Every element $g$ of $G$ has a symmetric neighborhood $V$ of $e$ such that $VgV^{-1}subset U$












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Let $G$ be a topological group and $gin G$ , $U$ is a neighborhood of $g$ . Prove that there exists a symmetric neighborhood $V$ of $e$ such that $VgV^{-1}subset U$.



If $g=e$, l have proved it. But if $gneq e$ , l have no idea. So how to prove ?










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  • Welcome to MSE. What is $U$?
    – José Carlos Santos
    Nov 27 '18 at 9:48










  • $U$ is any neighborhood of $g$.
    – water graph
    Nov 27 '18 at 9:51
















0














Let $G$ be a topological group and $gin G$ , $U$ is a neighborhood of $g$ . Prove that there exists a symmetric neighborhood $V$ of $e$ such that $VgV^{-1}subset U$.



If $g=e$, l have proved it. But if $gneq e$ , l have no idea. So how to prove ?










share|cite|improve this question






















  • Welcome to MSE. What is $U$?
    – José Carlos Santos
    Nov 27 '18 at 9:48










  • $U$ is any neighborhood of $g$.
    – water graph
    Nov 27 '18 at 9:51














0












0








0







Let $G$ be a topological group and $gin G$ , $U$ is a neighborhood of $g$ . Prove that there exists a symmetric neighborhood $V$ of $e$ such that $VgV^{-1}subset U$.



If $g=e$, l have proved it. But if $gneq e$ , l have no idea. So how to prove ?










share|cite|improve this question













Let $G$ be a topological group and $gin G$ , $U$ is a neighborhood of $g$ . Prove that there exists a symmetric neighborhood $V$ of $e$ such that $VgV^{-1}subset U$.



If $g=e$, l have proved it. But if $gneq e$ , l have no idea. So how to prove ?







topological-groups






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asked Nov 27 '18 at 9:44









water graph

232




232












  • Welcome to MSE. What is $U$?
    – José Carlos Santos
    Nov 27 '18 at 9:48










  • $U$ is any neighborhood of $g$.
    – water graph
    Nov 27 '18 at 9:51


















  • Welcome to MSE. What is $U$?
    – José Carlos Santos
    Nov 27 '18 at 9:48










  • $U$ is any neighborhood of $g$.
    – water graph
    Nov 27 '18 at 9:51
















Welcome to MSE. What is $U$?
– José Carlos Santos
Nov 27 '18 at 9:48




Welcome to MSE. What is $U$?
– José Carlos Santos
Nov 27 '18 at 9:48












$U$ is any neighborhood of $g$.
– water graph
Nov 27 '18 at 9:51




$U$ is any neighborhood of $g$.
– water graph
Nov 27 '18 at 9:51










1 Answer
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Let $f: G to G$ be $f(x) = xgx^{-1}$. Then $f(e) = g$. So by continuity, we can find some open neighborhood $V$ of $e$ for which $f(V) subset U$, i.e. for which $VgV^{-1} subset U$. To make $V$ symmetric, we can just replace $V$ with $Vcap V^{-1}$, which is a subset of $V$ (so that $VgV^{-1} subset U$ still holds).






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    Let $f: G to G$ be $f(x) = xgx^{-1}$. Then $f(e) = g$. So by continuity, we can find some open neighborhood $V$ of $e$ for which $f(V) subset U$, i.e. for which $VgV^{-1} subset U$. To make $V$ symmetric, we can just replace $V$ with $Vcap V^{-1}$, which is a subset of $V$ (so that $VgV^{-1} subset U$ still holds).






    share|cite|improve this answer


























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      Let $f: G to G$ be $f(x) = xgx^{-1}$. Then $f(e) = g$. So by continuity, we can find some open neighborhood $V$ of $e$ for which $f(V) subset U$, i.e. for which $VgV^{-1} subset U$. To make $V$ symmetric, we can just replace $V$ with $Vcap V^{-1}$, which is a subset of $V$ (so that $VgV^{-1} subset U$ still holds).






      share|cite|improve this answer
























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        Let $f: G to G$ be $f(x) = xgx^{-1}$. Then $f(e) = g$. So by continuity, we can find some open neighborhood $V$ of $e$ for which $f(V) subset U$, i.e. for which $VgV^{-1} subset U$. To make $V$ symmetric, we can just replace $V$ with $Vcap V^{-1}$, which is a subset of $V$ (so that $VgV^{-1} subset U$ still holds).






        share|cite|improve this answer












        Let $f: G to G$ be $f(x) = xgx^{-1}$. Then $f(e) = g$. So by continuity, we can find some open neighborhood $V$ of $e$ for which $f(V) subset U$, i.e. for which $VgV^{-1} subset U$. To make $V$ symmetric, we can just replace $V$ with $Vcap V^{-1}$, which is a subset of $V$ (so that $VgV^{-1} subset U$ still holds).







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 27 '18 at 9:51









        mathworker21

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