probability for filling fuel












1














I'm trying to solve below probability question ;



fuel station has $5$ filling points of which $3$ are use to fill petrol and remaining $2$ are use to fill diesel for different kind of vehicles.It was noticed that an average $3$ minutes to fill fuel to any vehicle (diesel/petrol).number of petrol vehicles to enter the fuel station within an hour estimated is $24$ and the diesel vehicle estimated 36 within an hour.



want to find below probabilities :




  1. all petrol filling points are idle

  2. all diesel filling points are busy

  3. all petrol filling points are busy

  4. all filling points are busy










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  • Busy in a given minute, hour, ... ?
    – BlackMath
    Nov 28 '18 at 5:00










  • Do you mean to say, "at any given time"?
    – bob
    Nov 28 '18 at 5:56










  • yes it is any given time
    – Tje123
    Nov 28 '18 at 6:00
















1














I'm trying to solve below probability question ;



fuel station has $5$ filling points of which $3$ are use to fill petrol and remaining $2$ are use to fill diesel for different kind of vehicles.It was noticed that an average $3$ minutes to fill fuel to any vehicle (diesel/petrol).number of petrol vehicles to enter the fuel station within an hour estimated is $24$ and the diesel vehicle estimated 36 within an hour.



want to find below probabilities :




  1. all petrol filling points are idle

  2. all diesel filling points are busy

  3. all petrol filling points are busy

  4. all filling points are busy










share|cite|improve this question
























  • Busy in a given minute, hour, ... ?
    – BlackMath
    Nov 28 '18 at 5:00










  • Do you mean to say, "at any given time"?
    – bob
    Nov 28 '18 at 5:56










  • yes it is any given time
    – Tje123
    Nov 28 '18 at 6:00














1












1








1







I'm trying to solve below probability question ;



fuel station has $5$ filling points of which $3$ are use to fill petrol and remaining $2$ are use to fill diesel for different kind of vehicles.It was noticed that an average $3$ minutes to fill fuel to any vehicle (diesel/petrol).number of petrol vehicles to enter the fuel station within an hour estimated is $24$ and the diesel vehicle estimated 36 within an hour.



want to find below probabilities :




  1. all petrol filling points are idle

  2. all diesel filling points are busy

  3. all petrol filling points are busy

  4. all filling points are busy










share|cite|improve this question















I'm trying to solve below probability question ;



fuel station has $5$ filling points of which $3$ are use to fill petrol and remaining $2$ are use to fill diesel for different kind of vehicles.It was noticed that an average $3$ minutes to fill fuel to any vehicle (diesel/petrol).number of petrol vehicles to enter the fuel station within an hour estimated is $24$ and the diesel vehicle estimated 36 within an hour.



want to find below probabilities :




  1. all petrol filling points are idle

  2. all diesel filling points are busy

  3. all petrol filling points are busy

  4. all filling points are busy







probability combinatorics matrices probability-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 28 '18 at 9:16

























asked Nov 28 '18 at 4:08









Tje123

84




84












  • Busy in a given minute, hour, ... ?
    – BlackMath
    Nov 28 '18 at 5:00










  • Do you mean to say, "at any given time"?
    – bob
    Nov 28 '18 at 5:56










  • yes it is any given time
    – Tje123
    Nov 28 '18 at 6:00


















  • Busy in a given minute, hour, ... ?
    – BlackMath
    Nov 28 '18 at 5:00










  • Do you mean to say, "at any given time"?
    – bob
    Nov 28 '18 at 5:56










  • yes it is any given time
    – Tje123
    Nov 28 '18 at 6:00
















Busy in a given minute, hour, ... ?
– BlackMath
Nov 28 '18 at 5:00




Busy in a given minute, hour, ... ?
– BlackMath
Nov 28 '18 at 5:00












Do you mean to say, "at any given time"?
– bob
Nov 28 '18 at 5:56




Do you mean to say, "at any given time"?
– bob
Nov 28 '18 at 5:56












yes it is any given time
– Tje123
Nov 28 '18 at 6:00




yes it is any given time
– Tje123
Nov 28 '18 at 6:00










1 Answer
1






active

oldest

votes


















0














It was noticed that an average 3 minutes are required to fill fuel to any vehicle. As there are 3 petrol filling points, they can fill fuel petrol to petrol vehicles at the most 60 per hour. As number of petrol vehicles entering into fuel station are 24, The probability that all the 3 petrol points will remain idle is $binom{3}{3}(frac{24}{60})^0(frac{36}{60})^3=0.216$



Likewise, You calculate the answers to other questions.



