Kilogram of steel v’s a kilogram of feathers











up vote
6
down vote

favorite












I’m really really sorry about this but i’m Having a discussion at the moment regarding a mass of one kilogram of feathers and one kilogram of steel.



The person i’m Arguing with states that one kilogram of feathers will be lighter when weighed against the one kilogram of steel because the feathers are more buoyant.



She has done her calculations for the density of feathers and works out that 1 kilogram of feathers will displace 400 litres of water. And because the feathers are more buoyant than the steel they would actually weigh less.



We are talking about a kilogram of feathers as mass, not weight.



The argument goes that if a scale balanced perfectly in a vacuum, it would not in air. The feathers being more buoyant in air would cause the scale to tip towards the steel.



I’m sure she is wrong, and even though buoyancy may be a factor, she calculates that the feathers would only be almost half their weight in air than they are in a vacuum.



So the question is...



If equal masses of 1 kilogram of feathers and steel were balanced in a vacuum, would they still balance in 1 atmosphere. And what would be the difference in weight?



Can you help me resolve this and tell me if buoyancy is a factor, and if so by how much?



Thank you.










share|cite|improve this question









New contributor




James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Do the test in water
    – user6760
    4 hours ago















up vote
6
down vote

favorite












I’m really really sorry about this but i’m Having a discussion at the moment regarding a mass of one kilogram of feathers and one kilogram of steel.



The person i’m Arguing with states that one kilogram of feathers will be lighter when weighed against the one kilogram of steel because the feathers are more buoyant.



She has done her calculations for the density of feathers and works out that 1 kilogram of feathers will displace 400 litres of water. And because the feathers are more buoyant than the steel they would actually weigh less.



We are talking about a kilogram of feathers as mass, not weight.



The argument goes that if a scale balanced perfectly in a vacuum, it would not in air. The feathers being more buoyant in air would cause the scale to tip towards the steel.



I’m sure she is wrong, and even though buoyancy may be a factor, she calculates that the feathers would only be almost half their weight in air than they are in a vacuum.



So the question is...



If equal masses of 1 kilogram of feathers and steel were balanced in a vacuum, would they still balance in 1 atmosphere. And what would be the difference in weight?



Can you help me resolve this and tell me if buoyancy is a factor, and if so by how much?



Thank you.










share|cite|improve this question









New contributor




James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Do the test in water
    – user6760
    4 hours ago













up vote
6
down vote

favorite









up vote
6
down vote

favorite











I’m really really sorry about this but i’m Having a discussion at the moment regarding a mass of one kilogram of feathers and one kilogram of steel.



The person i’m Arguing with states that one kilogram of feathers will be lighter when weighed against the one kilogram of steel because the feathers are more buoyant.



She has done her calculations for the density of feathers and works out that 1 kilogram of feathers will displace 400 litres of water. And because the feathers are more buoyant than the steel they would actually weigh less.



We are talking about a kilogram of feathers as mass, not weight.



The argument goes that if a scale balanced perfectly in a vacuum, it would not in air. The feathers being more buoyant in air would cause the scale to tip towards the steel.



I’m sure she is wrong, and even though buoyancy may be a factor, she calculates that the feathers would only be almost half their weight in air than they are in a vacuum.



So the question is...



If equal masses of 1 kilogram of feathers and steel were balanced in a vacuum, would they still balance in 1 atmosphere. And what would be the difference in weight?



Can you help me resolve this and tell me if buoyancy is a factor, and if so by how much?



Thank you.










share|cite|improve this question









New contributor




James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I’m really really sorry about this but i’m Having a discussion at the moment regarding a mass of one kilogram of feathers and one kilogram of steel.



The person i’m Arguing with states that one kilogram of feathers will be lighter when weighed against the one kilogram of steel because the feathers are more buoyant.



She has done her calculations for the density of feathers and works out that 1 kilogram of feathers will displace 400 litres of water. And because the feathers are more buoyant than the steel they would actually weigh less.



We are talking about a kilogram of feathers as mass, not weight.



The argument goes that if a scale balanced perfectly in a vacuum, it would not in air. The feathers being more buoyant in air would cause the scale to tip towards the steel.



I’m sure she is wrong, and even though buoyancy may be a factor, she calculates that the feathers would only be almost half their weight in air than they are in a vacuum.



So the question is...



If equal masses of 1 kilogram of feathers and steel were balanced in a vacuum, would they still balance in 1 atmosphere. And what would be the difference in weight?



Can you help me resolve this and tell me if buoyancy is a factor, and if so by how much?



