More questions on quadratic forms over field
$begingroup$
I'm a student, currently studying about quadratic forms over a field $mathbb{R}$ and I have a few questions regarding the topic.
- From a book I currently read, a quadratic form is a real-valued function over a vector space $E$ (i.e. $Q: E longrightarrow mathbb{R}$, please correct me if I'm mistaken) such that there exists a symmetric bilinear form $B: E times E longrightarrow mathbb{R}$ in which the following expression is valid:
begin{align}
Q(x)=B(x,x)
end{align}
$forall x in E$.
My question: given some function $F: E longrightarrow mathbb{R}$. The definition requires the existence of a symmetric bilinear form $G: E times E longrightarrow mathbb{R}$ in which the above expression valid, but how to make sure that we could have such function? For example, if I have a function $F: mathbb{R^3} longrightarrow mathbb{R}$ such that
begin{align}
F(x)= x_1+x_2+x_3
end{align}
with $ x=(x_1,x_2,x_3) in mathbb{R^3}$,
how to check whether $F$ is a quadratic form or not?
- The book also mentioned a regular quadratic space $(E, Q)$, i.e. a vector space $E$ in which it has a quadratic space $Q$ that is nonsingular. What is the definition of nonsingular in terms of function/transformation? And how to connect it to this?
I'm really lost, I know I'm still learning, and I need lots of help. Of course, this is not the last time I'll ask, maybe I'll come again if I find more difficulties but for now, this is all I've got to ask you good people in this community. Thanks! Any help will do!
linear-algebra abstract-algebra quadratic-forms
$endgroup$
add a comment |
$begingroup$
I'm a student, currently studying about quadratic forms over a field $mathbb{R}$ and I have a few questions regarding the topic.
- From a book I currently read, a quadratic form is a real-valued function over a vector space $E$ (i.e. $Q: E longrightarrow mathbb{R}$, please correct me if I'm mistaken) such that there exists a symmetric bilinear form $B: E times E longrightarrow mathbb{R}$ in which the following expression is valid:
begin{align}
Q(x)=B(x,x)
end{align}
$forall x in E$.
My question: given some function $F: E longrightarrow mathbb{R}$. The definition requires the existence of a symmetric bilinear form $G: E times E longrightarrow mathbb{R}$ in which the above expression valid, but how to make sure that we could have such function? For example, if I have a function $F: mathbb{R^3} longrightarrow mathbb{R}$ such that
begin{align}
F(x)= x_1+x_2+x_3
end{align}
with $ x=(x_1,x_2,x_3) in mathbb{R^3}$,
how to check whether $F$ is a quadratic form or not?
- The book also mentioned a regular quadratic space $(E, Q)$, i.e. a vector space $E$ in which it has a quadratic space $Q$ that is nonsingular. What is the definition of nonsingular in terms of function/transformation? And how to connect it to this?
I'm really lost, I know I'm still learning, and I need lots of help. Of course, this is not the last time I'll ask, maybe I'll come again if I find more difficulties but for now, this is all I've got to ask you good people in this community. Thanks! Any help will do!
linear-algebra abstract-algebra quadratic-forms
$endgroup$
$begingroup$
The key word is “quadratic.” When expanded in terms of coordinates, the expression for $Q$ will involve only second-degree terms.
$endgroup$
– amd
Dec 2 '18 at 3:18
$begingroup$
Show that for $E$ finite dimensional with basis $(e_i)$ then $q(sum_i x_i e_i) = sum_i sum_j frac{A_{i,j}+A_{j,i}}{2} x_i x_j$. In matrix form $B(x,y) = x^top frac{A+A^top}{2} y, q(x) = x^top frac{A+A^top}{2} x$
$endgroup$
– reuns
Dec 2 '18 at 4:01
$begingroup$
@amd Ah, I see. Then for any polynomial with degree of two, I could have a quadratic form then?
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:41
$begingroup$
@reuns Could you please explain what $A_{ij}$ suppose to mean? Hehe. Thanks for the help though!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:50
$begingroup$
en.wikipedia.org/wiki/Quadratic_form#Real_quadratic_forms
$endgroup$
– reuns
Dec 2 '18 at 22:16
add a comment |
$begingroup$
I'm a student, currently studying about quadratic forms over a field $mathbb{R}$ and I have a few questions regarding the topic.
