What's wrong with this Latex equation? Missing $? and undefinded control sequence












3














documentclass[10pt]{article}

usepackage[usenames]{color} % Farbunterstützung

usepackage{amssymb}    % Mathe

usepackage{amsmath} % Mathe

usepackage[utf8]{inputenc} % Direkte Eingabe von Umlauten und anderen Diakritika

usepackage{braket}



(-1)^p=(-1)^{$P^{prime}$+$P^{primeprime}$}





math-mode equations







share|improve this question




















  • 4




    Welcome! You cannot have (-1)^p=(-1)^ outside math mode. Try documentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
    – marmot
    Dec 6 at 17:16








  • 4




    You're also missing both a begin{document} and an end{document} directive.
    – Mico
    Dec 6 at 17:17
















3














documentclass[10pt]{article}

usepackage[usenames]{color} % Farbunterstützung

usepackage{amssymb}    % Mathe

usepackage{amsmath} % Mathe

usepackage[utf8]{inputenc} % Direkte Eingabe von Umlauten und anderen Diakritika

usepackage{braket}



(-1)^p=(-1)^{$P^{prime}$+$P^{primeprime}$}





math-mode equations







share|improve this question




















  • 4




    Welcome! You cannot have (-1)^p=(-1)^ outside math mode. Try documentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
    – marmot
    Dec 6 at 17:16








  • 4




    You're also missing both a begin{document} and an end{document} directive.
    – Mico
    Dec 6 at 17:17














3












3








3







documentclass[10pt]{article}

usepackage[usenames]{color} % Farbunterstützung

usepackage{amssymb}    % Mathe

usepackage{amsmath} % Mathe

usepackage[utf8]{inputenc} % Direkte Eingabe von Umlauten und anderen Diakritika

usepackage{braket}



(-1)^p=(-1)^{$P^{prime}$+$P^{primeprime}$}





math-mode equations







share|improve this question















documentclass[10pt]{article}

usepackage[usenames]{color} % Farbunterstützung

usepackage{amssymb}    % Mathe

usepackage{amsmath} % Mathe

usepackage[utf8]{inputenc} % Direkte Eingabe von Umlauten und anderen Diakritika

usepackage{braket}



(-1)^p=(-1)^{$P^{prime}$+$P^{primeprime}$}





math-mode equations




math-mode equations






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 6 at 18:56









Peter Mortensen

53536




53536










asked Dec 6 at 17:15









tqink

161




161








  • 4




    Welcome! You cannot have (-1)^p=(-1)^ outside math mode. Try documentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
    – marmot
    Dec 6 at 17:16








  • 4




    You're also missing both a begin{document} and an end{document} directive.
    – Mico
    Dec 6 at 17:17














  • 4




    Welcome! You cannot have (-1)^p=(-1)^ outside math mode. Try documentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
    – marmot
    Dec 6 at 17:16








  • 4




    You're also missing both a begin{document} and an end{document} directive.
    – Mico
    Dec 6 at 17:17








4




4




Welcome! You cannot have (-1)^p=(-1)^ outside math mode. Try documentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
– marmot
Dec 6 at 17:16






Welcome! You cannot have (-1)^p=(-1)^ outside math mode. Try documentclass{article} begin{document} $(-1)^p=(-1)^{P^{prime}+P^{primeprime}}$ or $(-1)^p=(-1)^{{P^{prime}+P^{primeprime}}}$ end{document}.
– marmot
Dec 6 at 17:16






4




4




You're also missing both a begin{document} and an end{document} directive.
– Mico
Dec 6 at 17:17




You're also missing both a begin{document} and an end{document} directive.
– Mico
Dec 6 at 17:17










1 Answer
1






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oldest

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I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)



enter image description here



documentclass{article}

begin{document}

$(-1)^p=(-1)^{(P'+P'')}$

end{document}





share|improve this answer





















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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    6














    I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)



    enter image description here



    documentclass{article}
    
begin{document}
    
$(-1)^p=(-1)^{(P'+P'')}$
    
end{document}





    share|improve this answer


























      6














      I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)



      enter image description here



      documentclass{article}
      
begin{document}
      
$(-1)^p=(-1)^{(P'+P'')}$
      
end{document}





      share|improve this answer
























        6












        6








        6






        I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)



        enter image description here



        documentclass{article}
        
begin{document}
        
$(-1)^p=(-1)^{(P'+P'')}$
        
end{document}





        share|improve this answer












        I believe this is what you're looking for. (I would also argue that writing ' is easier than ^{prime} -- and that writing '' is a lot easier than ^{primeprime}.)



        enter image description here



        documentclass{article}
        
begin{document}
        
$(-1)^p=(-1)^{(P'+P'')}$
        
end{document}






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 6 at 17:22









        Mico

        273k30369756




        273k30369756






























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