IC product lifetime as function of junction temperature
If an IC is rated for an absolute maximum junction temperature of say 170 Celsius, obviously it is not recommended to operate there - but how drastically is product lifetime impacted if we are close, say operating at junction temperature of 160. How severely does the IC lifetime get shortened as we get closer to the maximum junction temperature ?
integrated-circuit thermal
add a comment |
If an IC is rated for an absolute maximum junction temperature of say 170 Celsius, obviously it is not recommended to operate there - but how drastically is product lifetime impacted if we are close, say operating at junction temperature of 160. How severely does the IC lifetime get shortened as we get closer to the maximum junction temperature ?
integrated-circuit thermal
add a comment |
If an IC is rated for an absolute maximum junction temperature of say 170 Celsius, obviously it is not recommended to operate there - but how drastically is product lifetime impacted if we are close, say operating at junction temperature of 160. How severely does the IC lifetime get shortened as we get closer to the maximum junction temperature ?
integrated-circuit thermal
If an IC is rated for an absolute maximum junction temperature of say 170 Celsius, obviously it is not recommended to operate there - but how drastically is product lifetime impacted if we are close, say operating at junction temperature of 160. How severely does the IC lifetime get shortened as we get closer to the maximum junction temperature ?
integrated-circuit thermal
integrated-circuit thermal
asked Nov 23 at 23:10
VanGo
424415
424415
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
There are two rules of thumb when it comes to premature aging of electronics and temperature:
Every 10°C above 25°C halves its life
Every 15°C above 25°C halves its life.
The 10°C is derived from a certain application of Arrhenius' equation
$ AF = e^{ frac{E_a}{k}}(frac{1}{T_{use}}- frac{1}{T_{test}}) $
The issue with this is the 10°C result was a very broad interpretation of the empirical results (no consideration was given to other failure modes).
MIL-HDBK-217 took into account field data and concluded that 15°C is a figure more applicable to practical usage
https://www.electronics-cooling.com/2017/08/10c-increase-temperature-really-reduce-life-electronics-half/
I think thatEvery 10°C above 25°C halves its life
is related to chemistry.
– Harry Svensson
Nov 24 at 11:27
I agree, this was then broadly applied. I have been looking into this recently wrt uprating. The problem is the mail is out of date
– JonRB
Nov 24 at 13:16
1
And to just put a number to it. $2^{frac{160-25}{15}}=512$. That means, if the device has a lifetime of 512 years at 25° C, then it will have a lifetime of 1 year at 160° C.
– Harry Svensson
Nov 25 at 2:49
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
return StackExchange.using("schematics", function () {
StackExchange.schematics.init();
});
}, "cicuitlab");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "135"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f408537%2fic-product-lifetime-as-function-of-junction-temperature%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
There are two rules of thumb when it comes to premature aging of electronics and temperature:
Every 10°C above 25°C halves its life
Every 15°C above 25°C halves its life.
The 10°C is derived from a certain application of Arrhenius' equation
$ AF = e^{ frac{E_a}{k}}(frac{1}{T_{use}}- frac{1}{T_{test}}) $
The issue with this is the 10°C result was a very broad interpretation of the empirical results (no consideration was given to other failure modes).
MIL-HDBK-217 took into account field data and concluded that 15°C is a figure more applicable to practical usage
https://www.electronics-cooling.com/2017/08/10c-increase-temperature-really-reduce-life-electronics-half/
I think thatEvery 10°C above 25°C halves its life
is related to chemistry.
– Harry Svensson
Nov 24 at 11:27
I agree, this was then broadly applied. I have been looking into this recently wrt uprating. The problem is the mail is out of date
– JonRB
Nov 24 at 13:16
1
And to just put a number to it. $2^{frac{160-25}{15}}=512$. That means, if the device has a lifetime of 512 years at 25° C, then it will have a lifetime of 1 year at 160° C.
– Harry Svensson
Nov 25 at 2:49
add a comment |
There are two rules of thumb when it comes to premature aging of electronics and temperature:
Every 10°C above 25°C halves its life
Every 15°C above 25°C halves its life.
The 10°C is derived from a certain application of Arrhenius' equation
$ AF = e^{ frac{E_a}{k}}(frac{1}{T_{use}}- frac{1}{T_{test}}) $
The issue with this is the 10°C result was a very broad interpretation of the empirical results (no consideration was given to other failure modes).