- From a book I currently read, a quadratic form is a real-valued function over a vector space $E$ (i.e. $Q: E longrightarrow mathbb{R}$, please correct me if I'm mistaken) such that there exists a symmetric bilinear form $B: E times E longrightarrow mathbb{R}$ in which the following expression is valid:
begin{align}
Q(x)=B(x,x)
end{align}
$forall x in E$.
My question: given some function $F: E longrightarrow mathbb{R}$. The definition requires the existence of a symmetric bilinear form $G: E times E longrightarrow mathbb{R}$ in which the above expression valid, but how to make sure that we could have such function? For example, if I have a function $F: mathbb{R^3} longrightarrow mathbb{R}$ such that
begin{align}
F(x)= x_1+x_2+x_3
end{align}
with $ x=(x_1,x_2,x_3) in mathbb{R^3}$,
how to check whether $F$ is a quadratic form or not?
- The book also mentioned a regular quadratic space $(E, Q)$, i.e. a vector space $E$ in which it has a quadratic space $Q$ that is nonsingular. What is the definition of nonsingular in terms of function/transformation? And how to connect it to this?
I'm really lost, I know I'm still learning, and I need lots of help. Of course, this is not the last time I'll ask, maybe I'll come again if I find more difficulties but for now, this is all I've got to ask you good people in this community. Thanks! Any help will do!
linear-algebra abstract-algebra quadratic-forms
$endgroup$
I'm a student, currently studying about quadratic forms over a field $mathbb{R}$ and I have a few questions regarding the topic.
- From a book I currently read, a quadratic form is a real-valued function over a vector space $E$ (i.e. $Q: E longrightarrow mathbb{R}$, please correct me if I'm mistaken) such that there exists a symmetric bilinear form $B: E times E longrightarrow mathbb{R}$ in which the following expression is valid:
begin{align}
Q(x)=B(x,x)
end{align}
$forall x in E$.
My question: given some function $F: E longrightarrow mathbb{R}$. The definition requires the existence of a symmetric bilinear form $G: E times E longrightarrow mathbb{R}$ in which the above expression valid, but how to make sure that we could have such function? For example, if I have a function $F: mathbb{R^3} longrightarrow mathbb{R}$ such that
begin{align}
F(x)= x_1+x_2+x_3
end{align}
with $ x=(x_1,x_2,x_3) in mathbb{R^3}$,
how to check whether $F$ is a quadratic form or not?
- The book also mentioned a regular quadratic space $(E, Q)$, i.e. a vector space $E$ in which it has a quadratic space $Q$ that is nonsingular. What is the definition of nonsingular in terms of function/transformation? And how to connect it to this?
I'm really lost, I know I'm still learning, and I need lots of help. Of course, this is not the last time I'll ask, maybe I'll come again if I find more difficulties but for now, this is all I've got to ask you good people in this community. Thanks! Any help will do!
linear-algebra abstract-algebra quadratic-forms
linear-algebra abstract-algebra quadratic-forms
asked Dec 2 '18 at 3:10
20gobbledigook0820gobbledigook08
111
111
$begingroup$
The key word is “quadratic.” When expanded in terms of coordinates, the expression for $Q$ will involve only second-degree terms.
$endgroup$
– amd
Dec 2 '18 at 3:18
$begingroup$
Show that for $E$ finite dimensional with basis $(e_i)$ then $q(sum_i x_i e_i) = sum_i sum_j frac{A_{i,j}+A_{j,i}}{2} x_i x_j$. In matrix form $B(x,y) = x^top frac{A+A^top}{2} y, q(x) = x^top frac{A+A^top}{2} x$
$endgroup$
– reuns
Dec 2 '18 at 4:01
$begingroup$
@amd Ah, I see. Then for any polynomial with degree of two, I could have a quadratic form then?
