How to simplify this algebraic expression? What is the proper name for this problem?
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I am studying for a teacher exam and I am stumped with this problem $3cdot frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
arithmetic
edited Nov 20 at 21:01
Robert Howard
1,8651822
asked Jul 2 '16 at 14:24
tina
61
|
show 5 more comments
up vote
0
down vote
favorite
I am studying for a teacher exam and I am stumped with this problem $3cdot frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
arithmetic
edited Nov 20 at 21:01
Robert Howard
1,8651822
asked Jul 2 '16 at 14:24
tina
61
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
|
show 5 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am studying for a teacher exam and I am stumped with this problem $3cdot frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
arithmetic
edited Nov 20 at 21:01
Robert Howard
1,8651822
asked Jul 2 '16 at 14:24
tina
61
I am studying for a teacher exam and I am stumped with this problem $3cdot frac{(2+6)^2}{6}$
I know that the answer is $32$ because of the answer sheet, but how and why is this the answer? Can I get an example?
arithmetic
arithmetic
edited Nov 20 at 21:01
Robert Howard
1,8651822
asked Jul 2 '16 at 14:24
tina
61
edited Nov 20 at 21:01
Robert Howard
1,8651822
asked Jul 2 '16 at 14:24
tina
61
edited Nov 20 at 21:01
Robert Howard
1,8651822
edited Nov 20 at 21:01
Robert Howard
1,8651822
edited Nov 20 at 21:01
Robert Howard
1,8651822
1,8651822
asked Jul 2 '16 at 14:24
tina
61
asked Jul 2 '16 at 14:24
tina
61
asked Jul 2 '16 at 14:24
tina
61
61
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
|
show 5 more comments
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
1
1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56
|
show 5 more comments
1 Answer
1
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0
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It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
add a comment |
up vote
0
down vote
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
add a comment |
up vote
0
down vote
up vote
0
down vote
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
It seems that you did find your way to the correct answer, so just to summarize one correct sequence of steps you could take to get there, we have (using the method that callculus described in a comment): $$3cdotfrac{(2+6)^2}{6}=3cdotfrac{8^2}{6}=3cdotfrac{64}{6}=frac{3}{6}cdot64=frac{1}{2}cdot64=32$$
answered Nov 20 at 3:54
community wiki
Robert Howard
add a comment |
add a comment |
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1
Where did you stuck ? Are you able to calculate $(2+6)^2$ ?
– callculus
Jul 2 '16 at 14:25
no I can not remember how to calculate this? its been awhile for me
– tina
Jul 2 '16 at 14:30
OK, what is $2+6$ ?
– callculus
Jul 2 '16 at 14:31
Start by calculating $2+6$.
– user228113
Jul 2 '16 at 14:34
1
Yes. But it might be easiert to first calculate the fraction of 3 and 6: $frac{3}{6}$. Then take the intermediate result of 64 and multiply it by $frac{3}{6}=frac{1}{2}$: $ $ $64cdot frac12=64/2=32$
– callculus
Jul 2 '16 at 14:56