Homotheties: Let $A$ and $B$ be distinct points of a circle $o$. What is the set of possible centroids of...











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Question: Let $A$ and $B$ be distinct points of a circle $o$. What is the set of possible centroids of triangles $ABC$ with $Cin o$?



Here is what I have:
The angle at $C$ will always be the same as it is always subtended by the same arc as $A$ and $B$ are fixed.



There are 2 cases: Either $C$ lies on the small arc of $AB$ or $C$ lies on the big arc of $AB$.



In the case where $C$ lies on the large arc, by looking at the possible positions of $C$ one can observe that at some point $C$ and $A$ are on the same diameter and at another point $C$ and $B$ are on the same diameter. Also, it is worth mentioning that the midpoint at which $c$ intersects on the chord $AB$ does not depend on $C$ and is thus always the same.



One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points $C$ all seem to lie on a smaller circle contained in the original circle $o$.



One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale $r_1/r_2$ where $r_1$ is the radius of the larger circle and $r_2$ is the radius of the smaller circle(I am really not sure about this).



I am not sure what to say about the case where $c$ lies on the small arc and am not sure where to continue with the problem.



Any help is appreciated.










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    Question: Let $A$ and $B$ be distinct points of a circle $o$. What is the set of possible centroids of triangles $ABC$ with $Cin o$?



    Here is what I have:
    The angle at $C$ will always be the same as it is always subtended by the same arc as $A$ and $B$ are fixed.



    There are 2 cases: Either $C$ lies on the small arc of $AB$ or $C$ lies on the big arc of $AB$.



    In the case where $C$ lies on the large arc, by looking at the possible positions of $C$ one can observe that at some point $C$ and $A$ are on the same diameter and at another point $C$ and $B$ are on the same diameter. Also, it is worth mentioning that the midpoint at which $c$ intersects on the chord $AB$ does not depend on $C$ and is thus always the same.



    One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points $C$ all seem to lie on a smaller circle contained in the original circle $o$.



    One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale $r_1/r_2$ where $r_1$ is the radius of the larger circle and $r_2$ is the radius of the smaller circle(I am really not sure about this).



    I am not sure what to say about the case where $c$ lies on the small arc and am not sure where to continue with the problem.



    Any help is appreciated.










    share|cite|improve this question









    New contributor




    rico is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      Question: Let $A$ and $B$ be distinct points of a circle $o$. What is the set of possible centroids of triangles $ABC$ with $Cin o$?



      Here is what I have:
      The angle at $C$ will always be the same as it is always subtended by the same arc as $A$ and $B$ are fixed.



      There are 2 cases: Either $C$ lies on the small arc of $AB$ or $C$ lies on the big arc of $AB$.



      In the case where $C$ lies on the large arc, by looking at the possible positions of $C$ one can observe that at some point $C$ and $A$ are on the same diameter and at another point $C$ and $B$ are on the same diameter. Also, it is worth mentioning that the midpoint at which $c$ intersects on the chord $AB$ does not depend on $C$ and is thus always the same.



      One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points $C$ all seem to lie on a smaller circle contained in the original circle $o$.



      One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale $r_1/r_2$ where $r_1$ is the radius of the larger circle and $r_2$ is the radius of the smaller circle(I am really not sure about this).



      I am not sure what to say about the case where $c$ lies on the small arc and am not sure where to continue with the problem.



      Any help is appreciated.










      share|cite|improve this question









      New contributor




      rico is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Question: Let $A$ and $B$ be distinct points of a circle $o$. What is the set of possible centroids of triangles $ABC$ with $Cin o$?



      Here is what I have:
      The angle at $C$ will always be the same as it is always subtended by the same arc as $A$ and $B$ are fixed.



      There are 2 cases: Either $C$ lies on the small arc of $AB$ or $C$ lies on the big arc of $AB$.



      In the case where $C$ lies on the large arc, by looking at the possible positions of $C$ one can observe that at some point $C$ and $A$ are on the same diameter and at another point $C$ and $B$ are on the same diameter. Also, it is worth mentioning that the midpoint at which $c$ intersects on the chord $AB$ does not depend on $C$ and is thus always the same.



      One can observe, by determining various points that satisfy the criteria in a drawing, that the possible points $C$ all seem to lie on a smaller circle contained in the original circle $o$.



