Prove that $a + 2b equiv 0 pmod{3}$ if and only if $a equiv bpmod{3}$.












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I need to prove that $a + 2b equiv 0pmod{3}$ if and only if $a equiv b pmod{3}$.




I know that you need to show both cases but my professor said that we weren't supposed to use one to solve the other so I'm stuck.










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$endgroup$

















    1












    $begingroup$



    I need to prove that $a + 2b equiv 0pmod{3}$ if and only if $a equiv b pmod{3}$.




    I know that you need to show both cases but my professor said that we weren't supposed to use one to solve the other so I'm stuck.










    share|cite|improve this question











    $endgroup$















      1












      1








      1





      $begingroup$



      I need to prove that $a + 2b equiv 0pmod{3}$ if and only if $a equiv b pmod{3}$.




      I know that you need to show both cases but my professor said that we weren't supposed to use one to solve the other so I'm stuck.










      share|cite|improve this question











      $endgroup$





      I need to prove that $a + 2b equiv 0pmod{3}$ if and only if $a equiv b pmod{3}$.




      I know that you need to show both cases but my professor said that we weren't supposed to use one to solve the other so I'm stuck.







      elementary-number-theory






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      edited Dec 9 '18 at 2:38









      Shaun

      9,000113682




      9,000113682










      asked Dec 9 '18 at 1:53









      Lauren YLauren Y

      61




      61






















          4 Answers
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          active

          oldest

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          3












          $begingroup$

          Hint: $ 2equiv -1pmod3 $ so $ a+2bequiv a-bpmod 3 $






          share|cite|improve this answer











          $endgroup$





















            2












            $begingroup$

            Hint: Try converting the second equation to
            $$
            a -b equiv 0 pmod 3
            $$

            by subtracting $b$ from both sides.






            share|cite|improve this answer











            $endgroup$





















              1












              $begingroup$

              $a equiv b pmod 3 iff 3|a-b iff 3|a-b + 3b iff 3|a+2b iff a+2b equiv 0 pmod 3$



              or...



              $2equiv -1 pmod 3$ so....



              $a+2b equiv 0pmod 3 iff a- b equiv 0 pmod 3 iff a equiv b pmod 3$






              share|cite|improve this answer









              $endgroup$





















                1












                $begingroup$

                Hint: Here $2$ is "a multiple of three away from" $-1$, meaning that they are what modulo three?




                They are equivalent.







                share|cite|improve this answer









                $endgroup$













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                  4 Answers
                  4






                  active

                  oldest

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                  4 Answers
                  4






                  active

                  oldest

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                  active

                  oldest

                  votes






                  active

                  oldest

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                  3












                  $begingroup$

                  Hint: $ 2equiv -1pmod3 $ so $ a+2bequiv a-bpmod 3 $






                  share|cite|improve this answer











                  $endgroup$


















                    3












                    $begingroup$

                    Hint: $ 2equiv -1pmod3 $ so $ a+2bequiv a-bpmod 3 $






                    share|cite|improve this answer











                    $endgroup$
















                      3












                      3








                      3





                      $begingroup$

                      Hint: $ 2equiv -1pmod3 $ so $ a+2bequiv a-bpmod 3 $






                      share|cite|improve this answer











                      $endgroup$



                      Hint: $ 2equiv -1pmod3 $ so $ a+2bequiv a-bpmod 3 $







                      share|cite|improve this answer














                      share|cite|improve this answer



                      share|cite|improve this answer








                      edited Dec 9 '18 at 2:39









                      Bill Dubuque

                      210k29192640




                      210k29192640










                      answered Dec 9 '18 at 1:55









                      Tsemo AristideTsemo Aristide

                      57.5k11444




                      57.5k11444























                          2












                          $begingroup$

                          Hint: Try converting the second equation to
                          $$
                          a -b equiv 0 pmod 3
                          $$

                          by subtracting $b$ from both sides.






