Are the manifolds $N=(mathbb{R},text{Id})$ and $M=(mathbb{R},xmapsto x^{frac{1}{3}})$ diffeomorphic?
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Are the manifolds $N=(mathbb{R},text{Id})$ and $M=(mathbb{R},xmapsto x^{frac{1}{3}})$ diffeomorphic?
I have already shown that $text{Id}: N rightarrow M$ is a homeomorphism but not a diffeomorphism.
differential-geometry smooth-manifolds diffeomorphism
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$begingroup$
Are the manifolds $N=(mathbb{R},text{Id})$ and $M=(mathbb{R},xmapsto x^{frac{1}{3}})$ diffeomorphic?
I have already shown that $text{Id}: N rightarrow M$ is a homeomorphism but not a diffeomorphism.
differential-geometry smooth-manifolds diffeomorphism
$endgroup$
add a comment |
$begingroup$
Are the manifolds $N=(mathbb{R},text{Id})$ and $M=(mathbb{R},xmapsto x^{frac{1}{3}})$ diffeomorphic?
I have already shown that $text{Id}: N rightarrow M$ is a homeomorphism but not a diffeomorphism.
differential-geometry smooth-manifolds diffeomorphism
$endgroup$
Are the manifolds $N=(mathbb{R},text{Id})$ and $M=(mathbb{R},xmapsto x^{frac{1}{3}})$ diffeomorphic?
I have already shown that $text{Id}: N rightarrow M$ is a homeomorphism but not a diffeomorphism.
differential-geometry smooth-manifolds diffeomorphism
differential-geometry smooth-manifolds diffeomorphism
asked Dec 20 '18 at 12:14
Jens WagemakerJens Wagemaker
550312
550312
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Yes. Try to show that $F:Nto M$ given by $F(x)=x^3$ is a diffeomorphism.
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$begingroup$
Yes, they are diffeomorphic. Consider the map$$begin{array}{ccc}N&longrightarrow&M\x&mapsto&x^3.end{array}$$It's a diffeomorphism.
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2 Answers
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2 Answers
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$begingroup$
Yes. Try to show that $F:Nto M$ given by $F(x)=x^3$ is a diffeomorphism.
$endgroup$
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$begingroup$
Yes. Try to show that $F:Nto M$ given by $F(x)=x^3$ is a diffeomorphism.
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add a comment |
$begingroup$
Yes. Try to show that $F:Nto M$ given by $F(x)=x^3$ is a diffeomorphism.
$endgroup$
Yes. Try to show that $F:Nto M$ given by $F(x)=x^3$ is a diffeomorphism.
answered Dec 20 '18 at 12:18
positrón0802positrón0802
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$begingroup$
Yes, they are diffeomorphic. Consider the map$$begin{array}{ccc}N&longrightarrow&M\x&mapsto&x^3.end{array}$$It's a diffeomorphism.
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$begingroup$
Yes, they are diffeomorphic. Consider the map$$begin{array}{ccc}N&longrightarrow&M\x&mapsto&x^3.end{array}$$It's a diffeomorphism.
$endgroup$
add a comment |
$begingroup$
Yes, they are diffeomorphic. Consider the map$$begin{array}{ccc}N&longrightarrow&M\x&mapsto&x^3.end{array}$$It's a diffeomorphism.
$endgroup$
Yes, they are diffeomorphic. Consider the map$$begin{array}{ccc}N&longrightarrow&M\x&mapsto&x^3.end{array}$$It's a diffeomorphism.
answered Dec 20 '18 at 12:17
José Carlos SantosJosé Carlos Santos
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