Answers to the other questions are as follows:



2)$binom{2}{2}(frac{36}{40})^2(frac{4}{40})^0=0.81$



3)$binom{3}{3}(frac{24}{60})^3(frac{36}{40})^0=0.064$



4)$binom{5}{5}(frac{60}{100})^5(frac{40}{100})^0=0.0776.$






share|cite|improve this answer























  • Thank you for the help.can you show me the formula for 2,3,4 th answers?
    – Tje123
    Nov 28 '18 at 7:22










  • @Tje123, If you find my answer useful, upvote my answer by clicking$uparrow$
    – Dhamnekar Winod
    Nov 28 '18 at 9:30










  • what is this 40 ? and 100?
    – Tje123
    Nov 28 '18 at 9:40












  • @Tje123, Why don't you upvote my answer?
    – Dhamnekar Winod
    Nov 28 '18 at 9:55










  • i have accept your answer. can you please explain what is 40?100?
    – Tje123
    Nov 28 '18 at 10:03













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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

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active

oldest

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oldest

votes









0














It was noticed that an average 3 minutes are required to fill fuel to any vehicle. As there are 3 petrol filling points, they can fill fuel petrol to petrol vehicles at the most 60 per hour. As number of petrol vehicles entering into fuel station are 24, The probability that all the 3 petrol points will remain idle is $binom{3}{3}(frac{24}{60})^0(frac{36}{60})^3=0.216$



Likewise, You calculate the answers to other questions.



Answers to the other questions are as follows:



2)$binom{2}{2}(frac{36}{40})^2(frac{4}{40})^0=0.81$



3)$binom{3}{3}(frac{24}{60})^3(frac{36}{40})^0=0.064$



4)$binom{5}{5}(frac{60}{100})^5(frac{40}{100})^0=0.0776.$






share|cite|improve this answer























  • Thank you for the help.can you show me the formula for 2,3,4 th answers?
    – Tje123
    Nov 28 '18 at 7:22










  • @Tje123, If you find my answer useful, upvote my answer by clicking$uparrow$
    – Dhamnekar Winod
    Nov 28 '18 at 9:30










  • what is this 40 ? and 100?
    – Tje123
    Nov 28 '18 at 9:40












  • @Tje123, Why don't you upvote my answer?
    – Dhamnekar Winod
    Nov 28 '18 at 9:55










  • i have accept your answer. can you please explain what is 40?100?
    – Tje123
    Nov 28 '18 at 10:03


















0














It was noticed that an average 3 minutes are required to fill fuel to any vehicle. As there are 3 petrol filling points, they can fill fuel petrol to petrol vehicles at the most 60 per hour. As number of petrol vehicles entering into fuel station are 24, The probability that all the 3 petrol points will remain idle is $binom{3}{3}(frac{24}{60})^0(frac{36}{60})^3=0.216$



Likewise, You calculate the answers to other questions.



Answers to the other questions are as follows:



2)$binom{2}{2}(frac{36}{40})^2(frac{4}{40})^0=0.81$



3)$binom{3}{3}(frac{24}{60})^3(frac{36}{40})^0=0.064$



4)$binom{5}{5}(frac{60}{100})^5(frac{40}{100})^0=0.0776.$






share|cite|improve this answer























  • Thank you for the help.can you show me the formula for 2,3,4 th answers?
    – Tje123
    Nov 28 '18 at 7:22










  • @Tje123, If you find my answer useful, upvote my answer by clicking$uparrow$
    – Dhamnekar Winod
    Nov 28 '18 at 9:30










  • what is this 40 ? and 100?
    – Tje123
    Nov 28 '18 at 9:40












  • @Tje123, Why don't you upvote my answer?
    – Dhamnekar Winod
    Nov 28 '18 at 9:55










  • i have accept your answer. can you please explain what is 40?100?
    – Tje123
    Nov 28 '18 at 10:03
















0












0








0






It was noticed that an average 3 minutes are required to fill fuel to any vehicle. As there are 3 petrol filling points, they can fill fuel petrol to petrol vehicles at the most 60 per hour. As number of petrol vehicles entering into fuel station are 24, The probability that all the 3 petrol points will remain idle is $binom{3}{3}(frac{24}{60})^0(frac{36}{60})^3=0.216$



Likewise, You calculate the answers to other questions.