MIL-HDBK-217 took into account field data and concluded that 15°C is a figure more applicable to practical usage
https://www.electronics-cooling.com/2017/08/10c-increase-temperature-really-reduce-life-electronics-half/
I think thatEvery 10°C above 25°C halves its life
is related to chemistry.
– Harry Svensson
Nov 24 at 11:27
I agree, this was then broadly applied. I have been looking into this recently wrt uprating. The problem is the mail is out of date
– JonRB
Nov 24 at 13:16
1
And to just put a number to it. $2^{frac{160-25}{15}}=512$. That means, if the device has a lifetime of 512 years at 25° C, then it will have a lifetime of 1 year at 160° C.
– Harry Svensson
Nov 25 at 2:49
add a comment |
There are two rules of thumb when it comes to premature aging of electronics and temperature:
Every 10°C above 25°C halves its life
Every 15°C above 25°C halves its life.
The 10°C is derived from a certain application of Arrhenius' equation
$ AF = e^{ frac{E_a}{k}}(frac{1}{T_{use}}- frac{1}{T_{test}}) $
The issue with this is the 10°C result was a very broad interpretation of the empirical results (no consideration was given to other failure modes).
MIL-HDBK-217 took into account field data and concluded that 15°C is a figure more applicable to practical usage
https://www.electronics-cooling.com/2017/08/10c-increase-temperature-really-reduce-life-electronics-half/
There are two rules of thumb when it comes to premature aging of electronics and temperature:
Every 10°C above 25°C halves its life
Every 15°C above 25°C halves its life.
The 10°C is derived from a certain application of Arrhenius' equation
$ AF = e^{ frac{E_a}{k}}(frac{1}{T_{use}}- frac{1}{T_{test}}) $
The issue with this is the 10°C result was a very broad interpretation of the empirical results (no consideration was given to other failure modes).
MIL-HDBK-217 took into account field data and concluded that 15°C is a figure more applicable to practical usage
https://www.electronics-cooling.com/2017/08/10c-increase-temperature-really-reduce-life-electronics-half/
edited Nov 23 at 23:47
answered Nov 23 at 23:22
JonRB
13.3k22040
13.3k22040
I think thatEvery 10°C above 25°C halves its life
is related to chemistry.
– Harry Svensson
Nov 24 at 11:27
I agree, this was then broadly applied. I have been looking into this recently wrt uprating. The problem is the mail is out of date
– JonRB
Nov 24 at 13:16
1
And to just put a number to it. $2^{frac{160-25}{15}}=512$. That means, if the device has a lifetime of 512 years at 25° C, then it will have a lifetime of 1 year at 160° C.
– Harry Svensson
Nov 25 at 2:49
add a comment |
I think thatEvery 10°C above 25°C halves its life
is related to chemistry.
– Harry Svensson
Nov 24 at 11:27
I agree, this was then broadly applied. I have been looking into this recently wrt uprating. The problem is the mail is out of date
– JonRB
Nov 24 at 13:16
1
And to just put a number to it. $2^{frac{160-25}{15}}=512$. That means, if the device has a lifetime of 512 years at 25° C, then it will have a lifetime of 1 year at 160° C.
– Harry Svensson
Nov 25 at 2:49
I think that
Every 10°C above 25°C halves its life
is related to chemistry.– Harry Svensson
Nov 24 at 11:27
I think that
Every 10°C above 25°C halves its life
is related to chemistry.– Harry Svensson
Nov 24 at 11:27
I agree, this was then broadly applied. I have been looking into this recently wrt uprating. The problem is the mail is out of date
– JonRB
Nov 24 at 13:16
I agree, this was then broadly applied. I have been looking into this recently wrt uprating. The problem is the mail is out of date
– JonRB
Nov 24 at 13:16
1
1
And to just put a number to it. $2^{frac{160-25}{15}}=512$. That means, if the device has a lifetime of 512 years at 25° C, then it will have a lifetime of 1 year at 160° C.
– Harry Svensson
Nov 25 at 2:49
And to just put a number to it. $2^{frac{160-25}{15}}=512$. That means, if the device has a lifetime of 512 years at 25° C, then it will have a lifetime of 1 year at 160° C.
– Harry Svensson
Nov 25 at 2:49
add a comment |
Thanks for contributing an answer to Electrical Engineering Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f408537%2fic-product-lifetime-as-function-of-junction-temperature%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown