A set having the same mean, median, mode, and range
$begingroup$
Is it possible to have a set with the same mean, median, mode, and range?
If not, how can the following question be solved:
Set $H$ contains five positive integers such that the mean, median,
mode, and range are all equal. The sum of the data is $25$.
Using the above information, indicate which one will be greater:
a) the smallest possible number in set $H$.
b) 6.
If I assume that all the elements in set $H$ are equal to $5$, it doesn't satisfy the conditions for range, as the range will become zero then.
statistics means median
$endgroup$
add a comment |
$begingroup$
Is it possible to have a set with the same mean, median, mode, and range?
If not, how can the following question be solved:
Set $H$ contains five positive integers such that the mean, median,
mode, and range are all equal. The sum of the data is $25$.
Using the above information, indicate which one will be greater:
a) the smallest possible number in set $H$.
b) 6.
If I assume that all the elements in set $H$ are equal to $5$, it doesn't satisfy the conditions for range, as the range will become zero then.
statistics means median
$endgroup$
$begingroup$
The list ${0,0}$ works quite well for you first question.
$endgroup$
– Mike Pierce
Jun 5 '15 at 4:26
$begingroup$
@MikePierce Serious suggestion ?
$endgroup$
– callculus
Jun 5 '15 at 4:33
add a comment |
$begingroup$
Is it possible to have a set with the same mean, median, mode, and range?
If not, how can the following question be solved:
Set $H$ contains five positive integers such that the mean, median,
mode, and range are all equal. The sum of the data is $25$.
Using the above information, indicate which one will be greater:
a) the smallest possible number in set $H$.
b) 6.
If I assume that all the elements in set $H$ are equal to $5$, it doesn't satisfy the conditions for range, as the range will become zero then.
statistics means median
$endgroup$
Is it possible to have a set with the same mean, median, mode, and range?
If not, how can the following question be solved:
Set $H$ contains five positive integers such that the mean, median,
mode, and range are all equal. The sum of the data is $25$.
Using the above information, indicate which one will be greater:
a) the smallest possible number in set $H$.
b) 6.
If I assume that all the elements in set $H$ are equal to $5$, it doesn't satisfy the conditions for range, as the range will become zero then.
statistics means median
statistics means median
edited Jun 5 '15 at 4:36
Ken
3,62151728
3,62151728
asked Jun 5 '15 at 4:17
India SlaverIndia Slaver
27118
27118
$begingroup$
The list ${0,0}$ works quite well for you first question.
$endgroup$
– Mike Pierce
Jun 5 '15 at 4:26
$begingroup$
@MikePierce Serious suggestion ?
$endgroup$
– callculus
Jun 5 '15 at 4:33
add a comment |
$begingroup$
The list ${0,0}$ works quite well for you first question.
$endgroup$
– Mike Pierce
Jun 5 '15 at 4:26
$begingroup$
@MikePierce Serious suggestion ?
$endgroup$
– callculus
Jun 5 '15 at 4:33
$begingroup$
The list ${0,0}$ works quite well for you first question.
$endgroup$
– Mike Pierce
Jun 5 '15 at 4:26
$begingroup$
The list ${0,0}$ works quite well for you first question.
$endgroup$
– Mike Pierce
Jun 5 '15 at 4:26
$begingroup$
@MikePierce Serious suggestion ?
$endgroup$
– callculus
Jun 5 '15 at 4:33
$begingroup$
@MikePierce Serious suggestion ?
$endgroup$
– callculus
Jun 5 '15 at 4:33
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
The multiset $[3, 4, 5, 5, 8]$ will fit the bill.
You know, though, that even if you didn't have an example of a set on hand, the smallest element must be less than or equal to $5$ since the median is $5$ (since the mean is $5$).
$endgroup$
$begingroup$
Of course, I knew that. This was so silly on my part that I didn't spend much time thinking about such a set. Thanks. :)
$endgroup$
– India Slaver
Jun 5 '15 at 4:35
add a comment |
$begingroup$
Hint: If I allow non-integers and let the set contain duplicates (I think duplicates are allowed, though generally a set does not allow them. To have a mode you need duplicates), ${2.5,5,5,5,7.5}$ satisfies the constraints. Can you modify it to use only integers?
