Fermat's Little Theorem and Carmichael Numbers












0














Fermat's little theorem states that if $p$ is a prime number and $a$ is a positive integer, then $p|a^p-a$.



However, the converse is false, that is, for integers $a$ and $p$, if $p|a^p-a$, then $a$ is a prime number, is a false statement. For instant, $561|a^{561}-a$ for some integer $a$, but $561$ is actually a composite number, and such numbers are called "Carmichael numbers".



In other words, a Carmichael number is a composite integer, say $k$, such that $k|a^k-a$ for all integers $a$.




This is what I know, am I right or I misunderstand something?




and




Do we have a way to find Carmichael numbers?











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  • 2




    Search the web for find Carmicael numbers maths.lancs.ac.uk/jameson/carfind.pdf
    – Ethan Bolker
    Nov 28 '18 at 17:04












  • There is a nice criterion for a squarefree odd composite $N>1$ : $N$ is a Carmichael number if and only if $p-1mid N-1$ holds for every prime $pmid N$. If $N$ is not squarefree odd and composite, it cannot be a Carmichael number. Moreover, it can be shown that $N$ must have at least three prime factors.
    – Peter
    Nov 28 '18 at 19:00


















0














Fermat's little theorem states that if $p$ is a prime number and $a$ is a positive integer, then $p|a^p-a$.



However, the converse is false, that is, for integers $a$ and $p$, if $p|a^p-a$, then $a$ is a prime number, is a false statement. For instant, $561|a^{561}-a$ for some integer $a$, but $561$ is actually a composite number, and such numbers are called "Carmichael numbers".



In other words, a Carmichael number is a composite integer, say $k$, such that $k|a^k-a$ for all integers $a$.




This is what I know, am I right or I misunderstand something?




and




Do we have a way to find Carmichael numbers?











share|cite|improve this question


















  • 2




    Search the web for find Carmicael numbers maths.lancs.ac.uk/jameson/carfind.pdf
    – Ethan Bolker
    Nov 28 '18 at 17:04












  • There is a nice criterion for a squarefree odd composite $N>1$ : $N$ is a Carmichael number if and only if $p-1mid N-1$ holds for every prime $pmid N$. If $N$ is not squarefree odd and composite, it cannot be a Carmichael number. Moreover, it can be shown that $N$ must have at least three prime factors.
    – Peter
    Nov 28 '18 at 19:00
















0












0








0







Fermat's little theorem states that if $p$ is a prime number and $a$ is a positive integer, then $p|a^p-a$.



However, the converse is false, that is, for integers $a$ and $p$, if $p|a^p-a$, then $a$ is a prime number, is a false statement. For instant, $561|a^{561}-a$ for some integer $a$, but $561$ is actually a composite number, and such numbers are called "Carmichael numbers".



In other words, a Carmichael number is a composite integer, say $k$, such that $k|a^k-a$ for all integers $a$.




This is what I know, am I right or I misunderstand something?




and




Do we have a way to find Carmichael numbers?











share|cite|improve this question













Fermat's little theorem states that if $p$ is a prime number and $a$ is a positive integer, then $p|a^p-a$.



However, the converse is false, that is, for integers $a$ and $p$, if $p|a^p-a$, then $a$ is a prime number, is a false statement. For instant, $561|a^{561}-a$ for some integer $a$, but $561$ is actually a composite number, and such numbers are called "Carmichael numbers".



In other words, a Carmichael number is a composite integer, say $k$, such that $k|a^k-a$ for all integers $a$.




This is what I know, am I right or I misunderstand something?




and




Do we have a way to find Carmichael numbers?








number-theory elementary-number-theory prime-numbers carmichael-numbers






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asked Nov 28 '18 at 17:02









Hussain-AlqatariHussain-Alqatari

2997




2997








  • 2




    Search the web for find Carmicael numbers maths.lancs.ac.uk/jameson/carfind.pdf
    – Ethan Bolker
    Nov 28 '18 at 17:04












  • There is a nice criterion for a squarefree odd composite $N>1$ : $N$ is a Carmichael number if and only if $p-1mid N-1$ holds for every prime $pmid N$. If $N$ is not squarefree odd and composite, it cannot be a Carmichael number. Moreover, it can be shown that $N$ must have at least three prime factors.
    – Peter
    Nov 28 '18 at 19:00
















  • 2




    Search the web for find Carmicael numbers maths.lancs.ac.uk/jameson/carfind.pdf
    – Ethan Bolker
    Nov 28 '18 at 17:04












  • There is a nice criterion for a squarefree odd composite $N>1$ : $N$ is a Carmichael number if and only if $p-1mid N-1$ holds for every prime $pmid N$. If $N$ is not squarefree odd and composite, it cannot be a Carmichael number. Moreover, it can be shown that $N$ must have at least three prime factors.
    – Peter
    Nov 28 '18 at 19:00










