Let $S$ be a simple Module, prove $S^{(I)} cong S^{(I)}$ iff $|I|=|J|$
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Im looking for I proof on this Theorem since my lecture demonstration was kind of redundant.The proof $|I|=|J|$ implies $S^{(I)} cong S^{(I)}$ its quite easy, im more interested in the other implication
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Im looking for I proof on this Theorem since my lecture demonstration was kind of redundant.The proof $|I|=|J|$ implies $S^{(I)} cong S^{(I)}$ its quite easy, im more interested in the other implication
modules
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Im looking for I proof on this Theorem since my lecture demonstration was kind of redundant.The proof $|I|=|J|$ implies $S^{(I)} cong S^{(I)}$ its quite easy, im more interested in the other implication
modules
Im looking for I proof on this Theorem since my lecture demonstration was kind of redundant.The proof $|I|=|J|$ implies $S^{(I)} cong S^{(I)}$ its quite easy, im more interested in the other implication
modules
modules
asked yesterday
Marcos Martínez Wagner
726
726
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