Isn't Combination just selection?
$begingroup$
So,
There is this question which I came across.
"Total no of handshakes among 15 people."
The answer seems to be just 15C2.
Isn't that just a way of selecting and not the number of handshakes?
I'm in grade 10th. So don't judge.
combinations
$endgroup$
add a comment |
$begingroup$
So,
There is this question which I came across.
"Total no of handshakes among 15 people."
The answer seems to be just 15C2.
Isn't that just a way of selecting and not the number of handshakes?
I'm in grade 10th. So don't judge.
combinations
$endgroup$
add a comment |
$begingroup$
So,
There is this question which I came across.
"Total no of handshakes among 15 people."
The answer seems to be just 15C2.
Isn't that just a way of selecting and not the number of handshakes?
I'm in grade 10th. So don't judge.
combinations
$endgroup$
So,
There is this question which I came across.
"Total no of handshakes among 15 people."
The answer seems to be just 15C2.
Isn't that just a way of selecting and not the number of handshakes?
I'm in grade 10th. So don't judge.
combinations
combinations
edited Dec 16 '18 at 8:34
Eevee Trainer
5,9761936
5,9761936
asked Dec 16 '18 at 8:26
Jaimeblt1Jaimeblt1
82
82
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
I mean, $_{15}C_2$ gives a numerical result as well even if describes a method of selection:
$$_{15}C_2 = frac{15!}{2! cdot (15-2)!}$$
and generally
$$_{n}C_r = frac{n!}{r! cdot (n-r)!}$$
Do the calculations and boom, a number. $_{n}C_r$ is just a notation representing the underlying number (or, rather, the calculations leading up to that number), because who wants to write that fraction every single time?
$endgroup$
$begingroup$
I'm not quite sure. 15C2 in literal terms means, you select 2 objects out of 15. Nowhere does it say that selection is equal to the number of handshakes. Pardon if i'm missing something obvious.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:33
$begingroup$
What are you unsure about?
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:34
$begingroup$
Check it out. I edited it.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:39
$begingroup$
No, $_{15}C_2$ represents the number of ways in which you can choose $2$ objects from $15$. It does not mean "choose a single pair of $2$ from $15$" - it means the number of ways in whichiyou can choose those pairs. I guess, yes, you could argue that in the sense of languages and the usual connotation in English it means to choose $2$ from $15$, but if you go on to study math one day in more depth you'll realize that the mathematical meaning and the common/everyday meaning may differ greatly.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
Mathematicians make very poor poets, so to speak, and can suck at developing intuitive, not-confusing notations/conventions for various things. But either way, that's just how mathematical notation and standards have developed.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
|
show 1 more comment
$begingroup$
$_{15}C_2$ is the number of ways to select 2 people from 15 people (when order doesn't matter). This is exactly the number of handshakes that occur if $15$ people all shake hands with each other. There is one handshake for each set of 2 people.
$endgroup$
add a comment |
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2 Answers
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2 Answers
2
active
oldest
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$begingroup$
I mean, $_{15}C_2$ gives a numerical result as well even if describes a method of selection:
$$_{15}C_2 = frac{15!}{2! cdot (15-2)!}$$
and generally
$$_{n}C_r = frac{n!}{r! cdot (n-r)!}$$
Do the calculations and boom, a number. $_{n}C_r$ is just a notation representing the underlying number (or, rather, the calculations leading up to that number), because who wants to write that fraction every single time?
$endgroup$
$begingroup$
I'm not quite sure. 15C2 in literal terms means, you select 2 objects out of 15. Nowhere does it say that selection is equal to the number of handshakes. Pardon if i'm missing something obvious.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:33
$begingroup$
What are you unsure about?
