Compare elements in 2D two non-identical arrays [on hold]

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I want to compare each elements of List2 with first two elements of List1 and if matched return the 3rd elements from List1



List1 = np.array([[1,9,4],[1,6,2],[1,2,6],[1,7,3],[1,3,6],[1,8,2],[1,5,1],[1,10,2],[1,4]]);
List2 = np.array([[1,2],[1,3],[1,4],[1,5]]);



Expected result:



step-1: compare [1,2] from List1 with List2



step-2: if matched return the 3rd element of List1 for example 6 from [1,2,6]



any solution is highly appreciated. Thanks






python-3.x







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put on hold as off-topic by 200_success, Heslacher, πάντα ῥεῖ, Sᴀᴍ Onᴇᴌᴀ, alecxe 13 hours ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – 200_success, Heslacher, πάντα ῥεῖ, Sᴀᴍ Onᴇᴌᴀ, alecxe

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Welcome to Code Review. Unfortunately your question is off-topic as of now, as the code to be reviewed must be present in the question. Please add the code you want reviewed in your question. Thanks!
    – Heslacher
    15 hours ago















up vote
-3
down vote

favorite












I want to compare each elements of List2 with first two elements of List1 and if matched return the 3rd elements from List1



List1 = np.array([[1,9,4],[1,6,2],[1,2,6],[1,7,3],[1,3,6],[1,8,2],[1,5,1],[1,10,2],[1,4]]);
List2 = np.array([[1,2],[1,3],[1,4],[1,5]]);



Expected result:



step-1: compare [1,2] from List1 with List2



step-2: if matched return the 3rd element of List1 for example 6 from [1,2,6]



any solution is highly appreciated. Thanks






python-3.x







share|improve this question







New contributor




John is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











put on hold as off-topic by 200_success, Heslacher, πάντα ῥεῖ, Sᴀᴍ Onᴇᴌᴀ, alecxe 13 hours ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – 200_success, Heslacher, πάντα ῥεῖ, Sᴀᴍ Onᴇᴌᴀ, alecxe

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Welcome to Code Review. Unfortunately your question is off-topic as of now, as the code to be reviewed must be present in the question. Please add the code you want reviewed in your question. Thanks!
    – Heslacher
    15 hours ago













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











I want to compare each elements of List2 with first two elements of List1 and if matched return the 3rd elements from List1



List1 = np.array([[1,9,4],[1,6,2],[1,2,6],[1,7,3],[1,3,6],[1,8,2],[1,5,1],[1,10,2],[1,4]]);
List2 = np.array([[1,2],[1,3],[1,4],[1,5]]);



Expected result:



step-1: compare [1,2] from List1 with List2



step-2: if matched return the 3rd element of List1 for example 6 from [1,2,6]



any solution is highly appreciated. Thanks






python-3.x







share|improve this question







New contributor




John is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I want to compare each elements of List2 with first two elements of List1 and if matched return the 3rd elements from List1



List1 = np.array([[1,9,4],[1,6,2],[1,2,6],[1,7,3],[1,3,6],[1,8,2],[1,5,1],[1,10,2],[1,4]]);
List2 = np.array([[1,2],[1,3],[1,4],[1,5]]);



Expected result:



step-1: compare [1,2] from List1 with List2



step-2: if matched return the 3rd element of List1 for example 6 from [1,2,6]



any solution is highly appreciated. Thanks






python-3.x




python-3.x






share|improve this question







New contributor




John is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




John is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




John is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 15 hours ago









John

1




1




New contributor




John is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





John is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






John is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




put on hold as off-topic by 200_success, Heslacher, πάντα ῥεῖ, Sᴀᴍ Onᴇᴌᴀ, alecxe 13 hours ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – 200_success, Heslacher, πάντα ῥεῖ, Sᴀᴍ Onᴇᴌᴀ, alecxe

If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by 200_success, Heslacher, πάντα ῥεῖ, Sᴀᴍ Onᴇᴌᴀ, alecxe 13 hours ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – 200_success, Heslacher, πάντα ῥεῖ, Sᴀᴍ Onᴇᴌᴀ, alecxe

If this question can be reworded to fit the rules in the help center, please edit the question.












  • Welcome to Code Review. Unfortunately your question is off-topic as of now, as the code to be reviewed must be present in the question. Please add the code you want reviewed in your question. Thanks!
    – Heslacher
    15 hours ago


















  • Welcome to Code Review. Unfortunately your question is off-topic as of now, as the code to be reviewed must be present in the question. Please add the code you want reviewed in your question. Thanks!
    – Heslacher
    15 hours ago
















Welcome to Code Review. Unfortunately your question is off-topic as of now, as the code to be reviewed must be present in the question. Please add the code you want reviewed in your question. Thanks!
– Heslacher
15 hours ago




Welcome to Code Review. Unfortunately your question is off-topic as of now, as the code to be reviewed must be present in the question. Please add the code you want reviewed in your question. Thanks!
– Heslacher
15 hours ago















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