Q: LeetCode 189. Rotate Array
I have a working solution for this problem that was accepted in LeetCode:
"Given an array, rotate the array to the right by k steps, where k is non-negative."
function rotate(nums, k) {
for (let i = 1; i <= k; i += 1) {
const poppedNum = nums.pop();
nums.unshift(poppedNum);
}
return nums;
}
// rotate([1, 2, 3, 4, 5, 6, 7], 3) -> [5, 6, 7, 1, 2, 3, 4]
Questions:
Would the time complexity be O(k) and space complexity be O(1)?
Is there a better way to solve this? The question asked to rotate the elements in-place if possible, but I am not sure how to accomplish this at the moment.
javascript algorithm interview-questions
asked 34 mins ago
davidatthepark
101
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I have a working solution for this problem that was accepted in LeetCode:
"Given an array, rotate the array to the right by k steps, where k is non-negative."
function rotate(nums, k) {
for (let i = 1; i <= k; i += 1) {
const poppedNum = nums.pop();
nums.unshift(poppedNum);
}
return nums;
}
// rotate([1, 2, 3, 4, 5, 6, 7], 3) -> [5, 6, 7, 1, 2, 3, 4]
Questions:
Would the time complexity be O(k) and space complexity be O(1)?
Is there a better way to solve this? The question asked to rotate the elements in-place if possible, but I am not sure how to accomplish this at the moment.
javascript algorithm interview-questions
asked 34 mins ago
davidatthepark
101
New contributor
davidatthepark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have a working solution for this problem that was accepted in LeetCode:
"Given an array, rotate the array to the right by k steps, where k is non-negative."
function rotate(nums, k) {
for (let i = 1; i <= k; i += 1) {
const poppedNum = nums.pop();
nums.unshift(poppedNum);
}
return nums;
}
// rotate([1, 2, 3, 4, 5, 6, 7], 3) -> [5, 6, 7, 1, 2, 3, 4]
Questions:
Would the time complexity be O(k) and space complexity be O(1)?
Is there a better way to solve this? The question asked to rotate the elements in-place if possible, but I am not sure how to accomplish this at the moment.
javascript algorithm interview-questions
asked 34 mins ago
davidatthepark
101
New contributor
davidatthepark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have a working solution for this problem that was accepted in LeetCode:
"Given an array, rotate the array to the right by k steps, where k is non-negative."
function rotate(nums, k) {
for (let i = 1; i <= k; i += 1) {
const poppedNum = nums.pop();
nums.unshift(poppedNum);
}
return nums;
}
// rotate([1, 2, 3, 4, 5, 6, 7], 3) -> [5, 6, 7, 1, 2, 3, 4]
Questions:
Would the time complexity be O(k) and space complexity be O(1)?
Is there a better way to solve this? The question asked to rotate the elements in-place if possible, but I am not sure how to accomplish this at the moment.
javascript algorithm interview-questions
javascript algorithm interview-questions
asked 34 mins ago
davidatthepark
101
New contributor
davidatthepark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 34 mins ago
davidatthepark
101
New contributor
davidatthepark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 34 mins ago
davidatthepark
101
New contributor
davidatthepark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 34 mins ago
davidatthepark
101
asked 34 mins ago
davidatthepark
101
101
New contributor
davidatthepark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
davidatthepark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
davidatthepark is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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