How to get the first variation of a complex lagrangian?











up vote
1
down vote

favorite












How do I get the first variation for this:
$$ int_C Lleft(z,phi,frac{mathrm{d}phi}{mathrm{d}z}right)mathrm{d}z$$
where:
$$z=x+iy,$$
$$mathrm{d}z=mathrm{d}x+imathrm{d}y,$$
$$phi=f(x,y)+ig(x,y).$$
The integral is a complex line integral and $phi$ is an analytical function.
I'm not sure whether the process is identical to that of real analysis. Is it even possible to get such a variation? Does it even make any sense?










share|cite|improve this question




























    up vote
    1
    down vote

    favorite












    How do I get the first variation for this:
    $$ int_C Lleft(z,phi,frac{mathrm{d}phi}{mathrm{d}z}right)mathrm{d}z$$
    where:
    $$z=x+iy,$$
    $$mathrm{d}z=mathrm{d}x+imathrm{d}y,$$
    $$phi=f(x,y)+ig(x,y).$$
    The integral is a complex line integral and $phi$ is an analytical function.
    I'm not sure whether the process is identical to that of real analysis. Is it even possible to get such a variation? Does it even make any sense?










    share|cite|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      How do I get the first variation for this:
      $$ int_C Lleft(z,phi,frac{mathrm{d}phi}{mathrm{d}z}right)mathrm{d}z$$
      where:
      $$z=x+iy,$$
      $$mathrm{d}z=mathrm{d}x+imathrm{d}y,$$
      $$phi=f(x,y)+ig(x,y).$$
      The integral is a complex line integral and $phi$ is an analytical function.
      I'm not sure whether the process is identical to that of real analysis. Is it even possible to get such a variation? Does it even make any sense?










      share|cite|improve this question















      How do I get the first variation for this:
      $$ int_C Lleft(z,phi,frac{mathrm{d}phi}{mathrm{d}z}right)mathrm{d}z$$
      where:
      $$z=x+iy,$$
      $$mathrm{d}z=mathrm{d}x+imathrm{d}y,$$
      $$phi=f(x,y)+ig(x,y).$$
      The integral is a complex line integral and $phi$ is an analytical function.
      I'm not sure whether the process is identical to that of real analysis. Is it even possible to get such a variation? Does it even make any sense?







      complex-analysis calculus-of-variations






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Nov 22 at 13:04









      amWhy

      191k27223438




      191k27223438










      asked Nov 18 at 13:27









      BinaryBurst

      356110




      356110



























          active

          oldest

          votes











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














           

          draft saved


          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3003529%2fhow-to-get-the-first-variation-of-a-complex-lagrangian%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown






























          active

          oldest

          votes













          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















           

          draft saved


          draft discarded



















































           


          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3003529%2fhow-to-get-the-first-variation-of-a-complex-lagrangian%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Mont Emei

          Province de Neuquén

          Nastassja Kinski