What are the almost periodic functions on the complex plane?











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The almost periodic functions on the real line can be characterized as uniform limits of trigonometric functions. I was wondering whether a similar definition exists on the complex plane (a locally compact group under addition).



In particular, I am trying to figure out if there exists a non-constant almost periodic function $f$ on $mathbb{C}$ such that $f$ is invariant under rotations i.e. $f(tz) = f(z)$ for all $tin mathbb{T}$, $zin mathbb{C}$.



Any help is much appreciated.










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    up vote
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    down vote

    favorite












    The almost periodic functions on the real line can be characterized as uniform limits of trigonometric functions. I was wondering whether a similar definition exists on the complex plane (a locally compact group under addition).



    In particular, I am trying to figure out if there exists a non-constant almost periodic function $f$ on $mathbb{C}$ such that $f$ is invariant under rotations i.e. $f(tz) = f(z)$ for all $tin mathbb{T}$, $zin mathbb{C}$.



    Any help is much appreciated.










    share|cite|improve this question


























      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      The almost periodic functions on the real line can be characterized as uniform limits of trigonometric functions. I was wondering whether a similar definition exists on the complex plane (a locally compact group under addition).



      In particular, I am trying to figure out if there exists a non-constant almost periodic function $f$ on $mathbb{C}$ such that $f$ is invariant under rotations i.e. $f(tz) = f(z)$ for all $tin mathbb{T}$, $zin mathbb{C}$.



      Any help is much appreciated.










      share|cite|improve this question















      The almost periodic functions on the real line can be characterized as uniform limits of trigonometric functions. I was wondering whether a similar definition exists on the complex plane (a locally compact group under addition).



      In particular, I am trying to figure out if there exists a non-constant almost periodic function $f$ on $mathbb{C}$ such that $f$ is invariant under rotations i.e. $f(tz) = f(z)$ for all $tin mathbb{T}$, $zin mathbb{C}$.



      Any help is much appreciated.







      fa.functional-analysis fourier-analysis topological-groups abelian-groups almost-periodic-function






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      edited Nov 24 at 0:23









      Arun Debray

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      2,95911438










      asked Nov 24 at 0:13









      Merry

      1161




      1161






















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          Yes to the first question: the almost periodic functions on any LCA group are the uniform limits of linear combinations of characters. In the case of $mathbb{R}^2$ these are the functions $e^{i(ax + by)}$.



          I don't see how that immediately answers your second question, but there is an easy negative answer straight from the definition. Suppose $f$ is a rotationally invariant nonconstant almost periodic function. WLOG $f(0,0) =0$ and $f(1,0) = 1$. So $f$ is constantly $1$ on the unit circle. Now find $t > 1$ such that $f$ and its shift by $(t, 0)$ are uniformly at most $1/3$ apart. Then $f(t,0)$ is within $1/3$ of $0$, so the same must be true at any point on the circle of radius $t$ about the origin. But at the same time, $f$ must be within $1/3$ of $1$ on the circle of radius $1$ about $(t,0)$, and that is contradictory.






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            up vote
            6
            down vote













            Yes to the first question: the almost periodic functions on any LCA group are the uniform limits of linear combinations of characters. In the case of $mathbb{R}^2$ these are the functions $e^{i(ax + by)}$.



            I don't see how that immediately answers your second question, but there is an easy negative answer straight from the definition. Suppose $f$ is a rotationally invariant nonconstant almost periodic function. WLOG $f(0,0) =0$ and $f(1,0) = 1$. So $f$ is constantly $1$ on the unit circle. Now find $t > 1$ such that $f$ and its shift by $(t, 0)$ are uniformly at most $1/3$ apart. Then $f(t,0)$ is within $1/3$ of $0$, so the same must be true at any point on the circle of radius $t$ about the origin. But at the same time, $f$ must be within $1/3$ of $1$ on the circle of radius $1$ about $(t,0)$, and that is contradictory.






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              up vote
              6
              down vote













              Yes to the first question: the almost periodic functions on any LCA group are the uniform limits of linear combinations of characters. In the case of $mathbb{R}^2$ these are the functions $e^{i(ax + by)}$.



              I don't see how that immediately answers your second question, but there is an easy negative answer straight from the definition. Suppose $f$ is a rotationally invariant nonconstant almost periodic function. WLOG $f(0,0) =0$ and $f(1,0) = 1$. So $f$ is constantly $1$ on the unit circle. Now find $t > 1$ such that $f$ and its shift by $(t, 0)$ are uniformly at most $1/3$ apart. Then $f(t,0)$ is within $1/3$ of $0$, so the same must be true at any point on the circle of radius $t$ about the origin. But at the same time, $f$ must be within $1/3$ of $1$ on the circle of radius $1$ about $(t,0)$, and that is contradictory.






              share|cite|improve this answer

























                up vote
                6
                down vote










                up vote
                6
                down vote









                Yes to the first question: the almost periodic functions on any LCA group are the uniform limits of linear combinations of characters. In the case of $mathbb{R}^2$ these are the functions $e^{i(ax + by)}$.



                I don't see how that immediately answers your second question, but there is an easy negative answer straight from the definition. Suppose $f$ is a rotationally invariant nonconstant almost periodic function. WLOG $f(0,0) =0$ and $f(1,0) = 1$. So $f$ is constantly $1$ on the unit circle. Now find $t > 1$ such that $f$ and its shift by $(t, 0)$ are uniformly at most $1/3$ apart. Then $f(t,0)$ is within $1/3$ of $0$, so the same must be true at any point on the circle of radius $t$ about the origin. But at the same time, $f$ must be within $1/3$ of $1$ on the circle of radius $1$ about $(t,0)$, and that is contradictory.






                share|cite|improve this answer














                Yes to the first question: the almost periodic functions on any LCA group are the uniform limits of linear combinations of characters. In the case of $mathbb{R}^2$ these are the functions $e^{i(ax + by)}$.



                I don't see how that immediately answers your second question, but there is an easy negative answer straight from the definition. Suppose $f$ is a rotationally invariant nonconstant almost periodic function. WLOG $f(0,0) =0$ and $f(1,0) = 1$. So $f$ is constantly $1$ on the unit circle. Now find $t > 1$ such that $f$ and its shift by $(t, 0)$ are uniformly at most $1/3$ apart. Then $f(t,0)$ is within $1/3$ of $0$, so the same must be true at any point on the circle of radius $t$ about the origin. But at the same time, $f$ must be within $1/3$ of $1$ on the circle of radius $1$ about $(t,0)$, and that is contradictory.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Nov 24 at 2:09

























                answered Nov 24 at 1:30









                Nik Weaver

                19.5k145121




                19.5k145121






























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