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1312867%2fa-set-having-the-same-mean-median-mode-and-range%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The multiset $[3, 4, 5, 5, 8]$ will fit the bill.
You know, though, that even if you didn't have an example of a set on hand, the smallest element must be less than or equal to $5$ since the median is $5$ (since the mean is $5$).
$endgroup$
$begingroup$
Of course, I knew that. This was so silly on my part that I didn't spend much time thinking about such a set. Thanks. :)
$endgroup$
– India Slaver
Jun 5 '15 at 4:35
add a comment |
$begingroup$
The multiset $[3, 4, 5, 5, 8]$ will fit the bill.
You know, though, that even if you didn't have an example of a set on hand, the smallest element must be less than or equal to $5$ since the median is $5$ (since the mean is $5$).
$endgroup$
$begingroup$
Of course, I knew that. This was so silly on my part that I didn't spend much time thinking about such a set. Thanks. :)
$endgroup$
– India Slaver
Jun 5 '15 at 4:35
add a comment |
$begingroup$
The multiset $[3, 4, 5, 5, 8]$ will fit the bill.
You know, though, that even if you didn't have an example of a set on hand, the smallest element must be less than or equal to $5$ since the median is $5$ (since the mean is $5$).
$endgroup$
The multiset $[3, 4, 5, 5, 8]$ will fit the bill.
You know, though, that even if you didn't have an example of a set on hand, the smallest element must be less than or equal to $5$ since the median is $5$ (since the mean is $5$).
answered Jun 5 '15 at 4:31
KenKen
3,62151728
3,62151728
$begingroup$
Of course, I knew that. This was so silly on my part that I didn't spend much time thinking about such a set. Thanks. :)
$endgroup$
– India Slaver
Jun 5 '15 at 4:35
add a comment |
$begingroup$
Of course, I knew that. This was so silly on my part that I didn't spend much time thinking about such a set. Thanks. :)
$endgroup$
– India Slaver
Jun 5 '15 at 4:35
$begingroup$
Of course, I knew that. This was so silly on my part that I didn't spend much time thinking about such a set. Thanks. :)
$endgroup$
– India Slaver
Jun 5 '15 at 4:35
$begingroup$
Of course, I knew that. This was so silly on my part that I didn't spend much time thinking about such a set. Thanks. :)
$endgroup$
– India Slaver
Jun 5 '15 at 4:35
add a comment |
$begingroup$
Hint: If I allow non-integers and let the set contain duplicates (I think duplicates are allowed, though generally a set does not allow them. To have a mode you need duplicates), ${2.5,5,5,5,7.5}$ satisfies the constraints. Can you modify it to use only integers?
$endgroup$
add a comment |
$begingroup$
Hint: If I allow non-integers and let the set contain duplicates (I think duplicates are allowed, though generally a set does not allow them. To have a mode you need duplicates), ${2.5,5,5,5,7.5}$ satisfies the constraints. Can you modify it to use only integers?
$endgroup$
add a comment |
$begingroup$
Hint: If I allow non-integers and let the set contain duplicates (I think duplicates are allowed, though generally a set does not allow them. To have a mode you need duplicates), ${2.5,5,5,5,7.5}$ satisfies the constraints. Can you modify it to use only integers?
$endgroup$
Hint: If I allow non-integers and let the set contain duplicates (I think duplicates are allowed, though generally a set does not allow them. To have a mode you need duplicates), ${2.5,5,5,5,7.5}$ satisfies the constraints. Can you modify it to use only integers?
answered Jun 5 '15 at 4:27
Ross MillikanRoss Millikan
293k23197371
293k23197371
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1312867%2fa-set-having-the-same-mean-median-mode-and-range%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
The list ${0,0}$ works quite well for you first question.
$endgroup$
– Mike Pierce
Jun 5 '15 at 4:26
$begingroup$
@MikePierce Serious suggestion ?
$endgroup$
– callculus
Jun 5 '15 at 4:33