Normal distribution, find k for which P(-k≤Z≤k)=0.7850
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Find k such P(-k≤Z≤k)=0.7850
Help me with this problem, this is really getting me a headache, I tried doing it by tables (Because it's better), but it is really annoying and expense to doing it value by value, can someone explain to me how to do it in a logical form? please help me.
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Find k such P(-k≤Z≤k)=0.7850
Help me with this problem, this is really getting me a headache, I tried doing it by tables (Because it's better), but it is really annoying and expense to doing it value by value, can someone explain to me how to do it in a logical form? please help me.
statistics
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Find k such P(-k≤Z≤k)=0.7850
Help me with this problem, this is really getting me a headache, I tried doing it by tables (Because it's better), but it is really annoying and expense to doing it value by value, can someone explain to me how to do it in a logical form? please help me.
statistics
Find k such P(-k≤Z≤k)=0.7850
Help me with this problem, this is really getting me a headache, I tried doing it by tables (Because it's better), but it is really annoying and expense to doing it value by value, can someone explain to me how to do it in a logical form? please help me.
statistics
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asked Nov 21 at 2:32
Andrés HK
133
133
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1 Answer
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Hint
If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Hint
If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$
add a comment |
up vote
0
down vote
Hint
If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$
add a comment |
up vote
0
down vote
up vote
0
down vote
Hint
If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$
Hint
If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$
answered Nov 21 at 2:35
WaveX
2,4052721
2,4052721
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