      One can then guess that the center of this smaller circle is a possible center of homothethy mapping the smaller circle to the larger circle with scale $r_1/r_2$ where $r_1$ is the radius of the larger circle and $r_2$ is the radius of the smaller circle(I am really not sure about this).



      I am not sure what to say about the case where $c$ lies on the small arc and am not sure where to continue with the problem.



      Any help is appreciated.







      geometry euclidean-geometry






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      edited 11 hours ago









      Asaf Karagila

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      asked 18 hours ago









      rico

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      495




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      Check out our Code of Conduct.






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          2 Answers
          2






          active

          oldest

          votes

















          up vote
          6
          down vote



          accepted










          [This is just a translation of Carl Schildkraut's answer into synthetic language.]



          Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.






          share|cite|improve this answer




























            up vote
            4
            down vote













            Here's a moderately obnoxious idea:



            If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



            There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.






            share|cite|improve this answer





















            • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
              – rico
              18 hours ago










            • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
              – Eric Wofsey
              18 hours ago











            Your Answer





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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            6
            down vote



            accepted










            [This is just a translation of Carl Schildkraut's answer into synthetic language.]



            Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.






            share|cite|improve this answer

























              up vote
              6
              down vote



              accepted










              [This is just a translation of Carl Schildkraut's answer into synthetic language.]



              Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.






              share|cite|improve this answer























                up vote
                6
                down vote



                accepted







                up vote
                6
                down vote



                accepted






                [This is just a translation of Carl Schildkraut's answer into synthetic language.]



                Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.






                share|cite|improve this answer












                [This is just a translation of Carl Schildkraut's answer into synthetic language.]



                Note that the centroid of $ABC$ can be constructed by taking the midpoint $M$ of $AB$ and then taking the point $G$ which is $1/3$ of the way along $MC$ (closer to $M$). This means exactly that it is the image of $C$ under the homothety $T$ with center $M$ and scale factor $1/3$. Since homotheties preserve circles and their centers, this homothety maps a circle with center $D$ and radius $r$ to a circle with center $T(D)$ and radius $r/3$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered 18 hours ago









                Eric Wofsey

                177k12202328




                177k12202328






















                    up vote
                    4
                    down vote













                    Here's a moderately obnoxious idea:



                    If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



                    There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.






                    share|cite|improve this answer





















                    • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                      – rico
                      18 hours ago










                    • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                      – Eric Wofsey
                      18 hours ago















                    up vote
                    4
                    down vote













                    Here's a moderately obnoxious idea:



                    If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



                    There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.






                    share|cite|improve this answer





















                    • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                      – rico
                      18 hours ago










                    • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                      – Eric Wofsey
                      18 hours ago













                    up vote
                    4
                    down vote










                    up vote
                    4
                    down vote









                    Here's a moderately obnoxious idea:



                    If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



                    There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.






                    share|cite|improve this answer












                    Here's a moderately obnoxious idea:



                    If you use complex numbers and set your circle to be the unit circle, then the centroid of the triangle determined by $a,b,c$ is simply $frac{a+b+c}{3}$. Thus, the locus of possible centroids, as $A$ and $B$ are fixed and $C$ varies, is simply the circle with radius $frac{1}{3}$ centered at $frac{a+b}{3}$ (I think you need to get rid of two of the points because $Cneq A,B$, but oh well).



                    There should be a geometric interpretation of this idea as well, if you essentially try to phrase everything with homotheties.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered 18 hours ago









                    Carl Schildkraut

                    10.9k11439




                    10.9k11439












                    • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                      – rico
                      18 hours ago










                    • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                      – Eric Wofsey
                      18 hours ago


















                    • Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                      – rico
                      18 hours ago










                    • In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                      – Eric Wofsey
                      18 hours ago
















                    Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                    – rico
                    18 hours ago




                    Wow that is really interesting way of thinking about it, thanks. Unfortunately, I am trying to find a solution using homotheties.
                    – rico
                    18 hours ago












                    In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                    – Eric Wofsey
                    18 hours ago




                    In terms of homotheties, the transformation $T:cmapsto frac{a+b+c}{3}$ is a homothety with center $frac{a+b}{2}$ and scale factor $1/3$. So, it maps a circle of radius $r$ and center $d$ to a circle of radius $r/3$ and center $T(d)$.
                    – Eric Wofsey
                    18 hours ago










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