
– Oliver Tušla
Nov 22 at 18:45
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
Hint:
To shift any function $f$ horizontally, all you need to do is to replace $x$ by $xpm c$ where c is the distance of the shift and the sign $pm$ indicates the direction of the shift.
answered Nov 22 at 17:43
hamza boulahia
964319
Yes, you are right. After a lot of fiddling, it turned out I misplaced parentheses when graphing the absolute value.
– Oliver Tušla
Nov 22 at 18:44
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3009382%2fshift-sign-y-frac-xx-function-horizontally%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Hint:
To shift any function $f$ horizontally, all you need to do is to replace $x$ by $xpm c$ where c is the distance of the shift and the sign $pm$ indicates the direction of the shift.
answered Nov 22 at 17:43
hamza boulahia
964319
Yes, you are right. After a lot of fiddling, it turned out I misplaced parentheses when graphing the absolute value.
– Oliver Tušla
Nov 22 at 18:44
add a comment |
up vote
1
down vote
accepted
Hint:
To shift any function $f$ horizontally, all you need to do is to replace $x$ by $xpm c$ where c is the distance of the shift and the sign $pm$ indicates the direction of the shift.
answered Nov 22 at 17:43
hamza boulahia
964319
Yes, you are right. After a lot of fiddling, it turned out I misplaced parentheses when graphing the absolute value.
– Oliver Tušla
Nov 22 at 18:44
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Hint:
To shift any function $f$ horizontally, all you need to do is to replace $x$ by $xpm c$ where c is the distance of the shift and the sign $pm$ indicates the direction of the shift.
answered Nov 22 at 17:43
hamza boulahia
964319
Hint:
To shift any function $f$ horizontally, all you need to do is to replace $x$ by $xpm c$ where c is the distance of the shift and the sign $pm$ indicates the direction of the shift.
answered Nov 22 at 17:43
hamza boulahia
964319
answered Nov 22 at 17:43
hamza boulahia
964319
answered Nov 22 at 17:43
hamza boulahia
964319
answered Nov 22 at 17:43
hamza boulahia
964319
964319
Yes, you are right. After a lot of fiddling, it turned out I misplaced parentheses when graphing the absolute value.
– Oliver Tušla
Nov 22 at 18:44
add a comment |
Yes, you are right. After a lot of fiddling, it turned out I misplaced parentheses when graphing the absolute value.
– Oliver Tušla
Nov 22 at 18:44
Yes, you are right. After a lot of fiddling, it turned out I misplaced parentheses when graphing the absolute value.
– Oliver Tušla
Nov 22 at 18:44
Yes, you are right. After a lot of fiddling, it turned out I misplaced parentheses when graphing the absolute value.
– Oliver Tušla
Nov 22 at 18:44
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3009382%2fshift-sign-y-frac-xx-function-horizontally%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
One can in general shift $y=f(x)$. See for instance this note: math.utah.edu/~giessing/notes/ch3.6b.pdf and also math.berkeley.edu/~qiuyi/m1af14/EER4_Notes.pdf
– user587192
Nov 22 at 17:37
Do you mean something different from simply replacing every $x$ in the expression by $x-c$ for some $c$ being the distance you want to shift the graph?
– Henning Makholm
Nov 22 at 17:41
No, I didn't mean anything else. Thank you for the resources.
– Oliver Tušla
Nov 22 at 18:45