How to capture disk usage percentage of a partition as an integer?












14














I would like a method to capture the disk usage of a particular partition, by using the directory where the partition is mounted. The output should just be an integer with no padding or following symbols, as I'd like to save it in a variable.



I've used df --output=pcent /mount/point, but need to trim the output as it has an unnecessary header, single space padding before the value, and a % symbol following the value like so:



Use%
83%


In this case the output I would like would simply be 83. I'm not aware of any drawbacks to using the output of df, but am happy to accept other methods that do not rely on it.










share|improve this question


















  • 1




    why not simply parse it?
    – Jacob Vlijm
    Nov 10 '16 at 11:20






  • 1




    I don't see a drawback either, you can remove the header with df then | tr -dc '0-9'
    – bc2946088
    Nov 10 '16 at 11:25












  • I stand corrected, I can't find the switch to remove the header from df.
    – bc2946088
    Nov 10 '16 at 11:32










  • I'd read the man page, and the info page and couldn't find it either @bc2946088, good shout to consider tr, I was getting my head in a mess with sed and awk ideas.
    – Arronical
    Nov 10 '16 at 11:34






  • 3




    I've searched for removing header option,too. Basically GNU developers are reluctant to impleme it. There have been feature requests, and they just said no.
    – Sergiy Kolodyazhnyy
    Nov 10 '16 at 11:49
















14














I would like a method to capture the disk usage of a particular partition, by using the directory where the partition is mounted. The output should just be an integer with no padding or following symbols, as I'd like to save it in a variable.



I've used df --output=pcent /mount/point, but need to trim the output as it has an unnecessary header, single space padding before the value, and a % symbol following the value like so:



Use%
83%


In this case the output I would like would simply be 83. I'm not aware of any drawbacks to using the output of df, but am happy to accept other methods that do not rely on it.










share|improve this question


















  • 1




    why not simply parse it?
    – Jacob Vlijm
    Nov 10 '16 at 11:20






  • 1




    I don't see a drawback either, you can remove the header with df then | tr -dc '0-9'
    – bc2946088
    Nov 10 '16 at 11:25












  • I stand corrected, I can't find the switch to remove the header from df.
    – bc2946088
    Nov 10 '16 at 11:32










  • I'd read the man page, and the info page and couldn't find it either @bc2946088, good shout to consider tr, I was getting my head in a mess with sed and awk ideas.
    – Arronical
    Nov 10 '16 at 11:34






  • 3




    I've searched for removing header option,too. Basically GNU developers are reluctant to impleme it. There have been feature requests, and they just said no.
    – Sergiy Kolodyazhnyy
    Nov 10 '16 at 11:49














14












14








14


0





I would like a method to capture the disk usage of a particular partition, by using the directory where the partition is mounted. The output should just be an integer with no padding or following symbols, as I'd like to save it in a variable.



I've used df --output=pcent /mount/point, but need to trim the output as it has an unnecessary header, single space padding before the value, and a % symbol following the value like so:



Use%
83%


In this case the output I would like would simply be 83. I'm not aware of any drawbacks to using the output of df, but am happy to accept other methods that do not rely on it.










share|improve this question













I would like a method to capture the disk usage of a particular partition, by using the directory where the partition is mounted. The output should just be an integer with no padding or following symbols, as I'd like to save it in a variable.



I've used df --output=pcent /mount/point, but need to trim the output as it has an unnecessary header, single space padding before the value, and a % symbol following the value like so:



Use%
83%


In this case the output I would like would simply be 83. I'm not aware of any drawbacks to using the output of df, but am happy to accept other methods that do not rely on it.







command-line bash scripts disk-usage






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 10 '16 at 11:02









Arronical

13k84790




13k84790








  • 1




    why not simply parse it?
    – Jacob Vlijm
    Nov 10 '16 at 11:20






  • 1




    I don't see a drawback either, you can remove the header with df then | tr -dc '0-9'
    – bc2946088
    Nov 10 '16 at 11:25












  • I stand corrected, I can't find the switch to remove the header from df.
    – bc2946088
    Nov 10 '16 at 11:32










  • I'd read the man page, and the info page and couldn't find it either @bc2946088, good shout to consider tr, I was getting my head in a mess with sed and awk ideas.
    – Arronical
    Nov 10 '16 at 11:34






  • 3




    I've searched for removing header option,too. Basically GNU developers are reluctant to impleme it. There have been feature requests, and they just said no.
    – Sergiy Kolodyazhnyy
    Nov 10 '16 at 11:49














