In a saturated solution, why is there ongoing dissolution and crystallisation?











up vote
7
down vote

favorite












I was studying equilibrium, and had this question..



In a saturated solution with sugar dissolved, why is there a constant process of dissolving and crystallising? What I mean by this is, why don't the already dissolved sugar just stay that way, and the excess undissolved sugar stay that way? As I thought this would seem easier, and neater (?), wouldn't it??



Is it because the undissolved sugar is still in water, and that means it will want to dissolve, but since the solvent has reached maximum amount of solutes it has to kick some sugar out and hence there is a process of crystalisation??



I am sorry for a rather stupid question... But any explanation is much, much appreciated...










share|improve this question


















  • 1




    What could cause one of the processes to stop? How would having a lot of dissolved sugar cause sugar to not dissolve, or lots of crystals cause crystallization to stop?
    – Acccumulation
    Nov 19 at 18:46










  • Neater, until you tag the sugar water with radioactive isotope and put untagged sugar crystal in there, and is shocked when you find tagged molecule in the crystal a few minute later.
    – user3528438
    Nov 19 at 21:45















up vote
7
down vote

favorite












I was studying equilibrium, and had this question..



In a saturated solution with sugar dissolved, why is there a constant process of dissolving and crystallising? What I mean by this is, why don't the already dissolved sugar just stay that way, and the excess undissolved sugar stay that way? As I thought this would seem easier, and neater (?), wouldn't it??



Is it because the undissolved sugar is still in water, and that means it will want to dissolve, but since the solvent has reached maximum amount of solutes it has to kick some sugar out and hence there is a process of crystalisation??



I am sorry for a rather stupid question... But any explanation is much, much appreciated...










share|improve this question


















  • 1




    What could cause one of the processes to stop? How would having a lot of dissolved sugar cause sugar to not dissolve, or lots of crystals cause crystallization to stop?
    – Acccumulation
    Nov 19 at 18:46










  • Neater, until you tag the sugar water with radioactive isotope and put untagged sugar crystal in there, and is shocked when you find tagged molecule in the crystal a few minute later.
    – user3528438
    Nov 19 at 21:45













up vote
7
down vote

favorite









up vote
7
down vote

favorite











I was studying equilibrium, and had this question..



In a saturated solution with sugar dissolved, why is there a constant process of dissolving and crystallising? What I mean by this is, why don't the already dissolved sugar just stay that way, and the excess undissolved sugar stay that way? As I thought this would seem easier, and neater (?), wouldn't it??



Is it because the undissolved sugar is still in water, and that means it will want to dissolve, but since the solvent has reached maximum amount of solutes it has to kick some sugar out and hence there is a process of crystalisation??



I am sorry for a rather stupid question... But any explanation is much, much appreciated...










share|improve this question













I was studying equilibrium, and had this question..



In a saturated solution with sugar dissolved, why is there a constant process of dissolving and crystallising? What I mean by this is, why don't the already dissolved sugar just stay that way, and the excess undissolved sugar stay that way? As I thought this would seem easier, and neater (?), wouldn't it??



Is it because the undissolved sugar is still in water, and that means it will want to dissolve, but since the solvent has reached maximum amount of solutes it has to kick some sugar out and hence there is a process of crystalisation??



I am sorry for a rather stupid question... But any explanation is much, much appreciated...







equilibrium






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 19 at 11:51









Brian Kum

444




444








  • 1




    What could cause one of the processes to stop? How would having a lot of dissolved sugar cause sugar to not dissolve, or lots of crystals cause crystallization to stop?
    – Acccumulation
    Nov 19 at 18:46










  • Neater, until you tag the sugar water with radioactive isotope and put untagged sugar crystal in there, and is shocked when you find tagged molecule in the crystal a few minute later.
    – user3528438
    Nov 19 at 21:45














  • 1




    What could cause one of the processes to stop? How would having a lot of dissolved sugar cause sugar to not dissolve, or lots of crystals cause crystallization to stop?
    – Acccumulation
    Nov 19 at 18:46










