Mean and variance of beta looking distribution












1












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From lecture notes on SDE's. I have calculated a stationary distribution of an SDE from the forward kolmogorov equation. I can not, however, identify this distribution and I want to find the mean and variance. The pdf is.



$f(x)=frac{(x^2+1)^{-left(frac{sigma^2+lambda}{sigma^2} right)}Gammaleft( frac{sigma^2+lambda}{sigma^2}right)}{sqrt{pi}Gammaleft(-frac{1}{2}+frac{sigma^2+lambda}{sigma^2} right)}$



Where $lambda,sigma$ are real scalars and $Gamma$ is the gamma function. It looks like a beta-distribution, but I cannot wrangle it into a form where it yields it's mean and variance?










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  • 1




    $begingroup$
    It's a Student $t$, actually. That'll give what you need.
    $endgroup$
    – J.G.
    Dec 19 '18 at 0:19












  • $begingroup$
    That is exactly what it is, thank you so much!
    $endgroup$
    – thaumoctopus
    Dec 19 '18 at 0:20






  • 1




    $begingroup$
    I think strictly it may be a scaled Student $t$. In any case if $lambda=0$ it is a Cauchy distribution with no mean, and if $0 lt lambda le sigma^2$ then it has no variance
    $endgroup$
    – Henry
    Dec 19 '18 at 0:22
















1












$begingroup$


From lecture notes on SDE's. I have calculated a stationary distribution of an SDE from the forward kolmogorov equation. I can not, however, identify this distribution and I want to find the mean and variance. The pdf is.



$f(x)=frac{(x^2+1)^{-left(frac{sigma^2+lambda}{sigma^2} right)}Gammaleft( frac{sigma^2+lambda}{sigma^2}right)}{sqrt{pi}Gammaleft(-frac{1}{2}+frac{sigma^2+lambda}{sigma^2} right)}$



Where $lambda,sigma$ are real scalars and $Gamma$ is the gamma function. It looks like a beta-distribution, but I cannot wrangle it into a form where it yields it's mean and variance?










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    It's a Student $t$, actually. That'll give what you need.
    $endgroup$
    – J.G.
    Dec 19 '18 at 0:19












  • $begingroup$
    That is exactly what it is, thank you so much!
    $endgroup$
    – thaumoctopus
    Dec 19 '18 at 0:20






  • 1




    $begingroup$
    I think strictly it may be a scaled Student $t$. In any case if $lambda=0$ it is a Cauchy distribution with no mean, and if $0 lt lambda le sigma^2$ then it has no variance
    $endgroup$
    – Henry
    Dec 19 '18 at 0:22














1












1








1





$begingroup$


From lecture notes on SDE's. I have calculated a stationary distribution of an SDE from the forward kolmogorov equation. I can not, however, identify this distribution and I want to find the mean and variance. The pdf is.



$f(x)=frac{(x^2+1)^{-left(frac{sigma^2+lambda}{sigma^2} right)}Gammaleft( frac{sigma^2+lambda}{sigma^2}right)}{sqrt{pi}Gammaleft(-frac{1}{2}+frac{sigma^2+lambda}{sigma^2} right)}$



Where $lambda,sigma$ are real scalars and $Gamma$ is the gamma function. It looks like a beta-distribution, but I cannot wrangle it into a form where it yields it's mean and variance?










share|cite|improve this question











$endgroup$




From lecture notes on SDE's. I have calculated a stationary distribution of an SDE from the forward kolmogorov equation. I can not, however, identify this distribution and I want to find the mean and variance. The pdf is.



$f(x)=frac{(x^2+1)^{-left(frac{sigma^2+lambda}{sigma^2} right)}Gammaleft( frac{sigma^2+lambda}{sigma^2}right)}{sqrt{pi}Gammaleft(-frac{1}{2}+frac{sigma^2+lambda}{sigma^2} right)}$



Where $lambda,sigma$ are real scalars and $Gamma$ is the gamma function. It looks like a beta-distribution, but I cannot wrangle it into a form where it yields it's mean and variance?







probability probability-theory probability-distributions stochastic-processes stochastic-calculus






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 19 '18 at 0:11







thaumoctopus

















asked Dec 18 '18 at 23:54









thaumoctopusthaumoctopus

9519




9519








  • 1




    $begingroup$
    It's a Student $t$, actually. That'll give what you need.
    $endgroup$
    – J.G.
    Dec 19 '18 at 0:19












  • $begingroup$
    That is exactly what it is, thank you so much!
    $endgroup$
    – thaumoctopus
    Dec 19 '18 at 0:20






  • 1




    $begingroup$
    I think strictly it may be a scaled Student $t$. In any case if $lambda=0$ it is a Cauchy distribution with no mean, and if $0 lt lambda le sigma^2$ then it has no variance
    $endgroup$
    – Henry
    Dec 19 '18 at 0:22














  • 1




    $begingroup$
    It's a Student $t$, actually. That'll give what you need.
    $endgroup$
    – J.G.
    Dec 19 '18 at 0:19












  • $begingroup$
    That is exactly what it is, thank you so much!
    $endgroup$
    – thaumoctopus
    Dec 19 '18 at 0:20






  • 1




    $begingroup$
    I think strictly it may be a scaled Student $t$. In any case if $lambda=0$ it is a Cauchy distribution with no mean, and if $0 lt lambda le sigma^2$ then it has no variance
    $endgroup$
    – Henry
    Dec 19 '18 at 0:22








1




1




$begingroup$
It's a Student $t$, actually. That'll give what you need.
$endgroup$
– J.G.
Dec 19 '18 at 0:19






$begingroup$
It's a Student $t$, actually. That'll give what you need.
$endgroup$
– J.G.
Dec 19 '18 at 0:19














$begingroup$
That is exactly what it is, thank you so much!
$endgroup$
– thaumoctopus
Dec 19 '18 at 0:20




$begingroup$
That is exactly what it is, thank you so much!
$endgroup$
– thaumoctopus
Dec 19 '18 at 0:20




1




1




$begingroup$
I think strictly it may be a scaled Student $t$. In any case if $lambda=0$ it is a Cauchy distribution with no mean, and if $0 lt lambda le sigma^2$ then it has no variance
$endgroup$
– Henry
Dec 19 '18 at 0:22




$begingroup$
I think strictly it may be a scaled Student $t$. In any case if $lambda=0$ it is a Cauchy distribution with no mean, and if $0 lt lambda le sigma^2$ then it has no variance
$endgroup$
– Henry
Dec 19 '18 at 0:22










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