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:41
$begingroup$
@reuns Could you please explain what $A_{ij}$ suppose to mean? Hehe. Thanks for the help though!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:50
$begingroup$
en.wikipedia.org/wiki/Quadratic_form#Real_quadratic_forms
$endgroup$
– reuns
Dec 2 '18 at 22:16
add a comment |
$begingroup$
The key word is “quadratic.” When expanded in terms of coordinates, the expression for $Q$ will involve only second-degree terms.
$endgroup$
– amd
Dec 2 '18 at 3:18
$begingroup$
Show that for $E$ finite dimensional with basis $(e_i)$ then $q(sum_i x_i e_i) = sum_i sum_j frac{A_{i,j}+A_{j,i}}{2} x_i x_j$. In matrix form $B(x,y) = x^top frac{A+A^top}{2} y, q(x) = x^top frac{A+A^top}{2} x$
$endgroup$
– reuns
Dec 2 '18 at 4:01
$begingroup$
@amd Ah, I see. Then for any polynomial with degree of two, I could have a quadratic form then?
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:41
$begingroup$
@reuns Could you please explain what $A_{ij}$ suppose to mean? Hehe. Thanks for the help though!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:50
$begingroup$
en.wikipedia.org/wiki/Quadratic_form#Real_quadratic_forms
$endgroup$
– reuns
Dec 2 '18 at 22:16
$begingroup$
The key word is “quadratic.” When expanded in terms of coordinates, the expression for $Q$ will involve only second-degree terms.
$endgroup$
– amd
Dec 2 '18 at 3:18
$begingroup$
The key word is “quadratic.” When expanded in terms of coordinates, the expression for $Q$ will involve only second-degree terms.
$endgroup$
– amd
Dec 2 '18 at 3:18
$begingroup$
Show that for $E$ finite dimensional with basis $(e_i)$ then $q(sum_i x_i e_i) = sum_i sum_j frac{A_{i,j}+A_{j,i}}{2} x_i x_j$. In matrix form $B(x,y) = x^top frac{A+A^top}{2} y, q(x) = x^top frac{A+A^top}{2} x$
$endgroup$
– reuns
Dec 2 '18 at 4:01
$begingroup$
Show that for $E$ finite dimensional with basis $(e_i)$ then $q(sum_i x_i e_i) = sum_i sum_j frac{A_{i,j}+A_{j,i}}{2} x_i x_j$. In matrix form $B(x,y) = x^top frac{A+A^top}{2} y, q(x) = x^top frac{A+A^top}{2} x$
$endgroup$
– reuns
Dec 2 '18 at 4:01
$begingroup$
@amd Ah, I see. Then for any polynomial with degree of two, I could have a quadratic form then?
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:41
$begingroup$
@amd Ah, I see. Then for any polynomial with degree of two, I could have a quadratic form then?
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:41
$begingroup$
@reuns Could you please explain what $A_{ij}$ suppose to mean? Hehe. Thanks for the help though!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:50
$begingroup$
@reuns Could you please explain what $A_{ij}$ suppose to mean? Hehe. Thanks for the help though!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:50
$begingroup$
en.wikipedia.org/wiki/Quadratic_form#Real_quadratic_forms
$endgroup$
– reuns
Dec 2 '18 at 22:16
$begingroup$
en.wikipedia.org/wiki/Quadratic_form#Real_quadratic_forms
$endgroup$
– reuns
Dec 2 '18 at 22:16
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
A function $F:EtoBbb R $ is a quadratic form if
$$G (x,y)=frac 12 (F (x+y)-F (x)-F (y)) $$
is bilinear.
In that case $G $ is a symmetric bilinear form and $F (x)=G (x,x) $.
Moreover, $F$ is said to be non singular whenever $G (x,y)=0$ for all $y $ implies $x=0$.
$endgroup$
$begingroup$
Hello! Could I ask the reference to this definition of nonsingular? Thanks a bunch!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 15:58
$begingroup$
See for example here.
$endgroup$
– Fabio Lucchini
Dec 2 '18 at 17:51
add a comment |
Your Answer
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
A function $F:EtoBbb R $ is a quadratic form if
$$G (x,y)=frac 12 (F (x+y)-F (x)-F (y)) $$
is bilinear.
