Fourier Transform of Gaussian over Gaussian (sort of)











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I need help with the inverse fourier transform of the following expression



$$frac{ae^{-w^2/2}}{ae^{-w^2/2}+b}$$



where $a > 0,b > 0$ and $w$ is the angular frequency.



Top term is simply a Gaussian. It looks very simple except the additive term in denominator which complicates things.










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    up vote
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    down vote

    favorite












    I need help with the inverse fourier transform of the following expression



    $$frac{ae^{-w^2/2}}{ae^{-w^2/2}+b}$$



    where $a > 0,b > 0$ and $w$ is the angular frequency.



    Top term is simply a Gaussian. It looks very simple except the additive term in denominator which complicates things.










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I need help with the inverse fourier transform of the following expression



      $$frac{ae^{-w^2/2}}{ae^{-w^2/2}+b}$$



      where $a > 0,b > 0$ and $w$ is the angular frequency.



      Top term is simply a Gaussian. It looks very simple except the additive term in denominator which complicates things.










      share|cite|improve this question













      I need help with the inverse fourier transform of the following expression



      $$frac{ae^{-w^2/2}}{ae^{-w^2/2}+b}$$



      where $a > 0,b > 0$ and $w$ is the angular frequency.



      Top term is simply a Gaussian. It looks very simple except the additive term in denominator which complicates things.







      fourier-transform






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      share|cite|improve this question











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      asked Nov 22 at 18:34









      Cowboy Trader

      8712




      8712






















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          At least for $|a| < |b|$, you can express your function as a convergent series in powers of $a$:



          $$ sum_{n=1}^infty (-1)^{n+1} frac{a^n}{b^n} e^{-nw^2/2}$$



          and then transform term-by-term.






          share|cite|improve this answer





















          • What is this series called? Can it be applied to any function with af(x)/(af(x) + b)?
            – Cowboy Trader
            Nov 23 at 6:07












          • It's just a geometric series.
            – Robert Israel
            Nov 23 at 20:19











          Your Answer





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          1 Answer
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          active

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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

          oldest

          votes








          up vote
          2
          down vote













          At least for $|a| < |b|$, you can express your function as a convergent series in powers of $a$:



          $$ sum_{n=1}^infty (-1)^{n+1} frac{a^n}{b^n} e^{-nw^2/2}$$



          and then transform term-by-term.






          share|cite|improve this answer





















          • What is this series called? Can it be applied to any function with af(x)/(af(x) + b)?
            – Cowboy Trader
            Nov 23 at 6:07












          • It's just a geometric series.
            – Robert Israel
            Nov 23 at 20:19















          up vote
          2
          down vote













          At least for $|a| < |b|$, you can express your function as a convergent series in powers of $a$:



          $$ sum_{n=1}^infty (-1)^{n+1} frac{a^n}{b^n} e^{-nw^2/2}$$



          and then transform term-by-term.






          share|cite|improve this answer





















          • What is this series called? Can it be applied to any function with af(x)/(af(x) + b)?
            – Cowboy Trader
            Nov 23 at 6:07












          • It's just a geometric series.
            – Robert Israel
            Nov 23 at 20:19













          up vote
          2
          down vote










          up vote
          2
          down vote









          At least for $|a| < |b|$, you can express your function as a convergent series in powers of $a$:



          $$ sum_{n=1}^infty (-1)^{n+1} frac{a^n}{b^n} e^{-nw^2/2}$$



          and then transform term-by-term.






          share|cite|improve this answer












          At least for $|a| < |b|$, you can express your function as a convergent series in powers of $a$:



          $$ sum_{n=1}^infty (-1)^{n+1} frac{a^n}{b^n} e^{-nw^2/2}$$



          and then transform term-by-term.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 22 at 19:12









          Robert Israel

          317k23206457




          317k23206457












          • What is this series called? Can it be applied to any function with af(x)/(af(x) + b)?
            – Cowboy Trader
            Nov 23 at 6:07












          • It's just a geometric series.
            – Robert Israel
            Nov 23 at 20:19


















          • What is this series called? Can it be applied to any function with af(x)/(af(x) + b)?
            – Cowboy Trader
            Nov 23 at 6:07












          • It's just a geometric series.
            – Robert Israel
            Nov 23 at 20:19
















          What is this series called? Can it be applied to any function with af(x)/(af(x) + b)?
          – Cowboy Trader
          Nov 23 at 6:07






          What is this series called? Can it be applied to any function with af(x)/(af(x) + b)?
          – Cowboy Trader
          Nov 23 at 6:07














          It's just a geometric series.
          – Robert Israel
          Nov 23 at 20:19




          It's just a geometric series.
          – Robert Israel
          Nov 23 at 20:19


















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