Thank you.







mass






share|cite|improve this question









New contributor




James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 4 hours ago





















New contributor




James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 5 hours ago









James Thorpe

313




313




New contributor




James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






James Thorpe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Do the test in water
    – user6760
    4 hours ago


















  • Do the test in water
    – user6760
    4 hours ago
















Do the test in water
– user6760
4 hours ago




Do the test in water
– user6760
4 hours ago










3 Answers
3






active

oldest

votes

















up vote
5
down vote













Feathers are made from keratin, with a density of about 1.3 grams/cc. The net volume displaced by a kilogram of feathers is then 751 cc's. Steel has a density of 7.86 g/cc and a kilogram of it displaces 127 cc's.



Sea level air has a density of 0.0012 g/cc, so the buoyant force on 751 cc's of keratin is then 0.92 grams and the buoyant force on 127 cc's of steel is 0.155 grams.



This means that if we weigh the keratin in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.08 grams. If we weigh the steel in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.85 grams.



If we place the two bodies- keratin and steel, one kg of each- on a pivoting balance equidistant from the pivot in a vacuum, they will be in balance, but in air the keratin will be lighter by (999.85-999.08) grams or 0.77 grams.






share|cite|improve this answer






























    up vote
    1
    down vote













    You can argue that her feathers contain a lot of air (never perfectly compressed) so that the volume is not true. You could also take your kilo of steel and make it into a hollow sphere (empty) of the same volume as the feathers (whatever that is) and then it would actually weigh less because you have no air inside. But you could be nice and let her make the point about a bigger volume being more bouyant, she is correct about this but ..... even volume is tricky.






    share|cite|improve this answer





















    • The argument is not that buoyancy makes no difference, it is the amount of difference it makes that is in dispute. She is arguing that the buoyancy of the feathers is related to the density of feathers in the bag including the air within. This I do not agree with. She calculates that it’s buoyancy would make it weigh almost half of what it would weigh in a vacuum. I do not agree with either of these figures.
      – James Thorpe
      2 hours ago












    • She also calculates that a mass of one kilogram of feathers would displace 400 litres of water if immersed. I do not agree with that figure either.
      – James Thorpe
      2 hours ago










    • Yes good points.
      – PhysicsDave
      26 mins ago


















    up vote
    -2
    down vote













    Due to buoyancy one kilogram of hot air balloon indeed weighs less than one kilogram of steel!






    share|cite|improve this answer





















    • It would be nice if you told us by how much, haha.
      – FGSUZ
      5 hours ago










    • This would be better as a comment
      – Aaron Stevens
      4 hours ago










    • I have used the above to elaborate on the question. Thanks.
      – James Thorpe
      4 hours ago











    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "151"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });






    James Thorpe is a new contributor. Be nice, and check out our Code of Conduct.










    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f449433%2fkilogram-of-steel-v-s-a-kilogram-of-feathers%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    5
    down vote













    Feathers are made from keratin, with a density of about 1.3 grams/cc. The net volume displaced by a kilogram of feathers is then 751 cc's. Steel has a density of 7.86 g/cc and a kilogram of it displaces 127 cc's.



    Sea level air has a density of 0.0012 g/cc, so the buoyant force on 751 cc's of keratin is then 0.92 grams and the buoyant force on 127 cc's of steel is 0.155 grams.



    This means that if we weigh the keratin in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.08 grams. If we weigh the steel in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.85 grams.



    If we place the two bodies- keratin and steel, one kg of each- on a pivoting balance equidistant from the pivot in a vacuum, they will be in balance, but in air the keratin will be lighter by (999.85-999.08) grams or 0.77 grams.






    share|cite|improve this answer



























      up vote
      5
      down vote













      Feathers are made from keratin, with a density of about 1.3 grams/cc. The net volume displaced by a kilogram of feathers is then 751 cc's. Steel has a density of 7.86 g/cc and a kilogram of it displaces 127 cc's.



      Sea level air has a density of 0.0012 g/cc, so the buoyant force on 751 cc's of keratin is then 0.92 grams and the buoyant force on 127 cc's of steel is 0.155 grams.



      This means that if we weigh the keratin in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.08 grams. If we weigh the steel in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.85 grams.



      If we place the two bodies- keratin and steel, one kg of each- on a pivoting balance equidistant from the pivot in a vacuum, they will be in balance, but in air the keratin will be lighter by (999.85-999.08) grams or 0.77 grams.






      share|cite|improve this answer

























        up vote
        5
        down vote










        up vote
        5
        down vote









        Feathers are made from keratin, with a density of about 1.3 grams/cc. The net volume displaced by a kilogram of feathers is then 751 cc's. Steel has a density of 7.86 g/cc and a kilogram of it displaces 127 cc's.



        Sea level air has a density of 0.0012 g/cc, so the buoyant force on 751 cc's of keratin is then 0.92 grams and the buoyant force on 127 cc's of steel is 0.155 grams.