In that case $G $ is a symmetric bilinear form and $F (x)=G (x,x) $.
Moreover, $F$ is said to be non singular whenever $G (x,y)=0$ for all $y $ implies $x=0$.
$endgroup$
$begingroup$
Hello! Could I ask the reference to this definition of nonsingular? Thanks a bunch!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 15:58
$begingroup$
See for example here.
$endgroup$
– Fabio Lucchini
Dec 2 '18 at 17:51
add a comment |
$begingroup$
A function $F:EtoBbb R $ is a quadratic form if
$$G (x,y)=frac 12 (F (x+y)-F (x)-F (y)) $$
is bilinear.
In that case $G $ is a symmetric bilinear form and $F (x)=G (x,x) $.
Moreover, $F$ is said to be non singular whenever $G (x,y)=0$ for all $y $ implies $x=0$.
$endgroup$
$begingroup$
Hello! Could I ask the reference to this definition of nonsingular? Thanks a bunch!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 15:58
$begingroup$
See for example here.
$endgroup$
– Fabio Lucchini
Dec 2 '18 at 17:51
add a comment |
$begingroup$
A function $F:EtoBbb R $ is a quadratic form if
$$G (x,y)=frac 12 (F (x+y)-F (x)-F (y)) $$
is bilinear.
In that case $G $ is a symmetric bilinear form and $F (x)=G (x,x) $.
Moreover, $F$ is said to be non singular whenever $G (x,y)=0$ for all $y $ implies $x=0$.
$endgroup$
A function $F:EtoBbb R $ is a quadratic form if
$$G (x,y)=frac 12 (F (x+y)-F (x)-F (y)) $$
is bilinear.
In that case $G $ is a symmetric bilinear form and $F (x)=G (x,x) $.
Moreover, $F$ is said to be non singular whenever $G (x,y)=0$ for all $y $ implies $x=0$.
edited Dec 2 '18 at 12:57
answered Dec 2 '18 at 12:52
Fabio LucchiniFabio Lucchini
7,83811426
7,83811426
$begingroup$
Hello! Could I ask the reference to this definition of nonsingular? Thanks a bunch!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 15:58
$begingroup$
See for example here.
$endgroup$
– Fabio Lucchini
Dec 2 '18 at 17:51
add a comment |
$begingroup$
Hello! Could I ask the reference to this definition of nonsingular? Thanks a bunch!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 15:58
$begingroup$
See for example here.
$endgroup$
– Fabio Lucchini
Dec 2 '18 at 17:51
$begingroup$
Hello! Could I ask the reference to this definition of nonsingular? Thanks a bunch!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 15:58
$begingroup$
Hello! Could I ask the reference to this definition of nonsingular? Thanks a bunch!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 15:58
$begingroup$
See for example here.
$endgroup$
– Fabio Lucchini
Dec 2 '18 at 17:51
$begingroup$
See for example here.
$endgroup$
– Fabio Lucchini
Dec 2 '18 at 17:51
add a comment |
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$begingroup$
The key word is “quadratic.” When expanded in terms of coordinates, the expression for $Q$ will involve only second-degree terms.
$endgroup$
– amd
Dec 2 '18 at 3:18
$begingroup$
Show that for $E$ finite dimensional with basis $(e_i)$ then $q(sum_i x_i e_i) = sum_i sum_j frac{A_{i,j}+A_{j,i}}{2} x_i x_j$. In matrix form $B(x,y) = x^top frac{A+A^top}{2} y, q(x) = x^top frac{A+A^top}{2} x$
$endgroup$
– reuns
Dec 2 '18 at 4:01
$begingroup$
@amd Ah, I see. Then for any polynomial with degree of two, I could have a quadratic form then?
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:41
$begingroup$
@reuns Could you please explain what $A_{ij}$ suppose to mean? Hehe. Thanks for the help though!
$endgroup$
– 20gobbledigook08
Dec 2 '18 at 13:50
$begingroup$
en.wikipedia.org/wiki/Quadratic_form#Real_quadratic_forms
$endgroup$
– reuns
Dec 2 '18 at 22:16