  • 1




    why not simply parse it?
    – Jacob Vlijm
    Nov 10 '16 at 11:20






  • 1




    I don't see a drawback either, you can remove the header with df then | tr -dc '0-9'
    – bc2946088
    Nov 10 '16 at 11:25












  • I stand corrected, I can't find the switch to remove the header from df.
    – bc2946088
    Nov 10 '16 at 11:32










  • I'd read the man page, and the info page and couldn't find it either @bc2946088, good shout to consider tr, I was getting my head in a mess with sed and awk ideas.
    – Arronical
    Nov 10 '16 at 11:34






  • 3




    I've searched for removing header option,too. Basically GNU developers are reluctant to impleme it. There have been feature requests, and they just said no.
    – Sergiy Kolodyazhnyy
    Nov 10 '16 at 11:49








1




1




why not simply parse it?
– Jacob Vlijm
Nov 10 '16 at 11:20




why not simply parse it?
– Jacob Vlijm
Nov 10 '16 at 11:20




1




1




I don't see a drawback either, you can remove the header with df then | tr -dc '0-9'
– bc2946088
Nov 10 '16 at 11:25






I don't see a drawback either, you can remove the header with df then | tr -dc '0-9'
– bc2946088
Nov 10 '16 at 11:25














I stand corrected, I can't find the switch to remove the header from df.
– bc2946088
Nov 10 '16 at 11:32




I stand corrected, I can't find the switch to remove the header from df.
– bc2946088
Nov 10 '16 at 11:32












I'd read the man page, and the info page and couldn't find it either @bc2946088, good shout to consider tr, I was getting my head in a mess with sed and awk ideas.
– Arronical
Nov 10 '16 at 11:34




I'd read the man page, and the info page and couldn't find it either @bc2946088, good shout to consider tr, I was getting my head in a mess with sed and awk ideas.
– Arronical
Nov 10 '16 at 11:34




3




3




I've searched for removing header option,too. Basically GNU developers are reluctant to impleme it. There have been feature requests, and they just said no.
– Sergiy Kolodyazhnyy
Nov 10 '16 at 11:49




I've searched for removing header option,too. Basically GNU developers are reluctant to impleme it. There have been feature requests, and they just said no.
– Sergiy Kolodyazhnyy
Nov 10 '16 at 11:49










6 Answers
6






active

oldest

votes


















19














I'd use...



df --output=pcent /mount/point | tr -dc '0-9'


Not sure if sed is faster, but I can't ever remember the sed values.






share|improve this answer



















  • 1




    Using time to test it comes out as being just as fast as sed.
    – Arronical
    Nov 10 '16 at 11:54






  • 4




    @Arronical unless your outputs are waaaaaaaaaaaay greater than 100%, I doubt you'd see much difference. :P
    – muru
    Nov 10 '16 at 12:15










  • @Arronical What muru said; invocation time is likely to dominate.
    – a CVn
    Nov 11 '16 at 13:23






  • 1




    In this instance, tr is easier to read than sed.
    – Paddy Landau
    Nov 15 '16 at 12:49



















9














Here's awk solution:



$ df --output=pcent /mnt/HDD | awk -F'%' 'NR==2{print $1}'   
37


Basically what happens here is that we treat '%' character as field separator ( column delimiter ), and print first column $1 only when number of records equals to two ( the NR==2 part )



If we wanted to use bash-only tools, we could do something like this:



bash-4.3$ df --output=pcent / | while IFS= read -r line; do 
> ((c++));
> [ $c -eq 2 ] && echo "${line%%*}" ;
> done
74


And for fun, alternative sed via capture group and -r for extended regex:



df --output=pcent | sed -nr '/[[:digit:]]/{s/[[:space:]]+([[:digit:]]+)%/1/;p}'





share|improve this answer































    7














    sed solution



    df --output=pcent /mount/point | sed '1d;s/^ //;s/%//'




    • 1d delete the first line


    • ; to separate commands


    • s/^ // remove a space from the start of lines


    • s/%// remove % sign






    share|improve this answer































      7














      You can pipe to a grep that just extracts digits:



      df --output=pcent /mount/point | grep -o '[0-9]*'


      See it live:



      $ echo "Use%
      > 83%" | grep -o '[0-9]*'
      83





      share|improve this answer





























        1














        Bash two-step solution



        Being somewhat of a bash (Borne Again SHell) fan the last year I thought I'd propose a solution using it.



        $ DF_PCT=$(df --output=pcent /mnt/d)
        $ echo ${DF_PCT//[!0-9]/}
        5



        • Line 1 captures df output to variable DF_PCT.

