Write an equation as a single power(Grade 11 Math, Function)












1












$begingroup$


$$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}$$



The answer is $10^{-7/5}$, which seems impossible to me. I get:



$10^{-4/5} cdot 10^{-11/15}$. I see where the numerator $7$ comes from but the denominator is being a pest, and won't let me do anything because I have to make them equal to add them.






functions







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  • 1




    $begingroup$
    You don't mean an equation. You mean an expression.
    $endgroup$
    – symplectomorphic
    Jun 8 '16 at 22:58










  • $begingroup$
    Please read this tutorial on how to typeset mathematics on this site.
    $endgroup$
    – N. F. Taussig
    May 13 '17 at 19:36
















1












$begingroup$


$$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}$$



The answer is $10^{-7/5}$, which seems impossible to me. I get:



$10^{-4/5} cdot 10^{-11/15}$. I see where the numerator $7$ comes from but the denominator is being a pest, and won't let me do anything because I have to make them equal to add them.






functions







share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    You don't mean an equation. You mean an expression.
    $endgroup$
    – symplectomorphic
    Jun 8 '16 at 22:58










  • $begingroup$
    Please read this tutorial on how to typeset mathematics on this site.
    $endgroup$
    – N. F. Taussig
    May 13 '17 at 19:36














1












1








1





$begingroup$


$$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}$$



The answer is $10^{-7/5}$, which seems impossible to me. I get:



$10^{-4/5} cdot 10^{-11/15}$. I see where the numerator $7$ comes from but the denominator is being a pest, and won't let me do anything because I have to make them equal to add them.






functions







share|cite|improve this question











$endgroup$




$$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}$$



The answer is $10^{-7/5}$, which seems impossible to me. I get:



$10^{-4/5} cdot 10^{-11/15}$. I see where the numerator $7$ comes from but the denominator is being a pest, and won't let me do anything because I have to make them equal to add them.






functions




functions






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited May 13 '17 at 19:35









N. F. Taussig

44.1k93356




44.1k93356










asked Oct 28 '14 at 23:14









user188123user188123

93




93








  • 1




    $begingroup$
    You don't mean an equation. You mean an expression.
    $endgroup$
    – symplectomorphic
    Jun 8 '16 at 22:58










  • $begingroup$
    Please read this tutorial on how to typeset mathematics on this site.
    $endgroup$
    – N. F. Taussig
    May 13 '17 at 19:36














  • 1




    $begingroup$
    You don't mean an equation. You mean an expression.
    $endgroup$
    – symplectomorphic
    Jun 8 '16 at 22:58










  • $begingroup$
    Please read this tutorial on how to typeset mathematics on this site.
    $endgroup$
    – N. F. Taussig
    May 13 '17 at 19:36








1




1




$begingroup$
You don't mean an equation. You mean an expression.
$endgroup$
– symplectomorphic
Jun 8 '16 at 22:58




$begingroup$
You don't mean an equation. You mean an expression.
$endgroup$
– symplectomorphic
Jun 8 '16 at 22:58












$begingroup$
Please read this tutorial on how to typeset mathematics on this site.
$endgroup$
– N. F. Taussig
May 13 '17 at 19:36




$begingroup$
Please read this tutorial on how to typeset mathematics on this site.
$endgroup$
– N. F. Taussig
May 13 '17 at 19:36










4 Answers
4






active

oldest

votes


















0












$begingroup$

After taking a breather and relaxing, I realized my mistake, a/amn is subtracting, not adding, giving me -9/15, reducing that to -3/5 -4-3 = -7/5






share|cite|improve this answer









$endgroup$





















    0












    $begingroup$

    $$10^{-12/15};.;10^{1/15}; . ;10^{-10/15}$$



    $$10^{(-12-10+1)/15}$$



    $$10^{-21/15}$$



    $$10^{-7/5}$$






    share|cite|improve this answer









    $endgroup$





















      0












      $begingroup$

      Note that $$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}=10^{-4/5} cdotfrac{ 10^{1/15}}{10^{10/15}}=10^{-4/5} cdot10^{(1-10)/15}=10^{-4/5}cdot10^{-3/5}=boxed{10^{-7/5}}$$ as desired.






      share|cite|improve this answer









      $endgroup$





















        0












        $begingroup$

        It looks like you made a sign error while combining exponents.



        $$frac1{15} - frac23 = frac1{15} - frac{10}{15} = -frac9{15}.$$



        You seem to have gotten $-frac{11}{15}$ when you should have gotten $-frac9{15},$ perhaps by flipping the sign of $frac1{15}.$



        Of course $-frac9{15} = -frac35,$ and the last step is easy.



