Equation/Algebra
$begingroup$
Ethan, Mcdonald and Willie earns $$51700$ a month. Ethan earns $$400$ less than Mcdonald and Willie earns $$3000$ more than Ethan. How much do they all earn each?
Mcdonald's earnings is $X$.
Ethan: $x - $400$
Willie: $x - $400 + 3000$
I don't know the rest of the proccess.
$$X + x - 400 + x - 400 + 3000 = 57100$$
How do you get what each one of them earns?
problem-solving
edited Jan 3 at 16:10
Siong Thye Goh
102k1466118
asked Jan 3 at 16:03
Mumini ErhanMumini Erhan
1
$endgroup$
add a comment |
$begingroup$
Ethan, Mcdonald and Willie earns $$51700$ a month. Ethan earns $$400$ less than Mcdonald and Willie earns $$3000$ more than Ethan. How much do they all earn each?
Mcdonald's earnings is $X$.
Ethan: $x - $400$
Willie: $x - $400 + 3000$
I don't know the rest of the proccess.
$$X + x - 400 + x - 400 + 3000 = 57100$$
How do you get what each one of them earns?
problem-solving
edited Jan 3 at 16:10
Siong Thye Goh
102k1466118
asked Jan 3 at 16:03
Mumini ErhanMumini Erhan
1
$endgroup$
$begingroup$
Solve for $x$, and then find $x-400$ and $x+2600$.
$endgroup$
– KM101
Jan 3 at 16:16
1
$begingroup$
Use better titles, ones that describe the problem better. In this case "solving a system of equations" is far better than "equation/algebra"
$endgroup$
– rschwieb
Jan 3 at 16:21
add a comment |
$begingroup$
Ethan, Mcdonald and Willie earns $$51700$ a month. Ethan earns $$400$ less than Mcdonald and Willie earns $$3000$ more than Ethan. How much do they all earn each?
Mcdonald's earnings is $X$.
Ethan: $x - $400$
Willie: $x - $400 + 3000$
I don't know the rest of the proccess.
$$X + x - 400 + x - 400 + 3000 = 57100$$
How do you get what each one of them earns?
problem-solving
edited Jan 3 at 16:10
Siong Thye Goh
102k1466118
asked Jan 3 at 16:03
Mumini ErhanMumini Erhan
1
$endgroup$
Ethan, Mcdonald and Willie earns $$51700$ a month. Ethan earns $$400$ less than Mcdonald and Willie earns $$3000$ more than Ethan. How much do they all earn each?
Mcdonald's earnings is $X$.
Ethan: $x - $400$
Willie: $x - $400 + 3000$
I don't know the rest of the proccess.
$$X + x - 400 + x - 400 + 3000 = 57100$$
How do you get what each one of them earns?
problem-solving
problem-solving
edited Jan 3 at 16:10
Siong Thye Goh
102k1466118
asked Jan 3 at 16:03
Mumini ErhanMumini Erhan
1
edited Jan 3 at 16:10
Siong Thye Goh
102k1466118
asked Jan 3 at 16:03
Mumini ErhanMumini Erhan
1
edited Jan 3 at 16:10
Siong Thye Goh
102k1466118
edited Jan 3 at 16:10
Siong Thye Goh
102k1466118
edited Jan 3 at 16:10
Siong Thye Goh
102k1466118
102k1466118
asked Jan 3 at 16:03
Mumini ErhanMumini Erhan
1
asked Jan 3 at 16:03
Mumini ErhanMumini Erhan
1
asked Jan 3 at 16:03
Mumini ErhanMumini Erhan
1
1
$begingroup$
Solve for $x$, and then find $x-400$ and $x+2600$.
$endgroup$
– KM101
Jan 3 at 16:16
1
$begingroup$
Use better titles, ones that describe the problem better. In this case "solving a system of equations" is far better than "equation/algebra"
$endgroup$
– rschwieb
Jan 3 at 16:21
add a comment |
$begingroup$
Solve for $x$, and then find $x-400$ and $x+2600$.
$endgroup$
– KM101
Jan 3 at 16:16
1
$begingroup$
Use better titles, ones that describe the problem better. In this case "solving a system of equations" is far better than "equation/algebra"
$endgroup$
– rschwieb
Jan 3 at 16:21
$begingroup$
Solve for $x$, and then find $x-400$ and $x+2600$.
$endgroup$
– KM101
Jan 3 at 16:16
$begingroup$
Solve for $x$, and then find $x-400$ and $x+2600$.