        • Line 2 strips everything that is not a digit in DF_PCT and displays it on screen.

        • Advantage over accepted answer is line feed after percentage (5 in this case) is generated.






        share|improve this answer





























          0














          I came upon a server where --output=pcent was not yet implemented, so I used the normal output, filtered by column, followed by the regex: df /mount/point | awk '{print $5}' | tr -dc '0-9'






          share|improve this answer





















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            6 Answers
            6






            active

            oldest

            votes








            6 Answers
            6






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            19














            I'd use...



            df --output=pcent /mount/point | tr -dc '0-9'


            Not sure if sed is faster, but I can't ever remember the sed values.






            share|improve this answer



















            • 1




              Using time to test it comes out as being just as fast as sed.
              – Arronical
              Nov 10 '16 at 11:54






            • 4




              @Arronical unless your outputs are waaaaaaaaaaaay greater than 100%, I doubt you'd see much difference. :P
              – muru
              Nov 10 '16 at 12:15










            • @Arronical What muru said; invocation time is likely to dominate.
              – a CVn
              Nov 11 '16 at 13:23






            • 1




              In this instance, tr is easier to read than sed.
              – Paddy Landau
              Nov 15 '16 at 12:49
















            19














            I'd use...



            df --output=pcent /mount/point | tr -dc '0-9'


            Not sure if sed is faster, but I can't ever remember the sed values.






            share|improve this answer



















            • 1




              Using time to test it comes out as being just as fast as sed.
              – Arronical
              Nov 10 '16 at 11:54






            • 4




              @Arronical unless your outputs are waaaaaaaaaaaay greater than 100%, I doubt you'd see much difference. :P
              – muru
              Nov 10 '16 at 12:15










            • @Arronical What muru said; invocation time is likely to dominate.
              – a CVn
              Nov 11 '16 at 13:23






            • 1




              In this instance, tr is easier to read than sed.
              – Paddy Landau
              Nov 15 '16 at 12:49














            19












            19








            19






            I'd use...



            df --output=pcent /mount/point | tr -dc '0-9'


            Not sure if sed is faster, but I can't ever remember the sed values.






            share|improve this answer














            I'd use...



            df --output=pcent /mount/point | tr -dc '0-9'


            Not sure if sed is faster, but I can't ever remember the sed values.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 10 '16 at 12:04









            muru

            1




            1










            answered Nov 10 '16 at 11:47









            bc2946088

            3,18021129




            3,18021129








            • 1




              Using time to test it comes out as being just as fast as sed.
              – Arronical
              Nov 10 '16 at 11:54






            • 4




              @Arronical unless your outputs are waaaaaaaaaaaay greater than 100%, I doubt you'd see much difference. :P
              – muru
              Nov 10 '16 at 12:15










            • @Arronical What muru said; invocation time is likely to dominate.
              – a CVn
              Nov 11 '16 at 13:23






            • 1




              In this instance, tr is easier to read than sed.
              – Paddy Landau
              Nov 15 '16 at 12:49














            • 1




              Using time to test it comes out as being just as fast as sed.
              – Arronical
              Nov 10 '16 at 11:54






            • 4




              @Arronical unless your outputs are waaaaaaaaaaaay greater than 100%, I doubt you'd see much difference. :P
              – muru
              Nov 10 '16 at 12:15










            • @Arronical What muru said; invocation time is likely to dominate.
              – a CVn
              Nov 11 '16 at 13:23






            • 1




              In this instance, tr is easier to read than sed.
              – Paddy Landau
              Nov 15 '16 at 12:49








            1




            1




            Using time to test it comes out as being just as fast as sed.
            – Arronical
            Nov 10 '16 at 11:54




            Using time to test it comes out as being just as fast as sed.
            – Arronical
            Nov 10 '16 at 11:54




            4




            4




            @Arronical unless your outputs are waaaaaaaaaaaay greater than 100%, I doubt you'd see much difference. :P
            – muru
            Nov 10 '16 at 12:15




            @Arronical unless your outputs are waaaaaaaaaaaay greater than 100%, I doubt you'd see much difference. :P
            – muru
            Nov 10 '16 at 12:15












            @Arronical What muru said; invocation time is likely to dominate.
            – a CVn
            Nov 11 '16 at 13:23




            @Arronical What muru said; invocation time is likely to dominate.
            – a CVn
            Nov 11 '16 at 13:23




            1




            1




            In this instance, tr is easier to read than sed.
            – Paddy Landau
            Nov 15 '16 at 12:49




            In this instance, tr is easier to read than sed.
            – Paddy Landau
            Nov 15 '16 at 12:49













