Altitudes Ratio [closed]












0












$begingroup$


If h, h', h'' denote the lengths of the three altitudes of a triangle, which of the following ratios never occurs as the ratio h: h': h''?



a)2 : 3 : 4
b)2 : 3 : 5
c)2 : 4 : 5
d)3 : 4 : 5
e)3 : 4 : 6


Any help would be much appreciated!
If possible, please could you explain the solution.



Thanks in Advance










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closed as off-topic by José Carlos Santos, Alexander Gruber Dec 4 '18 at 4:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – José Carlos Santos, Alexander Gruber

If this question can be reworded to fit the rules in the help center, please edit the question.


















    0












    $begingroup$


    If h, h', h'' denote the lengths of the three altitudes of a triangle, which of the following ratios never occurs as the ratio h: h': h''?



    a)2 : 3 : 4
    b)2 : 3 : 5
    c)2 : 4 : 5
    d)3 : 4 : 5
    e)3 : 4 : 6


    Any help would be much appreciated!
    If possible, please could you explain the solution.



    Thanks in Advance










    share|cite|improve this question











    $endgroup$



    closed as off-topic by José Carlos Santos, Alexander Gruber Dec 4 '18 at 4:07


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – José Carlos Santos, Alexander Gruber

    If this question can be reworded to fit the rules in the help center, please edit the question.
















      0












      0








      0





      $begingroup$


      If h, h', h'' denote the lengths of the three altitudes of a triangle, which of the following ratios never occurs as the ratio h: h': h''?



      a)2 : 3 : 4
      b)2 : 3 : 5
      c)2 : 4 : 5
      d)3 : 4 : 5
      e)3 : 4 : 6


      Any help would be much appreciated!
      If possible, please could you explain the solution.



      Thanks in Advance










      share|cite|improve this question











      $endgroup$




      If h, h', h'' denote the lengths of the three altitudes of a triangle, which of the following ratios never occurs as the ratio h: h': h''?



      a)2 : 3 : 4
      b)2 : 3 : 5
      c)2 : 4 : 5
      d)3 : 4 : 5
      e)3 : 4 : 6


      Any help would be much appreciated!
      If possible, please could you explain the solution.



      Thanks in Advance







      triangle






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      share|cite|improve this question













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      edited Jul 16 '13 at 10:56







      Hummus

















      asked Jul 16 '13 at 10:37









      HummusHummus

      1981312




      1981312




      closed as off-topic by José Carlos Santos, Alexander Gruber Dec 4 '18 at 4:07


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – José Carlos Santos, Alexander Gruber

      If this question can be reworded to fit the rules in the help center, please edit the question.




      closed as off-topic by José Carlos Santos, Alexander Gruber Dec 4 '18 at 4:07


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – José Carlos Santos, Alexander Gruber

      If this question can be reworded to fit the rules in the help center, please edit the question.






















          2 Answers
          2






          active

          oldest

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          1












          $begingroup$

          Suppose that there is a triangle with altitudes $h_1$, $h_2$ and $h_3$.



          Let $a_1$, $a_2$, and $a_3$ be the three sides of this triangle, such that the altitude from side $a_i$ is $h_i$. The area $A$ of the triangle is, by the well known formula:
          $$
          A=frac{1}{2}a_1h_1=frac{1}{2}a_2h_2=frac{1}{2}a_3h_3.
          $$
          With this, we use the condition that for a triangle to exist, the sum of the length of its shorter sides must be bigger than the length of its longer side. In terms of altitudes, if $h_1leq h_2leq h_3$, the condition thus becomes
          $$
          frac{1}{h_1} leq frac{1}{h_2}+frac{1}{h_3},
          $$
          which does not hold for b) only.






          share|cite|improve this answer









          $endgroup$





















            0












            $begingroup$

            Sum of two altitudes is greater than the third altitude which is not satisfied by option (b).
            As if we take them to be 2x,3x and 5x
            2x+3x=5x(and it doesn't satisfy).
            Cheers!






            share|cite|improve this answer









            $endgroup$




















              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              1












              $begingroup$

              Suppose that there is a triangle with altitudes $h_1$, $h_2$ and $h_3$.