        This means that if we weigh the keratin in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.08 grams. If we weigh the steel in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.85 grams.



        If we place the two bodies- keratin and steel, one kg of each- on a pivoting balance equidistant from the pivot in a vacuum, they will be in balance, but in air the keratin will be lighter by (999.85-999.08) grams or 0.77 grams.






        share|cite|improve this answer














        Feathers are made from keratin, with a density of about 1.3 grams/cc. The net volume displaced by a kilogram of feathers is then 751 cc's. Steel has a density of 7.86 g/cc and a kilogram of it displaces 127 cc's.



        Sea level air has a density of 0.0012 g/cc, so the buoyant force on 751 cc's of keratin is then 0.92 grams and the buoyant force on 127 cc's of steel is 0.155 grams.



        This means that if we weigh the keratin in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.08 grams. If we weigh the steel in a vacuum, it will weigh 1 kilogram but in air it will weigh 999.85 grams.



        If we place the two bodies- keratin and steel, one kg of each- on a pivoting balance equidistant from the pivot in a vacuum, they will be in balance, but in air the keratin will be lighter by (999.85-999.08) grams or 0.77 grams.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited 56 mins ago

























        answered 1 hour ago









        niels nielsen

        15.3k42649




        15.3k42649






















            up vote
            1
            down vote













            You can argue that her feathers contain a lot of air (never perfectly compressed) so that the volume is not true. You could also take your kilo of steel and make it into a hollow sphere (empty) of the same volume as the feathers (whatever that is) and then it would actually weigh less because you have no air inside. But you could be nice and let her make the point about a bigger volume being more bouyant, she is correct about this but ..... even volume is tricky.






            share|cite|improve this answer





















            • The argument is not that buoyancy makes no difference, it is the amount of difference it makes that is in dispute. She is arguing that the buoyancy of the feathers is related to the density of feathers in the bag including the air within. This I do not agree with. She calculates that it’s buoyancy would make it weigh almost half of what it would weigh in a vacuum. I do not agree with either of these figures.
              – James Thorpe
              2 hours ago












            • She also calculates that a mass of one kilogram of feathers would displace 400 litres of water if immersed. I do not agree with that figure either.
              – James Thorpe
              2 hours ago










            • Yes good points.
              – PhysicsDave
              26 mins ago















            up vote
            1
            down vote













            You can argue that her feathers contain a lot of air (never perfectly compressed) so that the volume is not true. You could also take your kilo of steel and make it into a hollow sphere (empty) of the same volume as the feathers (whatever that is) and then it would actually weigh less because you have no air inside. But you could be nice and let her make the point about a bigger volume being more bouyant, she is correct about this but ..... even volume is tricky.






            share|cite|improve this answer





















            • The argument is not that buoyancy makes no difference, it is the amount of difference it makes that is in dispute. She is arguing that the buoyancy of the feathers is related to the density of feathers in the bag including the air within. This I do not agree with. She calculates that it’s buoyancy would make it weigh almost half of what it would weigh in a vacuum. I do not agree with either of these figures.
              – James Thorpe
              2 hours ago












            • She also calculates that a mass of one kilogram of feathers would displace 400 litres of water if immersed. I do not agree with that figure either.
              – James Thorpe
              2 hours ago










            • Yes good points.
              – PhysicsDave
              26 mins ago













            up vote
            1
            down vote










            up vote
            1
            down vote









            You can argue that her feathers contain a lot of air (never perfectly compressed) so that the volume is not true. You could also take your kilo of steel and make it into a hollow sphere (empty) of the same volume as the feathers (whatever that is) and then it would actually weigh less because you have no air inside. But you could be nice and let her make the point about a bigger volume being more bouyant, she is correct about this but ..... even volume is tricky.






            share|cite|improve this answer












            You can argue that her feathers contain a lot of air (never perfectly compressed) so that the volume is not true. You could also take your kilo of steel and make it into a hollow sphere (empty) of the same volume as the feathers (whatever that is) and then it would actually weigh less because you have no air inside. But you could be nice and let her make the point about a bigger volume being more bouyant, she is correct about this but ..... even volume is tricky.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered 4 hours ago









            PhysicsDave

            80536




            80536












            • The argument is not that buoyancy makes no difference, it is the amount of difference it makes that is in dispute. She is arguing that the buoyancy of the feathers is related to the density of feathers in the bag including the air within. This I do not agree with. She calculates that it’s buoyancy would make it weigh almost half of what it would weigh in a vacuum. I do not agree with either of these figures.
              – James Thorpe
              2 hours ago












            • She also calculates that a mass of one kilogram of feathers would displace 400 litres of water if immersed. I do not agree with that figure either.
              – James Thorpe
              2 hours ago