            9














            Here's awk solution:



            $ df --output=pcent /mnt/HDD | awk -F'%' 'NR==2{print $1}'   
            37


            Basically what happens here is that we treat '%' character as field separator ( column delimiter ), and print first column $1 only when number of records equals to two ( the NR==2 part )



            If we wanted to use bash-only tools, we could do something like this:



            bash-4.3$ df --output=pcent / | while IFS= read -r line; do 
            > ((c++));
            > [ $c -eq 2 ] && echo "${line%%*}" ;
            > done
            74


            And for fun, alternative sed via capture group and -r for extended regex:



            df --output=pcent | sed -nr '/[[:digit:]]/{s/[[:space:]]+([[:digit:]]+)%/1/;p}'





            share|improve this answer




























              9














              Here's awk solution:



              $ df --output=pcent /mnt/HDD | awk -F'%' 'NR==2{print $1}'   
              37


              Basically what happens here is that we treat '%' character as field separator ( column delimiter ), and print first column $1 only when number of records equals to two ( the NR==2 part )



              If we wanted to use bash-only tools, we could do something like this:



              bash-4.3$ df --output=pcent / | while IFS= read -r line; do 
              > ((c++));
              > [ $c -eq 2 ] && echo "${line%%*}" ;
              > done
              74


              And for fun, alternative sed via capture group and -r for extended regex:



              df --output=pcent | sed -nr '/[[:digit:]]/{s/[[:space:]]+([[:digit:]]+)%/1/;p}'





              share|improve this answer


























                9












                9








                9






                Here's awk solution:



                $ df --output=pcent /mnt/HDD | awk -F'%' 'NR==2{print $1}'   
                37


                Basically what happens here is that we treat '%' character as field separator ( column delimiter ), and print first column $1 only when number of records equals to two ( the NR==2 part )



                If we wanted to use bash-only tools, we could do something like this:



                bash-4.3$ df --output=pcent / | while IFS= read -r line; do 
                > ((c++));
                > [ $c -eq 2 ] && echo "${line%%*}" ;
                > done
                74


                And for fun, alternative sed via capture group and -r for extended regex:



                df --output=pcent | sed -nr '/[[:digit:]]/{s/[[:space:]]+([[:digit:]]+)%/1/;p}'





                share|improve this answer














                Here's awk solution:



                $ df --output=pcent /mnt/HDD | awk -F'%' 'NR==2{print $1}'   
                37


                Basically what happens here is that we treat '%' character as field separator ( column delimiter ), and print first column $1 only when number of records equals to two ( the NR==2 part )



                If we wanted to use bash-only tools, we could do something like this:



                bash-4.3$ df --output=pcent / | while IFS= read -r line; do 
                > ((c++));
                > [ $c -eq 2 ] && echo "${line%%*}" ;
                > done
                74


                And for fun, alternative sed via capture group and -r for extended regex:



                df --output=pcent | sed -nr '/[[:digit:]]/{s/[[:space:]]+([[:digit:]]+)%/1/;p}'






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Dec 5 at 19:18

























                answered Nov 10 '16 at 11:57









                Sergiy Kolodyazhnyy

                69.2k9144303




                69.2k9144303























                    7














                    sed solution



                    df --output=pcent /mount/point | sed '1d;s/^ //;s/%//'




                    • 1d delete the first line


                    • ; to separate commands


                    • s/^ // remove a space from the start of lines


                    • s/%// remove % sign






                    share|improve this answer




























                      7














                      sed solution



                      df --output=pcent /mount/point | sed '1d;s/^ //;s/%//'




                      • 1d delete the first line


                      • ; to separate commands


                      • s/^ // remove a space from the start of lines


                      • s/%// remove % sign






                      share|improve this answer


























                        7












                        7








                        7






                        sed solution



                        df --output=pcent /mount/point | sed '1d;s/^ //;s/%//'




                        • 1d delete the first line


                        • ; to separate commands


                        • s/^ // remove a space from the start of lines


                        • s/%// remove % sign






                        share|improve this answer














                        sed solution



                        df --output=pcent /mount/point | sed '1d;s/^ //;s/%//'




                        • 1d delete the first line


                        • ; to separate commands


                        • s/^ // remove a space from the start of lines


                        • s/%// remove % sign







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited Nov 10 '16 at 12:04









                        muru

                        1




                        1










                        answered Nov 10 '16 at 11:33









                        Zanna

                        49.9k13130237




                        49.9k13130237























                            7














                            You can pipe to a grep that just extracts digits:



