solve the equation $uu'+2e^u-t+e^ut=0$, $u(0)=1$
1
$begingroup$
I am trying to solve the equation, $uu'+2e^u-t+e^ut=0$, with $u(0)=1$.
This problem is giving me trouble because I don't know how to get the equation into the form of $dy/dx=g(x)f(y)$.
calculus
edited Dec 9 '18 at 4:13
Key Flex
7,84461233
asked Dec 9 '18 at 4:10
Levi BentleyLevi Bentley
61
$endgroup$
add a comment |
1
$begingroup$
I am trying to solve the equation, $uu'+2e^u-t+e^ut=0$, with $u(0)=1$.
This problem is giving me trouble because I don't know how to get the equation into the form of $dy/dx=g(x)f(y)$.
calculus
edited Dec 9 '18 at 4:13
Key Flex
7,84461233
asked Dec 9 '18 at 4:10
Levi BentleyLevi Bentley
61
$endgroup$
$begingroup$
Doesn't u' = du/dt?
$endgroup$
– William Elliot
Dec 9 '18 at 10:21
$begingroup$
I think so, but I'm at a loss as to what to do after that.
$endgroup$
– Levi Bentley
Dec 9 '18 at 19:36
add a comment |
1
1
1
2
$begingroup$
I am trying to solve the equation, $uu'+2e^u-t+e^ut=0$, with $u(0)=1$.
This problem is giving me trouble because I don't know how to get the equation into the form of $dy/dx=g(x)f(y)$.
calculus
edited Dec 9 '18 at 4:13
Key Flex
7,84461233
asked Dec 9 '18 at 4:10
Levi BentleyLevi Bentley
61
$endgroup$
I am trying to solve the equation, $uu'+2e^u-t+e^ut=0$, with $u(0)=1$.
This problem is giving me trouble because I don't know how to get the equation into the form of $dy/dx=g(x)f(y)$.
calculus
calculus
edited Dec 9 '18 at 4:13
Key Flex
7,84461233
asked Dec 9 '18 at 4:10
Levi BentleyLevi Bentley
61
edited Dec 9 '18 at 4:13
Key Flex
7,84461233
asked Dec 9 '18 at 4:10
Levi BentleyLevi Bentley
61
edited Dec 9 '18 at 4:13
Key Flex
7,84461233
edited Dec 9 '18 at 4:13
Key Flex
7,84461233
edited Dec 9 '18 at 4:13
Key Flex
7,84461233
7,84461233
asked Dec 9 '18 at 4:10
Levi BentleyLevi Bentley
61
asked Dec 9 '18 at 4:10
Levi BentleyLevi Bentley
61
asked Dec 9 '18 at 4:10
Levi BentleyLevi Bentley
61
61
$begingroup$
Doesn't u' = du/dt?
$endgroup$
– William Elliot
Dec 9 '18 at 10:21
$begingroup$
I think so, but I'm at a loss as to what to do after that.
$endgroup$
– Levi Bentley
Dec 9 '18 at 19:36
add a comment |
$begingroup$
Doesn't u' = du/dt?
$endgroup$
– William Elliot
Dec 9 '18 at 10:21
$begingroup$
I think so, but I'm at a loss as to what to do after that.
$endgroup$
– Levi Bentley
Dec 9 '18 at 19:36
$begingroup$
Doesn't u' = du/dt?
$endgroup$
– William Elliot
Dec 9 '18 at 10:21
$begingroup$
Doesn't u' = du/dt?
$endgroup$
– William Elliot
Dec 9 '18 at 10:21
$begingroup$
I think so, but I'm at a loss as to what to do after that.
$endgroup$
– Levi Bentley
Dec 9 '18 at 19:36
$begingroup$
I think so, but I'm at a loss as to what to do after that.
$endgroup$
– Levi Bentley
Dec 9 '18 at 19:36
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3031992%2fsolve-the-equation-uu2eu-teut-0-u0-1%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
draft saved
draft discarded
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3031992%2fsolve-the-equation-uu2eu-teut-0-u0-1%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Doesn't u' = du/dt?
$endgroup$
– William Elliot
Dec 9 '18 at 10:21
$begingroup$
I think so, but I'm at a loss as to what to do after that.
$endgroup$
– Levi Bentley
Dec 9 '18 at 19:36