Unable to understand this expression












0














enter image description here



I am unable to understand the above expression from the 3rd line onwards. Why is P(A|q1...qt-1)P(q1..q-1) = P(A|qt-1)P(q1..q-1)



I am not clear of the subsequent line as well






bayes-theorem







share|cite|improve this question






















  • Is this from a Markov process?
    – gd1035
    Nov 29 '18 at 21:59










  • I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
    – fleablood
    Nov 29 '18 at 22:02










  • yes its about Markov process
    – user1436508
    Nov 29 '18 at 22:15
















0














enter image description here



I am unable to understand the above expression from the 3rd line onwards. Why is P(A|q1...qt-1)P(q1..q-1) = P(A|qt-1)P(q1..q-1)



I am not clear of the subsequent line as well






bayes-theorem







share|cite|improve this question






















  • Is this from a Markov process?
    – gd1035
    Nov 29 '18 at 21:59










  • I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
    – fleablood
    Nov 29 '18 at 22:02










  • yes its about Markov process
    – user1436508
    Nov 29 '18 at 22:15














0












0








0







enter image description here



I am unable to understand the above expression from the 3rd line onwards. Why is P(A|q1...qt-1)P(q1..q-1) = P(A|qt-1)P(q1..q-1)



I am not clear of the subsequent line as well






bayes-theorem







share|cite|improve this question













enter image description here



I am unable to understand the above expression from the 3rd line onwards. Why is P(A|q1...qt-1)P(q1..q-1) = P(A|qt-1)P(q1..q-1)



I am not clear of the subsequent line as well






bayes-theorem




bayes-theorem






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 29 '18 at 21:54









user1436508user1436508

1538




1538












  • Is this from a Markov process?
    – gd1035
    Nov 29 '18 at 21:59










  • I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
    – fleablood
    Nov 29 '18 at 22:02










  • yes its about Markov process
    – user1436508
    Nov 29 '18 at 22:15


















  • Is this from a Markov process?
    – gd1035
    Nov 29 '18 at 21:59










  • I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
    – fleablood
    Nov 29 '18 at 22:02










  • yes its about Markov process
    – user1436508
    Nov 29 '18 at 22:15
















Is this from a Markov process?
– gd1035
Nov 29 '18 at 21:59




Is this from a Markov process?
– gd1035
Nov 29 '18 at 21:59












I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
– fleablood
Nov 29 '18 at 22:02




I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
– fleablood
Nov 29 '18 at 22:02












yes its about Markov process
– user1436508
Nov 29 '18 at 22:15




yes its about Markov process
– user1436508
Nov 29 '18 at 22:15










1 Answer
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This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.



See link for more information about this property.






share|cite|improve this answer





















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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.



    See link for more information about this property.






    share|cite|improve this answer


























      0














      This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.



      See link for more information about this property.






      share|cite|improve this answer
























        0












        0








        0






        This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.



        See link for more information about this property.






        share|cite|improve this answer












        This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.



        See link for more information about this property.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 29 '18 at 23:12









        gd1035gd1035

        4591210




        4591210






























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