How many primes of the form $2^p-p$ with $p$ prime?












5












$begingroup$


I know that if $p = 6k+1$ with $k$ integer, then $(2^p-p) mod 6 equiv 1$. I think that this means that $2^p-p$ could be prime. My question is: are there a finite or infinite number of primes which can be written like this?










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$endgroup$












  • $begingroup$
    Note: All primes after 3 can be written in the form of $6k+1$ and $6k-1$
    $endgroup$
    – user371530
    Oct 23 '16 at 1:27










  • $begingroup$
    Also worth noting that non-prime may work: $2^9-9=503$ is prime
    $endgroup$
    – Joffan
    Oct 23 '16 at 1:51






  • 2




    $begingroup$
    oeis.org/A048744 gives the first $23$ values of $n$ for which $2^n-n$ is prime, including the prime values $n=2,3,13,19$, and $481801$.
    $endgroup$
    – Barry Cipra
    Nov 22 '16 at 23:05
















5












$begingroup$


I know that if $p = 6k+1$ with $k$ integer, then $(2^p-p) mod 6 equiv 1$. I think that this means that $2^p-p$ could be prime. My question is: are there a finite or infinite number of primes which can be written like this?










share|cite|improve this question











$endgroup$












  • $begingroup$
    Note: All primes after 3 can be written in the form of $6k+1$ and $6k-1$
    $endgroup$
    – user371530
    Oct 23 '16 at 1:27










  • $begingroup$
    Also worth noting that non-prime may work: $2^9-9=503$ is prime
    $endgroup$
    – Joffan
    Oct 23 '16 at 1:51






  • 2




    $begingroup$
    oeis.org/A048744 gives the first $23$ values of $n$ for which $2^n-n$ is prime, including the prime values $n=2,3,13,19$, and $481801$.
    $endgroup$
    – Barry Cipra
    Nov 22 '16 at 23:05














5












5








5


1



$begingroup$


I know that if $p = 6k+1$ with $k$ integer, then $(2^p-p) mod 6 equiv 1$. I think that this means that $2^p-p$ could be prime. My question is: are there a finite or infinite number of primes which can be written like this?










share|cite|improve this question











$endgroup$




I know that if $p = 6k+1$ with $k$ integer, then $(2^p-p) mod 6 equiv 1$. I think that this means that $2^p-p$ could be prime. My question is: are there a finite or infinite number of primes which can be written like this?







number-theory prime-numbers






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jun 18 '17 at 15:54









jvdhooft

5,57561641




5,57561641










asked Oct 23 '16 at 1:21









O. ArcilaO. Arcila

757




757












  • $begingroup$
    Note: All primes after 3 can be written in the form of $6k+1$ and $6k-1$
    $endgroup$
    – user371530
    Oct 23 '16 at 1:27










  • $begingroup$
    Also worth noting that non-prime may work: $2^9-9=503$ is prime
    $endgroup$
    – Joffan
    Oct 23 '16 at 1:51






  • 2




    $begingroup$
    oeis.org/A048744 gives the first $23$ values of $n$ for which $2^n-n$ is prime, including the prime values $n=2,3,13,19$, and $481801$.
    $endgroup$
    – Barry Cipra
    Nov 22 '16 at 23:05


















  • $begingroup$
    Note: All primes after 3 can be written in the form of $6k+1$ and $6k-1$
    $endgroup$
    – user371530
    Oct 23 '16 at 1:27










  • $begingroup$
    Also worth noting that non-prime may work: $2^9-9=503$ is prime
    $endgroup$
    – Joffan
    Oct 23 '16 at 1:51






  • 2




    $begingroup$
    oeis.org/A048744 gives the first $23$ values of $n$ for which $2^n-n$ is prime, including the prime values $n=2,3,13,19$, and $481801$.
    $endgroup$
    – Barry Cipra
    Nov 22 '16 at 23:05
















$begingroup$
Note: All primes after 3 can be written in the form of $6k+1$ and $6k-1$
$endgroup$
– user371530
Oct 23 '16 at 1:27




$begingroup$
Note: All primes after 3 can be written in the form of $6k+1$ and $6k-1$
$endgroup$
– user371530
Oct 23 '16 at 1:27












$begingroup$
Also worth noting that non-prime may work: $2^9-9=503$ is prime
$endgroup$
– Joffan
Oct 23 '16 at 1:51




$begingroup$
Also worth noting that non-prime may work: $2^9-9=503$ is prime
$endgroup$
– Joffan
Oct 23 '16 at 1:51




2




2




$begingroup$
oeis.org/A048744 gives the first $23$ values of $n$ for which $2^n-n$ is prime, including the prime values $n=2,3,13,19$, and $481801$.
$endgroup$
– Barry Cipra
Nov 22 '16 at 23:05




$begingroup$
oeis.org/A048744 gives the first $23$ values of $n$ for which $2^n-n$ is prime, including the prime values $n=2,3,13,19$, and $481801$.
$endgroup$
– Barry Cipra
Nov 22 '16 at 23:05










1 Answer
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At this moment I do not have complete explanation of your question but with the use of my own properties of primes which I discovered last year I made a conclusion i.e.:



If (2p - 5) and (2p + 5) are primes than (2p - a) and (2p + a) are also primes only and only if "a" is a multiple of 5(which is rare but can come) or "a" is a prime number maybe "p" also.



7 also show similar property in (2p - 7) and (2p + 7)






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    1 Answer
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    1 Answer
    1






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    oldest

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    0












    $begingroup$



    At this moment I do not have complete explanation of your question but with the use of my own properties of primes which I discovered last year I made a conclusion i.e.:



    If (2p - 5) and (2p + 5) are primes than (2p - a) and (2p + a) are also primes only and only if "a" is a multiple of 5(which is rare but can come) or "a" is a prime number maybe "p" also.



    7 also show similar property in (2p - 7) and (2p + 7)






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$



      At this moment I do not have complete explanation of your question but with the use of my own properties of primes which I discovered last year I made a conclusion i.e.:



      If (2p - 5) and (2p + 5) are primes than (2p - a) and (2p + a) are also primes only and only if "a" is a multiple of 5(which is rare but can come) or "a" is a prime number maybe "p" also.



      7 also show similar property in (2p - 7) and (2p + 7)






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$



        At this moment I do not have complete explanation of your question but with the use of my own properties of primes which I discovered last year I made a conclusion i.e.:



        If (2p - 5) and (2p + 5) are primes than (2p - a) and (2p + a) are also primes only and only if "a" is a multiple of 5(which is rare but can come) or "a" is a prime number maybe "p" also.



        7 also show similar property in (2p - 7) and (2p + 7)






        share|cite|improve this answer









        $endgroup$





        At this moment I do not have complete explanation of your question but with the use of my own properties of primes which I discovered last year I made a conclusion i.e.:



        If (2p - 5) and (2p + 5) are primes than (2p - a) and (2p + a) are also primes only and only if "a" is a multiple of 5(which is rare but can come) or "a" is a prime number maybe "p" also.



        7 also show similar property in (2p - 7) and (2p + 7)







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 18 '18 at 21:03









        DynamoDynamo

        104517




        104517






























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