Overhead brace in tikz
up vote
5
down vote
favorite
I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.
Here is a template:
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
add a comment |
up vote
5
down vote
favorite
I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.
Here is a template:
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
add a comment |
up vote
5
down vote
favorite
up vote
5
down vote
favorite
I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.
Here is a template:
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.
Here is a template:
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
tikz-pgf horizontal-alignment vertical-alignment braces overbrace
asked 1 hour ago
wonderich
632618
632618
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
5
down vote
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
1 hour ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
1 hour ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
1 hour ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
1 hour ago
add a comment |
up vote
5
down vote
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
1 hour ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
1 hour ago
add a comment |
up vote
5
down vote
up vote
5
down vote
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
I have not simplified your code which can be simplified in several different ways. I used the positioning
library (page 229 of the manual 3.0.1a) to position nodes 2
and 1
relative to node 3
.
I named a few nodes by their value.
To use the braces, I used the decorations.pathreplacing
library. (page 581 of manual 3.0.1a)
documentclass[11pt,urlcolor=blue, linkcolor=blue]{article}
% usepackage{sseq}
% usepackage[all,cmtip]{xy}
% usepackage{tikz-cd}
usepackage{tikz}
% usetikzlibrary{matrix}
% usetikzlibrary{decorations.markings}
usetikzlibrary{positioning,decorations.pathreplacing}
begin{document}
begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,4)(3) {3};
node[above =of 3] {1};
node[above=5mm of 3]{2};
node at (-4,4)(8) {8};
node at (4,4)(11) {11};
draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};
draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};
end{tikzpicture}
end{center}
end{figure}
end{document}
edited 1 hour ago
answered 1 hour ago
AndréC
7,13211340
7,13211340
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
1 hour ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
1 hour ago
add a comment |
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
1 hour ago
You can use thegraphs
library in several different ways to make this graph (see page 257)
– AndréC
1 hour ago
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
1 hour ago
that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
– wonderich
1 hour ago
You can use the
graphs
library in several different ways to make this graph (see page 257)– AndréC
1 hour ago
You can use the
graphs
library in several different ways to make this graph (see page 257)– AndréC
1 hour ago
add a comment |
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