Answers to the other questions are as follows:



2)$binom{2}{2}(frac{36}{40})^2(frac{4}{40})^0=0.81$



3)$binom{3}{3}(frac{24}{60})^3(frac{36}{40})^0=0.064$



4)$binom{5}{5}(frac{60}{100})^5(frac{40}{100})^0=0.0776.$






share|cite|improve this answer














It was noticed that an average 3 minutes are required to fill fuel to any vehicle. As there are 3 petrol filling points, they can fill fuel petrol to petrol vehicles at the most 60 per hour. As number of petrol vehicles entering into fuel station are 24, The probability that all the 3 petrol points will remain idle is $binom{3}{3}(frac{24}{60})^0(frac{36}{60})^3=0.216$



Likewise, You calculate the answers to other questions.



Answers to the other questions are as follows:



2)$binom{2}{2}(frac{36}{40})^2(frac{4}{40})^0=0.81$



3)$binom{3}{3}(frac{24}{60})^3(frac{36}{40})^0=0.064$



4)$binom{5}{5}(frac{60}{100})^5(frac{40}{100})^0=0.0776.$







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Nov 28 '18 at 9:27

























answered Nov 28 '18 at 6:23









Dhamnekar Winod

387414




387414












  • Thank you for the help.can you show me the formula for 2,3,4 th answers?
    – Tje123
    Nov 28 '18 at 7:22










  • @Tje123, If you find my answer useful, upvote my answer by clicking$uparrow$
    – Dhamnekar Winod
    Nov 28 '18 at 9:30










  • what is this 40 ? and 100?
    – Tje123
    Nov 28 '18 at 9:40












  • @Tje123, Why don't you upvote my answer?
    – Dhamnekar Winod
    Nov 28 '18 at 9:55










  • i have accept your answer. can you please explain what is 40?100?
    – Tje123
    Nov 28 '18 at 10:03




















  • Thank you for the help.can you show me the formula for 2,3,4 th answers?
    – Tje123
    Nov 28 '18 at 7:22










  • @Tje123, If you find my answer useful, upvote my answer by clicking$uparrow$
    – Dhamnekar Winod
    Nov 28 '18 at 9:30










  • what is this 40 ? and 100?
    – Tje123
    Nov 28 '18 at 9:40












  • @Tje123, Why don't you upvote my answer?
    – Dhamnekar Winod
    Nov 28 '18 at 9:55










  • i have accept your answer. can you please explain what is 40?100?
    – Tje123
    Nov 28 '18 at 10:03


















Thank you for the help.can you show me the formula for 2,3,4 th answers?
– Tje123
Nov 28 '18 at 7:22




Thank you for the help.can you show me the formula for 2,3,4 th answers?
– Tje123
Nov 28 '18 at 7:22












@Tje123, If you find my answer useful, upvote my answer by clicking$uparrow$
– Dhamnekar Winod
Nov 28 '18 at 9:30




@Tje123, If you find my answer useful, upvote my answer by clicking$uparrow$
– Dhamnekar Winod
Nov 28 '18 at 9:30












what is this 40 ? and 100?
– Tje123
Nov 28 '18 at 9:40






what is this 40 ? and 100?
– Tje123
Nov 28 '18 at 9:40














@Tje123, Why don't you upvote my answer?
– Dhamnekar Winod
Nov 28 '18 at 9:55




@Tje123, Why don't you upvote my answer?
– Dhamnekar Winod
Nov 28 '18 at 9:55












i have accept your answer. can you please explain what is 40?100?
– Tje123
Nov 28 '18 at 10:03






i have accept your answer. can you please explain what is 40?100?
– Tje123
Nov 28 '18 at 10:03




















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