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:34
$begingroup$
Check it out. I edited it.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:39
$begingroup$
No, $_{15}C_2$ represents the number of ways in which you can choose $2$ objects from $15$. It does not mean "choose a single pair of $2$ from $15$" - it means the number of ways in whichiyou can choose those pairs. I guess, yes, you could argue that in the sense of languages and the usual connotation in English it means to choose $2$ from $15$, but if you go on to study math one day in more depth you'll realize that the mathematical meaning and the common/everyday meaning may differ greatly.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
Mathematicians make very poor poets, so to speak, and can suck at developing intuitive, not-confusing notations/conventions for various things. But either way, that's just how mathematical notation and standards have developed.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
|
show 1 more comment
$begingroup$
I mean, $_{15}C_2$ gives a numerical result as well even if describes a method of selection:
$$_{15}C_2 = frac{15!}{2! cdot (15-2)!}$$
and generally
$$_{n}C_r = frac{n!}{r! cdot (n-r)!}$$
Do the calculations and boom, a number. $_{n}C_r$ is just a notation representing the underlying number (or, rather, the calculations leading up to that number), because who wants to write that fraction every single time?
$endgroup$
$begingroup$
I'm not quite sure. 15C2 in literal terms means, you select 2 objects out of 15. Nowhere does it say that selection is equal to the number of handshakes. Pardon if i'm missing something obvious.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:33
$begingroup$
What are you unsure about?
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:34
$begingroup$
Check it out. I edited it.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:39
$begingroup$
No, $_{15}C_2$ represents the number of ways in which you can choose $2$ objects from $15$. It does not mean "choose a single pair of $2$ from $15$" - it means the number of ways in whichiyou can choose those pairs. I guess, yes, you could argue that in the sense of languages and the usual connotation in English it means to choose $2$ from $15$, but if you go on to study math one day in more depth you'll realize that the mathematical meaning and the common/everyday meaning may differ greatly.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
Mathematicians make very poor poets, so to speak, and can suck at developing intuitive, not-confusing notations/conventions for various things. But either way, that's just how mathematical notation and standards have developed.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
|
show 1 more comment
$begingroup$
I mean, $_{15}C_2$ gives a numerical result as well even if describes a method of selection:
$$_{15}C_2 = frac{15!}{2! cdot (15-2)!}$$
and generally
$$_{n}C_r = frac{n!}{r! cdot (n-r)!}$$
Do the calculations and boom, a number. $_{n}C_r$ is just a notation representing the underlying number (or, rather, the calculations leading up to that number), because who wants to write that fraction every single time?
$endgroup$
I mean, $_{15}C_2$ gives a numerical result as well even if describes a method of selection:
$$_{15}C_2 = frac{15!}{2! cdot (15-2)!}$$
and generally
$$_{n}C_r = frac{n!}{r! cdot (n-r)!}$$
Do the calculations and boom, a number. $_{n}C_r$ is just a notation representing the underlying number (or, rather, the calculations leading up to that number), because who wants to write that fraction every single time?
answered Dec 16 '18 at 8:29
Eevee TrainerEevee Trainer
5,9761936
5,9761936
$begingroup$
I'm not quite sure. 15C2 in literal terms means, you select 2 objects out of 15. Nowhere does it say that selection is equal to the number of handshakes. Pardon if i'm missing something obvious.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:33
$begingroup$
What are you unsure about?
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:34
$begingroup$
Check it out. I edited it.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:39
$begingroup$
No, $_{15}C_2$ represents the number of ways in which you can choose $2$ objects from $15$. It does not mean "choose a single pair of $2$ from $15$" - it means the number of ways in whichiyou can choose those pairs. I guess, yes, you could argue that in the sense of languages and the usual connotation in English it means to choose $2$ from $15$, but if you go on to study math one day in more depth you'll realize that the mathematical meaning and the common/everyday meaning may differ greatly.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
Mathematicians make very poor poets, so to speak, and can suck at developing intuitive, not-confusing notations/conventions for various things. But either way, that's just how mathematical notation and standards have developed.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
|
show 1 more comment
$begingroup$
I'm not quite sure. 15C2 in literal terms means, you select 2 objects out of 15. Nowhere does it say that selection is equal to the number of handshakes. Pardon if i'm missing something obvious.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:33
$begingroup$
What are you unsure about?
