Vector Calculus_line integral [closed]
up vote
0
down vote
favorite
The plane $2x+2y+z=2 $ cuts the $x,y$ and $z$ axis at $P(1,0,0), Q(0,1,0)$ and $R(0,0,2) $ respectively. Path $C$ is defined as a straight line segments from $P$ to $Q$ to $R$ and back to $P$. Find the line integral $$int_Cmathbf{F}cdotmathrm{d}mathbf{r},$$ where $mathbf{F}(x,y,z)=x^{2}y,mathbf{i} + cos y,mathbf{j} + 5e^{3z},mathbf{k}$.
line-integrals
asked Nov 18 at 14:21
Megajs
42
closed as off-topic by B. Goddard, Paul Frost, T. Bongers, José Carlos Santos, Cesareo Nov 19 at 0:52
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – B. Goddard, Paul Frost, T. Bongers, José Carlos Santos, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
up vote
0
down vote
favorite
The plane $2x+2y+z=2 $ cuts the $x,y$ and $z$ axis at $P(1,0,0), Q(0,1,0)$ and $R(0,0,2) $ respectively. Path $C$ is defined as a straight line segments from $P$ to $Q$ to $R$ and back to $P$. Find the line integral $$int_Cmathbf{F}cdotmathrm{d}mathbf{r},$$ where $mathbf{F}(x,y,z)=x^{2}y,mathbf{i} + cos y,mathbf{j} + 5e^{3z},mathbf{k}$.
line-integrals
asked Nov 18 at 14:21
Megajs
42
closed as off-topic by B. Goddard, Paul Frost, T. Bongers, José Carlos Santos, Cesareo Nov 19 at 0:52
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – B. Goddard, Paul Frost, T. Bongers, José Carlos Santos, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
You should really show what you've tried so far. This isn't a "do your homework for free" site.
– B. Goddard
Nov 18 at 14:37
I have tried, please refer to this link l.facebook.com/….. i was wondering is there another shorter way to do this question?
– Megajs
Nov 18 at 15:17
Have you learned Stokes' Theorem? This is a closed curve, so Stokes' Theorem should apply.
– Nick
Nov 18 at 15:38
There is a typo, the $mathbf i$ component is $x^2 y$, not $x^{2 y}$. Your calculations are correct. You can obtain the same result as $$int_0^1 int_0^{1 - x} (nabla times mathbf F) cdot nabla (2 x + 2 y + z - 2) ,dy dx.$$
– Maxim
Nov 19 at 13:27
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
The plane $2x+2y+z=2 $ cuts the $x,y$ and $z$ axis at $P(1,0,0), Q(0,1,0)$ and $R(0,0,2) $ respectively. Path $C$ is defined as a straight line segments from $P$ to $Q$ to $R$ and back to $P$. Find the line integral $$int_Cmathbf{F}cdotmathrm{d}mathbf{r},$$ where $mathbf{F}(x,y,z)=x^{2}y,mathbf{i} + cos y,mathbf{j} + 5e^{3z},mathbf{k}$.
line-integrals
asked Nov 18 at 14:21
Megajs
42
The plane $2x+2y+z=2 $ cuts the $x,y$ and $z$ axis at $P(1,0,0), Q(0,1,0)$ and $R(0,0,2) $ respectively. Path $C$ is defined as a straight line segments from $P$ to $Q$ to $R$ and back to $P$. Find the line integral $$int_Cmathbf{F}cdotmathrm{d}mathbf{r},$$ where $mathbf{F}(x,y,z)=x^{2}y,mathbf{i} + cos y,mathbf{j} + 5e^{3z},mathbf{k}$.
line-integrals
line-integrals
asked Nov 18 at 14:21
Megajs
42
asked Nov 18 at 14:21
Megajs
42
edited Nov 20 at 5:21
asked Nov 18 at 14:21
Megajs
42
asked Nov 18 at 14:21
Megajs
42
asked Nov 18 at 14:21
Megajs
42
42
closed as off-topic by B. Goddard, Paul Frost, T. Bongers, José Carlos Santos, Cesareo Nov 19 at 0:52
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – B. Goddard, Paul Frost, T. Bongers, José Carlos Santos, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by B. Goddard, Paul Frost, T. Bongers, José Carlos Santos, Cesareo Nov 19 at 0:52
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – B. Goddard, Paul Frost, T. Bongers, José Carlos Santos, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
You should really show what you've tried so far. This isn't a "do your homework for free" site.