        The fact that $4 - 11 = -7$ is a complete red herring.
        If the problem were just a little different so the denominators happened to be equal, for example if they were both $5,$ you would have
        $$ -frac45 - frac{11}5 = -frac{15}5 = -3.$$
        So it seems you have a tendency to make sign errors while adding or subtracting. Now that you know this, you may be able to take steps to correct it.






        share|cite|improve this answer









        $endgroup$













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          4 Answers
          4






          active

          oldest

          votes








          4 Answers
          4






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0












          $begingroup$

          After taking a breather and relaxing, I realized my mistake, a/amn is subtracting, not adding, giving me -9/15, reducing that to -3/5 -4-3 = -7/5






          share|cite|improve this answer









          $endgroup$


















            0












            $begingroup$

            After taking a breather and relaxing, I realized my mistake, a/amn is subtracting, not adding, giving me -9/15, reducing that to -3/5 -4-3 = -7/5






            share|cite|improve this answer









            $endgroup$
















              0












              0








              0





              $begingroup$

              After taking a breather and relaxing, I realized my mistake, a/amn is subtracting, not adding, giving me -9/15, reducing that to -3/5 -4-3 = -7/5






              share|cite|improve this answer









              $endgroup$



              After taking a breather and relaxing, I realized my mistake, a/amn is subtracting, not adding, giving me -9/15, reducing that to -3/5 -4-3 = -7/5







              share|cite|improve this answer












              share|cite|improve this answer



              share|cite|improve this answer










              answered Oct 28 '14 at 23:20









              user188123user188123

              93




              93























                  0












                  $begingroup$

                  $$10^{-12/15};.;10^{1/15}; . ;10^{-10/15}$$



                  $$10^{(-12-10+1)/15}$$



                  $$10^{-21/15}$$



                  $$10^{-7/5}$$






                  share|cite|improve this answer









                  $endgroup$


















                    0












                    $begingroup$

                    $$10^{-12/15};.;10^{1/15}; . ;10^{-10/15}$$



                    $$10^{(-12-10+1)/15}$$



                    $$10^{-21/15}$$



                    $$10^{-7/5}$$






                    share|cite|improve this answer









                    $endgroup$
















                      0












                      0








                      0





                      $begingroup$

                      $$10^{-12/15};.;10^{1/15}; . ;10^{-10/15}$$



                      $$10^{(-12-10+1)/15}$$



                      $$10^{-21/15}$$



                      $$10^{-7/5}$$






                      share|cite|improve this answer









                      $endgroup$



                      $$10^{-12/15};.;10^{1/15}; . ;10^{-10/15}$$



                      $$10^{(-12-10+1)/15}$$



                      $$10^{-21/15}$$



                      $$10^{-7/5}$$







                      share|cite|improve this answer












                      share|cite|improve this answer



                      share|cite|improve this answer










                      answered Jan 28 '18 at 11:16









                      prog_SAHILprog_SAHIL

                      1,697518




                      1,697518























                          0












                          $begingroup$

                          Note that $$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}=10^{-4/5} cdotfrac{ 10^{1/15}}{10^{10/15}}=10^{-4/5} cdot10^{(1-10)/15}=10^{-4/5}cdot10^{-3/5}=boxed{10^{-7/5}}$$ as desired.






                          share|cite|improve this answer









                          $endgroup$


















                            0












                            $begingroup$

                            Note that $$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}=10^{-4/5} cdotfrac{ 10^{1/15}}{10^{10/15}}=10^{-4/5} cdot10^{(1-10)/15}=10^{-4/5}cdot10^{-3/5}=boxed{10^{-7/5}}$$ as desired.






                            share|cite|improve this answer









                            $endgroup$
















                              0












                              0








                              0





                              $begingroup$

                              Note that $$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}=10^{-4/5} cdotfrac{ 10^{1/15}}{10^{10/15}}=10^{-4/5} cdot10^{(1-10)/15}=10^{-4/5}cdot10^{-3/5}=boxed{10^{-7/5}}$$ as desired.