2




2




Search the web for find Carmicael numbers maths.lancs.ac.uk/jameson/carfind.pdf
– Ethan Bolker
Nov 28 '18 at 17:04






Search the web for find Carmicael numbers maths.lancs.ac.uk/jameson/carfind.pdf
– Ethan Bolker
Nov 28 '18 at 17:04














There is a nice criterion for a squarefree odd composite $N>1$ : $N$ is a Carmichael number if and only if $p-1mid N-1$ holds for every prime $pmid N$. If $N$ is not squarefree odd and composite, it cannot be a Carmichael number. Moreover, it can be shown that $N$ must have at least three prime factors.
– Peter
Nov 28 '18 at 19:00






There is a nice criterion for a squarefree odd composite $N>1$ : $N$ is a Carmichael number if and only if $p-1mid N-1$ holds for every prime $pmid N$. If $N$ is not squarefree odd and composite, it cannot be a Carmichael number. Moreover, it can be shown that $N$ must have at least three prime factors.
– Peter
Nov 28 '18 at 19:00












1 Answer
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Numbers of the form $(6k+1)(12k+1)(18k+1)$ are Carmichael numbers if each of the three factors is prime. This gives some examples - already $k=1$ works. Actually, the sequence A046025 gives more values, e.g.,



$$
k=1, 6, 35, 45, 51, 55, 56, 100, 121, 195, 206, 216, 255, 276, 370, 380,
426, 506, 510, 511, 710, 741, 800, 825, 871, 930, 975, 1025, 1060, 1115,
1140, 1161, 1270, 1280, 1281, 1311, 1336, 1361, 1365, 1381, 1420, 1421,
1441, 1490, 1515, 1696, 1805, 1875, 1885
$$






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    1 Answer
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    1 Answer
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    Numbers of the form $(6k+1)(12k+1)(18k+1)$ are Carmichael numbers if each of the three factors is prime. This gives some examples - already $k=1$ works. Actually, the sequence A046025 gives more values, e.g.,



    $$
    k=1, 6, 35, 45, 51, 55, 56, 100, 121, 195, 206, 216, 255, 276, 370, 380,
    426, 506, 510, 511, 710, 741, 800, 825, 871, 930, 975, 1025, 1060, 1115,
    1140, 1161, 1270, 1280, 1281, 1311, 1336, 1361, 1365, 1381, 1420, 1421,
    1441, 1490, 1515, 1696, 1805, 1875, 1885
    $$






    share|cite|improve this answer


























      0














      Numbers of the form $(6k+1)(12k+1)(18k+1)$ are Carmichael numbers if each of the three factors is prime. This gives some examples - already $k=1$ works. Actually, the sequence A046025 gives more values, e.g.,



      $$
      k=1, 6, 35, 45, 51, 55, 56, 100, 121, 195, 206, 216, 255, 276, 370, 380,
      426, 506, 510, 511, 710, 741, 800, 825, 871, 930, 975, 1025, 1060, 1115,
      1140, 1161, 1270, 1280, 1281, 1311, 1336, 1361, 1365, 1381, 1420, 1421,
      1441, 1490, 1515, 1696, 1805, 1875, 1885
      $$






      share|cite|improve this answer
























        0












        0








        0






        Numbers of the form $(6k+1)(12k+1)(18k+1)$ are Carmichael numbers if each of the three factors is prime. This gives some examples - already $k=1$ works. Actually, the sequence A046025 gives more values, e.g.,



        $$
        k=1, 6, 35, 45, 51, 55, 56, 100, 121, 195, 206, 216, 255, 276, 370, 380,
        426, 506, 510, 511, 710, 741, 800, 825, 871, 930, 975, 1025, 1060, 1115,
        1140, 1161, 1270, 1280, 1281, 1311, 1336, 1361, 1365, 1381, 1420, 1421,
        1441, 1490, 1515, 1696, 1805, 1875, 1885
        $$






        share|cite|improve this answer












        Numbers of the form $(6k+1)(12k+1)(18k+1)$ are Carmichael numbers if each of the three factors is prime. This gives some examples - already $k=1$ works. Actually, the sequence A046025 gives more values, e.g.,



        $$
        k=1, 6, 35, 45, 51, 55, 56, 100, 121, 195, 206, 216, 255, 276, 370, 380,
        426, 506, 510, 511, 710, 741, 800, 825, 871, 930, 975, 1025, 1060, 1115,
        1140, 1161, 1270, 1280, 1281, 1311, 1336, 1361, 1365, 1381, 1420, 1421,
        1441, 1490, 1515, 1696, 1805, 1875, 1885
        $$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 28 '18 at 19:13









        Dietrich BurdeDietrich Burde

        78k64386




        78k64386






























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