$endgroup$
– KM101
Jan 3 at 16:16
1
1
$begingroup$
Use better titles, ones that describe the problem better. In this case "solving a system of equations" is far better than "equation/algebra"
$endgroup$
– rschwieb
Jan 3 at 16:21
$begingroup$
Use better titles, ones that describe the problem better. In this case "solving a system of equations" is far better than "equation/algebra"
$endgroup$
– rschwieb
Jan 3 at 16:21
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You could first set how much Ethan earned as x and make the equation using,
(x+400) <- How much McDonald earns
(x+3000) <- How much Willie earns
Then you have the equation, x+x+x+400+3000=51700. Or 3x+3400=51700. You then do,
3x=51700-3400=48300
x=48300/3
x=16100 (How much Ethan earns)
Then for McDonald:
16100+400=16500
Then for Willie:
16100+3000=19100
answered Jan 3 at 16:12
SightSight
1
$endgroup$
$begingroup$
Oh I solved it a different way by mistake, my bad. Do you have to solve it with two separate variables? If not, then u could use my method.
$endgroup$
– Sight
Jan 3 at 16:14
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
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votes
active
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votes
$begingroup$
You could first set how much Ethan earned as x and make the equation using,
(x+400) <- How much McDonald earns
(x+3000) <- How much Willie earns
Then you have the equation, x+x+x+400+3000=51700. Or 3x+3400=51700. You then do,
3x=51700-3400=48300
x=48300/3
x=16100 (How much Ethan earns)
Then for McDonald:
16100+400=16500
Then for Willie:
16100+3000=19100
answered Jan 3 at 16:12
SightSight
1
$endgroup$
$begingroup$
Oh I solved it a different way by mistake, my bad. Do you have to solve it with two separate variables? If not, then u could use my method.
$endgroup$
– Sight
Jan 3 at 16:14
add a comment |
$begingroup$
You could first set how much Ethan earned as x and make the equation using,
(x+400) <- How much McDonald earns
(x+3000) <- How much Willie earns
Then you have the equation, x+x+x+400+3000=51700. Or 3x+3400=51700. You then do,
3x=51700-3400=48300
x=48300/3
x=16100 (How much Ethan earns)
Then for McDonald:
16100+400=16500
Then for Willie:
16100+3000=19100
answered Jan 3 at 16:12
SightSight
1
$endgroup$
$begingroup$
Oh I solved it a different way by mistake, my bad. Do you have to solve it with two separate variables? If not, then u could use my method.
$endgroup$
– Sight
Jan 3 at 16:14
add a comment |
$begingroup$
You could first set how much Ethan earned as x and make the equation using,
(x+400) <- How much McDonald earns
(x+3000) <- How much Willie earns
Then you have the equation, x+x+x+400+3000=51700. Or 3x+3400=51700. You then do,
3x=51700-3400=48300
x=48300/3
x=16100 (How much Ethan earns)
Then for McDonald:
16100+400=16500
Then for Willie:
16100+3000=19100
answered Jan 3 at 16:12
SightSight
1
$endgroup$
You could first set how much Ethan earned as x and make the equation using,
(x+400) <- How much McDonald earns
(x+3000) <- How much Willie earns
Then you have the equation, x+x+x+400+3000=51700. Or 3x+3400=51700. You then do,
3x=51700-3400=48300
x=48300/3
x=16100 (How much Ethan earns)
Then for McDonald:
16100+400=16500
Then for Willie:
16100+3000=19100
answered Jan 3 at 16:12
SightSight
1
answered Jan 3 at 16:12
SightSight
1
answered Jan 3 at 16:12
SightSight
1
answered Jan 3 at 16:12
SightSight
1
1
$begingroup$
Oh I solved it a different way by mistake, my bad. Do you have to solve it with two separate variables? If not, then u could use my method.
$endgroup$
– Sight
Jan 3 at 16:14
add a comment |
$begingroup$
Oh I solved it a different way by mistake, my bad. Do you have to solve it with two separate variables? If not, then u could use my method.
$endgroup$
– Sight
Jan 3 at 16:14
$begingroup$
Oh I solved it a different way by mistake, my bad. Do you have to solve it with two separate variables? If not, then u could use my method.
$endgroup$
– Sight
Jan 3 at 16:14
$begingroup$
Oh I solved it a different way by mistake, my bad. Do you have to solve it with two separate variables? If not, then u could use my method.
$endgroup$
– Sight
Jan 3 at 16:14
add a comment |
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$begingroup$
Solve for $x$, and then find $x-400$ and $x+2600$.
$endgroup$
– KM101
Jan 3 at 16:16
1
$begingroup$
Use better titles, ones that describe the problem better. In this case "solving a system of equations" is far better than "equation/algebra"
$endgroup$
– rschwieb
Jan 3 at 16:21