              Let $a_1$, $a_2$, and $a_3$ be the three sides of this triangle, such that the altitude from side $a_i$ is $h_i$. The area $A$ of the triangle is, by the well known formula:
              $$
              A=frac{1}{2}a_1h_1=frac{1}{2}a_2h_2=frac{1}{2}a_3h_3.
              $$
              With this, we use the condition that for a triangle to exist, the sum of the length of its shorter sides must be bigger than the length of its longer side. In terms of altitudes, if $h_1leq h_2leq h_3$, the condition thus becomes
              $$
              frac{1}{h_1} leq frac{1}{h_2}+frac{1}{h_3},
              $$
              which does not hold for b) only.






              share|cite|improve this answer









              $endgroup$


















                1












                $begingroup$

                Suppose that there is a triangle with altitudes $h_1$, $h_2$ and $h_3$.



                Let $a_1$, $a_2$, and $a_3$ be the three sides of this triangle, such that the altitude from side $a_i$ is $h_i$. The area $A$ of the triangle is, by the well known formula:
                $$
                A=frac{1}{2}a_1h_1=frac{1}{2}a_2h_2=frac{1}{2}a_3h_3.
                $$
                With this, we use the condition that for a triangle to exist, the sum of the length of its shorter sides must be bigger than the length of its longer side. In terms of altitudes, if $h_1leq h_2leq h_3$, the condition thus becomes
                $$
                frac{1}{h_1} leq frac{1}{h_2}+frac{1}{h_3},
                $$
                which does not hold for b) only.






                share|cite|improve this answer









                $endgroup$
















                  1












                  1








                  1





                  $begingroup$

                  Suppose that there is a triangle with altitudes $h_1$, $h_2$ and $h_3$.



                  Let $a_1$, $a_2$, and $a_3$ be the three sides of this triangle, such that the altitude from side $a_i$ is $h_i$. The area $A$ of the triangle is, by the well known formula:
                  $$
                  A=frac{1}{2}a_1h_1=frac{1}{2}a_2h_2=frac{1}{2}a_3h_3.
                  $$
                  With this, we use the condition that for a triangle to exist, the sum of the length of its shorter sides must be bigger than the length of its longer side. In terms of altitudes, if $h_1leq h_2leq h_3$, the condition thus becomes
                  $$
                  frac{1}{h_1} leq frac{1}{h_2}+frac{1}{h_3},
                  $$
                  which does not hold for b) only.






                  share|cite|improve this answer









                  $endgroup$



                  Suppose that there is a triangle with altitudes $h_1$, $h_2$ and $h_3$.



                  Let $a_1$, $a_2$, and $a_3$ be the three sides of this triangle, such that the altitude from side $a_i$ is $h_i$. The area $A$ of the triangle is, by the well known formula:
                  $$
                  A=frac{1}{2}a_1h_1=frac{1}{2}a_2h_2=frac{1}{2}a_3h_3.
                  $$
                  With this, we use the condition that for a triangle to exist, the sum of the length of its shorter sides must be bigger than the length of its longer side. In terms of altitudes, if $h_1leq h_2leq h_3$, the condition thus becomes
                  $$
                  frac{1}{h_1} leq frac{1}{h_2}+frac{1}{h_3},
                  $$
                  which does not hold for b) only.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Jul 16 '13 at 11:40









                  zugggzuggg

                  1,074614




                  1,074614























                      0












                      $begingroup$

                      Sum of two altitudes is greater than the third altitude which is not satisfied by option (b).
                      As if we take them to be 2x,3x and 5x
                      2x+3x=5x(and it doesn't satisfy).
                      Cheers!






                      share|cite|improve this answer









                      $endgroup$


















                        0












                        $begingroup$

                        Sum of two altitudes is greater than the third altitude which is not satisfied by option (b).
                        As if we take them to be 2x,3x and 5x
                        2x+3x=5x(and it doesn't satisfy).
                        Cheers!






                        share|cite|improve this answer









                        $endgroup$
















                          0












                          0








                          0





                          $begingroup$

                          Sum of two altitudes is greater than the third altitude which is not satisfied by option (b).
                          As if we take them to be 2x,3x and 5x
                          2x+3x=5x(and it doesn't satisfy).
                          Cheers!






                          share|cite|improve this answer









                          $endgroup$



                          Sum of two altitudes is greater than the third altitude which is not satisfied by option (b).
                          As if we take them to be 2x,3x and 5x
                          2x+3x=5x(and it doesn't satisfy).
                          Cheers!







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered Dec 3 '18 at 17:50









                          maurana desanmaurana desan

                          1




                          1















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