                          share|cite|improve this answer











                          $endgroup$


















                            2












                            $begingroup$

                            Hint: Try converting the second equation to
                            $$
                            a -b equiv 0 pmod 3
                            $$

                            by subtracting $b$ from both sides.






                            share|cite|improve this answer











                            $endgroup$
















                              2












                              2








                              2





                              $begingroup$

                              Hint: Try converting the second equation to
                              $$
                              a -b equiv 0 pmod 3
                              $$

                              by subtracting $b$ from both sides.






                              share|cite|improve this answer











                              $endgroup$



                              Hint: Try converting the second equation to
                              $$
                              a -b equiv 0 pmod 3
                              $$

                              by subtracting $b$ from both sides.







                              share|cite|improve this answer














                              share|cite|improve this answer



                              share|cite|improve this answer








                              edited Dec 9 '18 at 2:38









                              Bill Dubuque

                              210k29192640




                              210k29192640










                              answered Dec 9 '18 at 1:55









                              John HughesJohn Hughes

                              63.3k24090




                              63.3k24090























                                  1












                                  $begingroup$

                                  $a equiv b pmod 3 iff 3|a-b iff 3|a-b + 3b iff 3|a+2b iff a+2b equiv 0 pmod 3$



                                  or...



                                  $2equiv -1 pmod 3$ so....



                                  $a+2b equiv 0pmod 3 iff a- b equiv 0 pmod 3 iff a equiv b pmod 3$






                                  share|cite|improve this answer









                                  $endgroup$


















                                    1












                                    $begingroup$

                                    $a equiv b pmod 3 iff 3|a-b iff 3|a-b + 3b iff 3|a+2b iff a+2b equiv 0 pmod 3$



                                    or...



                                    $2equiv -1 pmod 3$ so....



                                    $a+2b equiv 0pmod 3 iff a- b equiv 0 pmod 3 iff a equiv b pmod 3$






                                    share|cite|improve this answer









                                    $endgroup$
















                                      1












                                      1








                                      1





                                      $begingroup$

                                      $a equiv b pmod 3 iff 3|a-b iff 3|a-b + 3b iff 3|a+2b iff a+2b equiv 0 pmod 3$



                                      or...



                                      $2equiv -1 pmod 3$ so....



                                      $a+2b equiv 0pmod 3 iff a- b equiv 0 pmod 3 iff a equiv b pmod 3$






                                      share|cite|improve this answer









                                      $endgroup$



                                      $a equiv b pmod 3 iff 3|a-b iff 3|a-b + 3b iff 3|a+2b iff a+2b equiv 0 pmod 3$



                                      or...



                                      $2equiv -1 pmod 3$ so....



                                      $a+2b equiv 0pmod 3 iff a- b equiv 0 pmod 3 iff a equiv b pmod 3$







                                      share|cite|improve this answer












                                      share|cite|improve this answer



                                      share|cite|improve this answer










                                      answered Dec 9 '18 at 1:57









                                      fleabloodfleablood

                                      69.6k22685




                                      69.6k22685























                                          1












                                          $begingroup$

                                          Hint: Here $2$ is "a multiple of three away from" $-1$, meaning that they are what modulo three?




                                          They are equivalent.







                                          share|cite|improve this answer









                                          $endgroup$


















                                            1












                                            $begingroup$

                                            Hint: Here $2$ is "a multiple of three away from" $-1$, meaning that they are what modulo three?




                                            They are equivalent.







                                            share|cite|improve this answer









                                            $endgroup$
















                                              1












                                              1








                                              1





                                              $begingroup$

                                              Hint: Here $2$ is "a multiple of three away from" $-1$, meaning that they are what modulo three?




                                              They are equivalent.







                                              share|cite|improve this answer









                                              $endgroup$



                                              Hint: Here $2$ is "a multiple of three away from" $-1$, meaning that they are what modulo three?




                                              They are equivalent.








                                              share|cite|improve this answer












                                              share|cite|improve this answer



                                              share|cite|improve this answer










                                              answered Dec 9 '18 at 2:26









                                              ShaunShaun

                                              9,000113682




                                              9,000113682






























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