Is there a general way to simplify such group presentations (Free Abelian Group with Relations)?












2












$begingroup$


If I want to simplify the group presentation (free abelian group with relations)



$$langle a,b,cmid 2a=b=2crangle,$$



I can simplify it as $$langle a,cmid 2a=2crangleconglangle a,a-cmid 2(a-c)ranglecongmathbb{Z}oplusmathbb{Z}_2.$$




How about for more complicated presentations such as
$$langle a,b,cmid 2a=3b=5crangle?$$



How do I simplify it, if possible?



In general, I am interested in simplifying
$$langle a,b,cmid n_1a=n_2b=n_3crangle,$$
where $n_1,n_2,n_3inmathbb{Z}$.




Thanks.










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$endgroup$








  • 2




    $begingroup$
    The general method for this problem is the Smith Normal Form diagonlization algorithm for matrices over the integers.
    $endgroup$
    – Derek Holt
    Feb 5 '18 at 9:46


















2












$begingroup$


If I want to simplify the group presentation (free abelian group with relations)



$$langle a,b,cmid 2a=b=2crangle,$$



I can simplify it as $$langle a,cmid 2a=2crangleconglangle a,a-cmid 2(a-c)ranglecongmathbb{Z}oplusmathbb{Z}_2.$$




How about for more complicated presentations such as
$$langle a,b,cmid 2a=3b=5crangle?$$



How do I simplify it, if possible?



In general, I am interested in simplifying
$$langle a,b,cmid n_1a=n_2b=n_3crangle,$$
where $n_1,n_2,n_3inmathbb{Z}$.




Thanks.










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    The general method for this problem is the Smith Normal Form diagonlization algorithm for matrices over the integers.
    $endgroup$
    – Derek Holt
    Feb 5 '18 at 9:46
















2












2








2


3



$begingroup$


If I want to simplify the group presentation (free abelian group with relations)



$$langle a,b,cmid 2a=b=2crangle,$$



I can simplify it as $$langle a,cmid 2a=2crangleconglangle a,a-cmid 2(a-c)ranglecongmathbb{Z}oplusmathbb{Z}_2.$$




How about for more complicated presentations such as
$$langle a,b,cmid 2a=3b=5crangle?$$



How do I simplify it, if possible?



In general, I am interested in simplifying
$$langle a,b,cmid n_1a=n_2b=n_3crangle,$$
where $n_1,n_2,n_3inmathbb{Z}$.




Thanks.










share|cite|improve this question











$endgroup$




If I want to simplify the group presentation (free abelian group with relations)



$$langle a,b,cmid 2a=b=2crangle,$$



I can simplify it as $$langle a,cmid 2a=2crangleconglangle a,a-cmid 2(a-c)ranglecongmathbb{Z}oplusmathbb{Z}_2.$$




How about for more complicated presentations such as
$$langle a,b,cmid 2a=3b=5crangle?$$



How do I simplify it, if possible?



In general, I am interested in simplifying
$$langle a,b,cmid n_1a=n_2b=n_3crangle,$$
where $n_1,n_2,n_3inmathbb{Z}$.




Thanks.







abstract-algebra group-theory group-presentation combinatorial-group-theory






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 3 '18 at 0:43









Shaun

8,893113681




8,893113681










asked Feb 5 '18 at 7:41









yoyosteinyoyostein

7,91593768




7,91593768








  • 2




    $begingroup$
    The general method for this problem is the Smith Normal Form diagonlization algorithm for matrices over the integers.
    $endgroup$
    – Derek Holt
    Feb 5 '18 at 9:46
















  • 2




    $begingroup$
    The general method for this problem is the Smith Normal Form diagonlization algorithm for matrices over the integers.
    $endgroup$
    – Derek Holt
    Feb 5 '18 at 9:46










2




2




$begingroup$
The general method for this problem is the Smith Normal Form diagonlization algorithm for matrices over the integers.
$endgroup$
– Derek Holt
Feb 5 '18 at 9:46






$begingroup$
The general method for this problem is the Smith Normal Form diagonlization algorithm for matrices over the integers.
$endgroup$
– Derek Holt
Feb 5 '18 at 9:46












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