  • Neater, until you tag the sugar water with radioactive isotope and put untagged sugar crystal in there, and is shocked when you find tagged molecule in the crystal a few minute later.
    – user3528438
    Nov 19 at 21:45








1




1




What could cause one of the processes to stop? How would having a lot of dissolved sugar cause sugar to not dissolve, or lots of crystals cause crystallization to stop?
– Acccumulation
Nov 19 at 18:46




What could cause one of the processes to stop? How would having a lot of dissolved sugar cause sugar to not dissolve, or lots of crystals cause crystallization to stop?
– Acccumulation
Nov 19 at 18:46












Neater, until you tag the sugar water with radioactive isotope and put untagged sugar crystal in there, and is shocked when you find tagged molecule in the crystal a few minute later.
– user3528438
Nov 19 at 21:45




Neater, until you tag the sugar water with radioactive isotope and put untagged sugar crystal in there, and is shocked when you find tagged molecule in the crystal a few minute later.
– user3528438
Nov 19 at 21:45










1 Answer
1






active

oldest

votes

















up vote
19
down vote



accepted










Because equilibrium is dynamic not static



There are many things in the world of chemistry which could be simpler but are not. Equilibrium is one of them.



There are few chemical processes where equilibrium is equivalent to the situation where everything just stops. Equilibrium normally occurs when the rates of processes going forward are the same as the rates going backward, not when things stop happening. In this case the rate of dissolution is the same as the rate of crystallisation.



On a molecular level things are very dynamic. Molecules in the solution are hitting crystals all the time. Molecules in the crystal are vibrating and being hit by molecules of the solvent: sometimes the molecules in the crystal have enough energy to escape from the crystal and go into solution. Equilibrium is the point where those two reactions have equal rates, not where all the activity stops.



We know this is true in real solutions from several experiments. We can, for example, label the molecules in the crystal with radioactive versions of one of their atoms (eg carbon 14). Even if we start with a saturated non-radioactive solution and add radioactive crystals of the same compound, the radioactivity will spread to the solution (see this question Proof of Dynamic Nature of Equilibrium).



The key thing is that all equilibria in chemistry are dynamic. The major difference in many cases is how dynamic. Some happen very slowly, others very quickly. But the position of the equilibrium only has a weak relationship to the speed of the equilibrium.






share|improve this answer





















    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "431"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fchemistry.stackexchange.com%2fquestions%2f104545%2fin-a-saturated-solution-why-is-there-ongoing-dissolution-and-crystallisation%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    19
    down vote



    accepted










    Because equilibrium is dynamic not static



    There are many things in the world of chemistry which could be simpler but are not. Equilibrium is one of them.



    There are few chemical processes where equilibrium is equivalent to the situation where everything just stops. Equilibrium normally occurs when the rates of processes going forward are the same as the rates going backward, not when things stop happening. In this case the rate of dissolution is the same as the rate of crystallisation.



    On a molecular level things are very dynamic. Molecules in the solution are hitting crystals all the time. Molecules in the crystal are vibrating and being hit by molecules of the solvent: sometimes the molecules in the crystal have enough energy to escape from the crystal and go into solution. Equilibrium is the point where those two reactions have equal rates, not where all the activity stops.



    We know this is true in real solutions from several experiments. We can, for example, label the molecules in the crystal with radioactive versions of one of their atoms (eg carbon 14). Even if we start with a saturated non-radioactive solution and add radioactive crystals of the same compound, the radioactivity will spread to the solution (see this question Proof of Dynamic Nature of Equilibrium).



    The key thing is that all equilibria in chemistry are dynamic. The major difference in many cases is how dynamic. Some happen very slowly, others very quickly. But the position of the equilibrium only has a weak relationship to the speed of the equilibrium.






    share|improve this answer

























      up vote
      19
      down vote



      accepted










      Because equilibrium is dynamic not static



      There are many things in the world of chemistry which could be simpler but are not. Equilibrium is one of them.