                              share|cite|improve this answer









                              $endgroup$



                              Note that $$frac{10^{-4/5} cdot 10^{1/15}}{10^{2/3}}=10^{-4/5} cdotfrac{ 10^{1/15}}{10^{10/15}}=10^{-4/5} cdot10^{(1-10)/15}=10^{-4/5}cdot10^{-3/5}=boxed{10^{-7/5}}$$ as desired.







                              share|cite|improve this answer












                              share|cite|improve this answer



                              share|cite|improve this answer










                              answered Jan 28 '18 at 11:39









                              TheSimpliFireTheSimpliFire

                              12.4k62460




                              12.4k62460























                                  0












                                  $begingroup$

                                  It looks like you made a sign error while combining exponents.



                                  $$frac1{15} - frac23 = frac1{15} - frac{10}{15} = -frac9{15}.$$



                                  You seem to have gotten $-frac{11}{15}$ when you should have gotten $-frac9{15},$ perhaps by flipping the sign of $frac1{15}.$



                                  Of course $-frac9{15} = -frac35,$ and the last step is easy.



                                  The fact that $4 - 11 = -7$ is a complete red herring.
                                  If the problem were just a little different so the denominators happened to be equal, for example if they were both $5,$ you would have
                                  $$ -frac45 - frac{11}5 = -frac{15}5 = -3.$$
                                  So it seems you have a tendency to make sign errors while adding or subtracting. Now that you know this, you may be able to take steps to correct it.






                                  share|cite|improve this answer









                                  $endgroup$


















                                    0












                                    $begingroup$

                                    It looks like you made a sign error while combining exponents.



                                    $$frac1{15} - frac23 = frac1{15} - frac{10}{15} = -frac9{15}.$$



                                    You seem to have gotten $-frac{11}{15}$ when you should have gotten $-frac9{15},$ perhaps by flipping the sign of $frac1{15}.$



                                    Of course $-frac9{15} = -frac35,$ and the last step is easy.



                                    The fact that $4 - 11 = -7$ is a complete red herring.
                                    If the problem were just a little different so the denominators happened to be equal, for example if they were both $5,$ you would have
                                    $$ -frac45 - frac{11}5 = -frac{15}5 = -3.$$
                                    So it seems you have a tendency to make sign errors while adding or subtracting. Now that you know this, you may be able to take steps to correct it.






                                    share|cite|improve this answer









                                    $endgroup$
















                                      0












                                      0








                                      0





                                      $begingroup$

                                      It looks like you made a sign error while combining exponents.



                                      $$frac1{15} - frac23 = frac1{15} - frac{10}{15} = -frac9{15}.$$



                                      You seem to have gotten $-frac{11}{15}$ when you should have gotten $-frac9{15},$ perhaps by flipping the sign of $frac1{15}.$



                                      Of course $-frac9{15} = -frac35,$ and the last step is easy.



                                      The fact that $4 - 11 = -7$ is a complete red herring.
                                      If the problem were just a little different so the denominators happened to be equal, for example if they were both $5,$ you would have
                                      $$ -frac45 - frac{11}5 = -frac{15}5 = -3.$$
                                      So it seems you have a tendency to make sign errors while adding or subtracting. Now that you know this, you may be able to take steps to correct it.






                                      share|cite|improve this answer









                                      $endgroup$



                                      It looks like you made a sign error while combining exponents.



                                      $$frac1{15} - frac23 = frac1{15} - frac{10}{15} = -frac9{15}.$$



                                      You seem to have gotten $-frac{11}{15}$ when you should have gotten $-frac9{15},$ perhaps by flipping the sign of $frac1{15}.$



                                      Of course $-frac9{15} = -frac35,$ and the last step is easy.



                                      The fact that $4 - 11 = -7$ is a complete red herring.
                                      If the problem were just a little different so the denominators happened to be equal, for example if they were both $5,$ you would have
                                      $$ -frac45 - frac{11}5 = -frac{15}5 = -3.$$
                                      So it seems you have a tendency to make sign errors while adding or subtracting. Now that you know this, you may be able to take steps to correct it.







                                      share|cite|improve this answer












                                      share|cite|improve this answer



                                      share|cite|improve this answer










                                      answered Jul 24 '18 at 22:18









                                      David KDavid K

                                      53.9k342116




                                      53.9k342116






























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