Normal distribution, find k for which P(-k≤Z≤k)=0.7850











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Find k such P(-k≤Z≤k)=0.7850
Help me with this problem, this is really getting me a headache, I tried doing it by tables (Because it's better), but it is really annoying and expense to doing it value by value, can someone explain to me how to do it in a logical form? please help me.










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    Find k such P(-k≤Z≤k)=0.7850
    Help me with this problem, this is really getting me a headache, I tried doing it by tables (Because it's better), but it is really annoying and expense to doing it value by value, can someone explain to me how to do it in a logical form? please help me.










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      up vote
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      down vote

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      Find k such P(-k≤Z≤k)=0.7850
      Help me with this problem, this is really getting me a headache, I tried doing it by tables (Because it's better), but it is really annoying and expense to doing it value by value, can someone explain to me how to do it in a logical form? please help me.










      share|cite|improve this question













      Find k such P(-k≤Z≤k)=0.7850
      Help me with this problem, this is really getting me a headache, I tried doing it by tables (Because it's better), but it is really annoying and expense to doing it value by value, can someone explain to me how to do it in a logical form? please help me.







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      asked Nov 21 at 2:32









      Andrés HK

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          Hint



          If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$






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            1 Answer
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            1 Answer
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            oldest

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            active

            oldest

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            up vote
            0
            down vote













            Hint



            If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$






            share|cite|improve this answer

























              up vote
              0
              down vote













              Hint



              If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$






              share|cite|improve this answer























                up vote
                0
                down vote










                up vote
                0
                down vote









                Hint



                If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$






                share|cite|improve this answer












                Hint



                If $P(-k < Z < k) = 0.7850$, then by symmetry, $P(0 < Z < k) = 0.3925$







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 21 at 2:35









                WaveX

                2,4052721




                2,4052721






























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