      There are few chemical processes where equilibrium is equivalent to the situation where everything just stops. Equilibrium normally occurs when the rates of processes going forward are the same as the rates going backward, not when things stop happening. In this case the rate of dissolution is the same as the rate of crystallisation.



      On a molecular level things are very dynamic. Molecules in the solution are hitting crystals all the time. Molecules in the crystal are vibrating and being hit by molecules of the solvent: sometimes the molecules in the crystal have enough energy to escape from the crystal and go into solution. Equilibrium is the point where those two reactions have equal rates, not where all the activity stops.



      We know this is true in real solutions from several experiments. We can, for example, label the molecules in the crystal with radioactive versions of one of their atoms (eg carbon 14). Even if we start with a saturated non-radioactive solution and add radioactive crystals of the same compound, the radioactivity will spread to the solution (see this question Proof of Dynamic Nature of Equilibrium).



      The key thing is that all equilibria in chemistry are dynamic. The major difference in many cases is how dynamic. Some happen very slowly, others very quickly. But the position of the equilibrium only has a weak relationship to the speed of the equilibrium.






      share|improve this answer























        up vote
        19
        down vote



        accepted







        up vote
        19
        down vote



        accepted






        Because equilibrium is dynamic not static



        There are many things in the world of chemistry which could be simpler but are not. Equilibrium is one of them.



        There are few chemical processes where equilibrium is equivalent to the situation where everything just stops. Equilibrium normally occurs when the rates of processes going forward are the same as the rates going backward, not when things stop happening. In this case the rate of dissolution is the same as the rate of crystallisation.



        On a molecular level things are very dynamic. Molecules in the solution are hitting crystals all the time. Molecules in the crystal are vibrating and being hit by molecules of the solvent: sometimes the molecules in the crystal have enough energy to escape from the crystal and go into solution. Equilibrium is the point where those two reactions have equal rates, not where all the activity stops.



        We know this is true in real solutions from several experiments. We can, for example, label the molecules in the crystal with radioactive versions of one of their atoms (eg carbon 14). Even if we start with a saturated non-radioactive solution and add radioactive crystals of the same compound, the radioactivity will spread to the solution (see this question Proof of Dynamic Nature of Equilibrium).



        The key thing is that all equilibria in chemistry are dynamic. The major difference in many cases is how dynamic. Some happen very slowly, others very quickly. But the position of the equilibrium only has a weak relationship to the speed of the equilibrium.






        share|improve this answer












        Because equilibrium is dynamic not static



        There are many things in the world of chemistry which could be simpler but are not. Equilibrium is one of them.



        There are few chemical processes where equilibrium is equivalent to the situation where everything just stops. Equilibrium normally occurs when the rates of processes going forward are the same as the rates going backward, not when things stop happening. In this case the rate of dissolution is the same as the rate of crystallisation.



        On a molecular level things are very dynamic. Molecules in the solution are hitting crystals all the time. Molecules in the crystal are vibrating and being hit by molecules of the solvent: sometimes the molecules in the crystal have enough energy to escape from the crystal and go into solution. Equilibrium is the point where those two reactions have equal rates, not where all the activity stops.



        We know this is true in real solutions from several experiments. We can, for example, label the molecules in the crystal with radioactive versions of one of their atoms (eg carbon 14). Even if we start with a saturated non-radioactive solution and add radioactive crystals of the same compound, the radioactivity will spread to the solution (see this question Proof of Dynamic Nature of Equilibrium).



        The key thing is that all equilibria in chemistry are dynamic. The major difference in many cases is how dynamic. Some happen very slowly, others very quickly. But the position of the equilibrium only has a weak relationship to the speed of the equilibrium.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 19 at 12:59









        matt_black

        17.6k249105




        17.6k249105






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Chemistry Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fchemistry.stackexchange.com%2fquestions%2f104545%2fin-a-saturated-solution-why-is-there-ongoing-dissolution-and-crystallisation%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Quarter-circle Tiles

            build a pushdown automaton that recognizes the reverse language of a given pushdown automaton?

            Mont Emei