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:34
$begingroup$
Check it out. I edited it.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:39
$begingroup$
No, $_{15}C_2$ represents the number of ways in which you can choose $2$ objects from $15$. It does not mean "choose a single pair of $2$ from $15$" - it means the number of ways in whichiyou can choose those pairs. I guess, yes, you could argue that in the sense of languages and the usual connotation in English it means to choose $2$ from $15$, but if you go on to study math one day in more depth you'll realize that the mathematical meaning and the common/everyday meaning may differ greatly.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
Mathematicians make very poor poets, so to speak, and can suck at developing intuitive, not-confusing notations/conventions for various things. But either way, that's just how mathematical notation and standards have developed.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
I'm not quite sure. 15C2 in literal terms means, you select 2 objects out of 15. Nowhere does it say that selection is equal to the number of handshakes. Pardon if i'm missing something obvious.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:33
$begingroup$
I'm not quite sure. 15C2 in literal terms means, you select 2 objects out of 15. Nowhere does it say that selection is equal to the number of handshakes. Pardon if i'm missing something obvious.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:33
$begingroup$
What are you unsure about?
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:34
$begingroup$
What are you unsure about?
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:34
$begingroup$
Check it out. I edited it.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:39
$begingroup$
Check it out. I edited it.
$endgroup$
– Jaimeblt1
Dec 16 '18 at 8:39
$begingroup$
No, $_{15}C_2$ represents the number of ways in which you can choose $2$ objects from $15$. It does not mean "choose a single pair of $2$ from $15$" - it means the number of ways in whichiyou can choose those pairs. I guess, yes, you could argue that in the sense of languages and the usual connotation in English it means to choose $2$ from $15$, but if you go on to study math one day in more depth you'll realize that the mathematical meaning and the common/everyday meaning may differ greatly.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
No, $_{15}C_2$ represents the number of ways in which you can choose $2$ objects from $15$. It does not mean "choose a single pair of $2$ from $15$" - it means the number of ways in whichiyou can choose those pairs. I guess, yes, you could argue that in the sense of languages and the usual connotation in English it means to choose $2$ from $15$, but if you go on to study math one day in more depth you'll realize that the mathematical meaning and the common/everyday meaning may differ greatly.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
Mathematicians make very poor poets, so to speak, and can suck at developing intuitive, not-confusing notations/conventions for various things. But either way, that's just how mathematical notation and standards have developed.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
$begingroup$
Mathematicians make very poor poets, so to speak, and can suck at developing intuitive, not-confusing notations/conventions for various things. But either way, that's just how mathematical notation and standards have developed.
$endgroup$
– Eevee Trainer
Dec 16 '18 at 8:43
|
show 1 more comment
$begingroup$
$_{15}C_2$ is the number of ways to select 2 people from 15 people (when order doesn't matter). This is exactly the number of handshakes that occur if $15$ people all shake hands with each other. There is one handshake for each set of 2 people.
$endgroup$
add a comment |
$begingroup$
$_{15}C_2$ is the number of ways to select 2 people from 15 people (when order doesn't matter). This is exactly the number of handshakes that occur if $15$ people all shake hands with each other. There is one handshake for each set of 2 people.
$endgroup$
add a comment |
$begingroup$
$_{15}C_2$ is the number of ways to select 2 people from 15 people (when order doesn't matter). This is exactly the number of handshakes that occur if $15$ people all shake hands with each other. There is one handshake for each set of 2 people.
$endgroup$
$_{15}C_2$ is the number of ways to select 2 people from 15 people (when order doesn't matter). This is exactly the number of handshakes that occur if $15$ people all shake hands with each other. There is one handshake for each set of 2 people.
answered Dec 16 '18 at 8:35
littleOlittleO
29.8k646109
29.8k646109
add a comment |
add a comment |
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