            • Yes good points.
              – PhysicsDave
              26 mins ago


















            • The argument is not that buoyancy makes no difference, it is the amount of difference it makes that is in dispute. She is arguing that the buoyancy of the feathers is related to the density of feathers in the bag including the air within. This I do not agree with. She calculates that it’s buoyancy would make it weigh almost half of what it would weigh in a vacuum. I do not agree with either of these figures.
              – James Thorpe
              2 hours ago












            • She also calculates that a mass of one kilogram of feathers would displace 400 litres of water if immersed. I do not agree with that figure either.
              – James Thorpe
              2 hours ago










            • Yes good points.
              – PhysicsDave
              26 mins ago
















            The argument is not that buoyancy makes no difference, it is the amount of difference it makes that is in dispute. She is arguing that the buoyancy of the feathers is related to the density of feathers in the bag including the air within. This I do not agree with. She calculates that it’s buoyancy would make it weigh almost half of what it would weigh in a vacuum. I do not agree with either of these figures.
            – James Thorpe
            2 hours ago






            The argument is not that buoyancy makes no difference, it is the amount of difference it makes that is in dispute. She is arguing that the buoyancy of the feathers is related to the density of feathers in the bag including the air within. This I do not agree with. She calculates that it’s buoyancy would make it weigh almost half of what it would weigh in a vacuum. I do not agree with either of these figures.
            – James Thorpe
            2 hours ago














            She also calculates that a mass of one kilogram of feathers would displace 400 litres of water if immersed. I do not agree with that figure either.
            – James Thorpe
            2 hours ago




            She also calculates that a mass of one kilogram of feathers would displace 400 litres of water if immersed. I do not agree with that figure either.
            – James Thorpe
            2 hours ago












            Yes good points.
            – PhysicsDave
            26 mins ago




            Yes good points.
            – PhysicsDave
            26 mins ago










            up vote
            -2
            down vote













            Due to buoyancy one kilogram of hot air balloon indeed weighs less than one kilogram of steel!






            share|cite|improve this answer





















            • It would be nice if you told us by how much, haha.
              – FGSUZ
              5 hours ago










            • This would be better as a comment
              – Aaron Stevens
              4 hours ago










            • I have used the above to elaborate on the question. Thanks.
              – James Thorpe
              4 hours ago















            up vote
            -2
            down vote













            Due to buoyancy one kilogram of hot air balloon indeed weighs less than one kilogram of steel!






            share|cite|improve this answer





















            • It would be nice if you told us by how much, haha.
              – FGSUZ
              5 hours ago










            • This would be better as a comment
              – Aaron Stevens
              4 hours ago










            • I have used the above to elaborate on the question. Thanks.
              – James Thorpe
              4 hours ago













            up vote
            -2
            down vote










            up vote
            -2
            down vote









            Due to buoyancy one kilogram of hot air balloon indeed weighs less than one kilogram of steel!






            share|cite|improve this answer












            Due to buoyancy one kilogram of hot air balloon indeed weighs less than one kilogram of steel!







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered 5 hours ago









            my2cts

            4,3502617




            4,3502617












            • It would be nice if you told us by how much, haha.
              – FGSUZ
              5 hours ago










            • This would be better as a comment
              – Aaron Stevens
              4 hours ago










            • I have used the above to elaborate on the question. Thanks.
              – James Thorpe
              4 hours ago


















            • It would be nice if you told us by how much, haha.
              – FGSUZ
              5 hours ago










            • This would be better as a comment
              – Aaron Stevens
              4 hours ago










            • I have used the above to elaborate on the question. Thanks.
              – James Thorpe
              4 hours ago
















            It would be nice if you told us by how much, haha.
            – FGSUZ
            5 hours ago




            It would be nice if you told us by how much, haha.
            – FGSUZ
            5 hours ago












            This would be better as a comment
            – Aaron Stevens
            4 hours ago




            This would be better as a comment
            – Aaron Stevens
            4 hours ago












            I have used the above to elaborate on the question. Thanks.
            – James Thorpe
            4 hours ago




            I have used the above to elaborate on the question. Thanks.
            – James Thorpe
            4 hours ago










            James Thorpe is a new contributor. Be nice, and check out our Code of Conduct.










            draft saved

            draft discarded


















            James Thorpe is a new contributor. Be nice, and check out our Code of Conduct.













            James Thorpe is a new contributor. Be nice, and check out our Code of Conduct.












            James Thorpe is a new contributor. Be nice, and check out our Code of Conduct.
















            Thanks for contributing an answer to Physics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f449433%2fkilogram-of-steel-v-s-a-kilogram-of-feathers%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Quarter-circle Tiles

            build a pushdown automaton that recognizes the reverse language of a given pushdown automaton?

            Mont Emei