– B. Goddard
Nov 18 at 14:37
I have tried, please refer to this link l.facebook.com/….. i was wondering is there another shorter way to do this question?
– Megajs
Nov 18 at 15:17
Have you learned Stokes' Theorem? This is a closed curve, so Stokes' Theorem should apply.
– Nick
Nov 18 at 15:38
There is a typo, the $mathbf i$ component is $x^2 y$, not $x^{2 y}$. Your calculations are correct. You can obtain the same result as $$int_0^1 int_0^{1 - x} (nabla times mathbf F) cdot nabla (2 x + 2 y + z - 2) ,dy dx.$$
– Maxim
Nov 19 at 13:27
add a comment |
You should really show what you've tried so far. This isn't a "do your homework for free" site.
– B. Goddard
Nov 18 at 14:37
I have tried, please refer to this link l.facebook.com/….. i was wondering is there another shorter way to do this question?
– Megajs
Nov 18 at 15:17
Have you learned Stokes' Theorem? This is a closed curve, so Stokes' Theorem should apply.
– Nick
Nov 18 at 15:38
There is a typo, the $mathbf i$ component is $x^2 y$, not $x^{2 y}$. Your calculations are correct. You can obtain the same result as $$int_0^1 int_0^{1 - x} (nabla times mathbf F) cdot nabla (2 x + 2 y + z - 2) ,dy dx.$$
– Maxim
Nov 19 at 13:27
You should really show what you've tried so far. This isn't a "do your homework for free" site.
– B. Goddard
Nov 18 at 14:37
You should really show what you've tried so far. This isn't a "do your homework for free" site.
– B. Goddard
Nov 18 at 14:37
I have tried, please refer to this link l.facebook.com/….. i was wondering is there another shorter way to do this question?
– Megajs
Nov 18 at 15:17
I have tried, please refer to this link l.facebook.com/….. i was wondering is there another shorter way to do this question?
– Megajs
Nov 18 at 15:17
Have you learned Stokes' Theorem? This is a closed curve, so Stokes' Theorem should apply.
– Nick
Nov 18 at 15:38
Have you learned Stokes' Theorem? This is a closed curve, so Stokes' Theorem should apply.
– Nick
Nov 18 at 15:38
There is a typo, the $mathbf i$ component is $x^2 y$, not $x^{2 y}$. Your calculations are correct. You can obtain the same result as $$int_0^1 int_0^{1 - x} (nabla times mathbf F) cdot nabla (2 x + 2 y + z - 2) ,dy dx.$$
– Maxim
Nov 19 at 13:27
There is a typo, the $mathbf i$ component is $x^2 y$, not $x^{2 y}$. Your calculations are correct. You can obtain the same result as $$int_0^1 int_0^{1 - x} (nabla times mathbf F) cdot nabla (2 x + 2 y + z - 2) ,dy dx.$$
– Maxim
Nov 19 at 13:27
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should really show what you've tried so far. This isn't a "do your homework for free" site.
– B. Goddard
Nov 18 at 14:37
I have tried, please refer to this link l.facebook.com/….. i was wondering is there another shorter way to do this question?
– Megajs
Nov 18 at 15:17
Have you learned Stokes' Theorem? This is a closed curve, so Stokes' Theorem should apply.
– Nick
Nov 18 at 15:38
There is a typo, the $mathbf i$ component is $x^2 y$, not $x^{2 y}$. Your calculations are correct. You can obtain the same result as $$int_0^1 int_0^{1 - x} (nabla times mathbf F) cdot nabla (2 x + 2 y + z - 2) ,dy dx.$$
– Maxim
Nov 19 at 13:27