                            df --output=pcent /mount/point | grep -o '[0-9]*'


                            See it live:



                            $ echo "Use%
                            > 83%" | grep -o '[0-9]*'
                            83





                            share|improve this answer


























                              7














                              You can pipe to a grep that just extracts digits:



                              df --output=pcent /mount/point | grep -o '[0-9]*'


                              See it live:



                              $ echo "Use%
                              > 83%" | grep -o '[0-9]*'
                              83





                              share|improve this answer
























                                7












                                7








                                7






                                You can pipe to a grep that just extracts digits:



                                df --output=pcent /mount/point | grep -o '[0-9]*'


                                See it live:



                                $ echo "Use%
                                > 83%" | grep -o '[0-9]*'
                                83





                                share|improve this answer












                                You can pipe to a grep that just extracts digits:



                                df --output=pcent /mount/point | grep -o '[0-9]*'


                                See it live:



                                $ echo "Use%
                                > 83%" | grep -o '[0-9]*'
                                83






                                share|improve this answer












                                share|improve this answer



                                share|improve this answer










                                answered Nov 11 '16 at 9:28









                                fedorqui

                                6,07611032




                                6,07611032























                                    1














                                    Bash two-step solution



                                    Being somewhat of a bash (Borne Again SHell) fan the last year I thought I'd propose a solution using it.



                                    $ DF_PCT=$(df --output=pcent /mnt/d)
                                    $ echo ${DF_PCT//[!0-9]/}
                                    5



                                    • Line 1 captures df output to variable DF_PCT.

                                    • Line 2 strips everything that is not a digit in DF_PCT and displays it on screen.

                                    • Advantage over accepted answer is line feed after percentage (5 in this case) is generated.






                                    share|improve this answer


























                                      1














                                      Bash two-step solution



                                      Being somewhat of a bash (Borne Again SHell) fan the last year I thought I'd propose a solution using it.



                                      $ DF_PCT=$(df --output=pcent /mnt/d)
                                      $ echo ${DF_PCT//[!0-9]/}
                                      5



                                      • Line 1 captures df output to variable DF_PCT.

                                      • Line 2 strips everything that is not a digit in DF_PCT and displays it on screen.

                                      • Advantage over accepted answer is line feed after percentage (5 in this case) is generated.






                                      share|improve this answer
























                                        1












                                        1








                                        1






                                        Bash two-step solution



                                        Being somewhat of a bash (Borne Again SHell) fan the last year I thought I'd propose a solution using it.



                                        $ DF_PCT=$(df --output=pcent /mnt/d)
                                        $ echo ${DF_PCT//[!0-9]/}
                                        5



                                        • Line 1 captures df output to variable DF_PCT.

                                        • Line 2 strips everything that is not a digit in DF_PCT and displays it on screen.

                                        • Advantage over accepted answer is line feed after percentage (5 in this case) is generated.






                                        share|improve this answer












                                        Bash two-step solution



                                        Being somewhat of a bash (Borne Again SHell) fan the last year I thought I'd propose a solution using it.



                                        $ DF_PCT=$(df --output=pcent /mnt/d)
                                        $ echo ${DF_PCT//[!0-9]/}
                                        5



                                        • Line 1 captures df output to variable DF_PCT.

                                        • Line 2 strips everything that is not a digit in DF_PCT and displays it on screen.

                                        • Advantage over accepted answer is line feed after percentage (5 in this case) is generated.







                                        share|improve this answer












                                        share|improve this answer



                                        share|improve this answer










                                        answered Dec 6 at 4:12









                                        WinEunuuchs2Unix

                                        41.7k1070158




                                        41.7k1070158























                                            0














                                            I came upon a server where --output=pcent was not yet implemented, so I used the normal output, filtered by column, followed by the regex: df /mount/point | awk '{print $5}' | tr -dc '0-9'






                                            share|improve this answer


























                                              0














                                              I came upon a server where --output=pcent was not yet implemented, so I used the normal output, filtered by column, followed by the regex: df /mount/point | awk '{print $5}' | tr -dc '0-9'






                                              share|improve this answer
























                                                0












                                                0








                                                0






                                                I came upon a server where --output=pcent was not yet implemented, so I used the normal output, filtered by column, followed by the regex: df /mount/point | awk '{print $5}' | tr -dc '0-9'






                                                share|improve this answer












                                                I came upon a server where --output=pcent was not yet implemented, so I used the normal output, filtered by column, followed by the regex: df /mount/point | awk '{print $5}' | tr -dc '0-9'







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                                                answered Jan 3 at 18:55









                                                Ramon Fincken

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