Eigenvector relations between matrices whose Gramian Matrices are the same
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I have two symmetric real matrices I am interested in, $A_{ntimes n}$ and $B_{mtimes m}$. If I do the following operations:
$$EAE^{T}=FBF^{T}$$
where $E$ and $F$ are of dimensions $ptimes n$ and $ptimes m$ respectively.
Supposed that the $A$ and $B$ can be eigen-decomposed as $A=Q_ALambda_A Q_A^{T}$, $B=Q_BLambda_B Q_B^{T}$, and thus the previous equation can be written as
$$EQ_ALambda_A Q_A^{T}E^{T}=FQ_BLambda_B Q_B^{T}F^{T}$$
where $Q$ and $Lambda$ are matrices containing eigenvectors and eigenvalues, respectively
or in the form as
$$(EQ_ALambda_A^{1/2}) (EQ_ALambda_A^{1/2} )^T=(FQ_BLambda_B^{1/2}) (FQ_BLambda_B^{1/2} )^T.$$
If I further let $K=EQ_ALambda_A^{1/2}$ and $L=FQ_BLambda_B^{1/2}$, then I obtain
$$KK^T=LL^T.$$
Here come my questions:
- What are the relations between $Q_A$ and $Q_B$?
- To simplify the first question, my strategy is to obtain $KK^{T}=LL^{T}$ as mentioned, and find the relations between $K$ and $L$ first. That is, what are the relations between matrices with the same Gramian matrix?
I found the answer in wiki, which says, "...in finite-dimensions it determines the vectors up to isomorphism, i.e. any two sets of vectors with the same Gramian matrix must be related by a single unitary matrix." But I still can not understand what it exactly means.
Thus, can anyone help me with these two questions or give me any references to read?
linear-algebra matrix-decomposition matrix-analysis
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I have two symmetric real matrices I am interested in, $A_{ntimes n}$ and $B_{mtimes m}$. If I do the following operations:
$$EAE^{T}=FBF^{T}$$
where $E$ and $F$ are of dimensions $ptimes n$ and $ptimes m$ respectively.
Supposed that the $A$ and $B$ can be eigen-decomposed as $A=Q_ALambda_A Q_A^{T}$, $B=Q_BLambda_B Q_B^{T}$, and thus the previous equation can be written as
$$EQ_ALambda_A Q_A^{T}E^{T}=FQ_BLambda_B Q_B^{T}F^{T}$$
where $Q$ and $Lambda$ are matrices containing eigenvectors and eigenvalues, respectively
or in the form as
$$(EQ_ALambda_A^{1/2}) (EQ_ALambda_A^{1/2} )^T=(FQ_BLambda_B^{1/2}) (FQ_BLambda_B^{1/2} )^T.$$
If I further let $K=EQ_ALambda_A^{1/2}$ and $L=FQ_BLambda_B^{1/2}$, then I obtain
$$KK^T=LL^T.$$
Here come my questions:
- What are the relations between $Q_A$ and $Q_B$?
- To simplify the first question, my strategy is to obtain $KK^{T}=LL^{T}$ as mentioned, and find the relations between $K$ and $L$ first. That is, what are the relations between matrices with the same Gramian matrix?
I found the answer in wiki, which says, "...in finite-dimensions it determines the vectors up to isomorphism, i.e. any two sets of vectors with the same Gramian matrix must be related by a single unitary matrix." But I still can not understand what it exactly means.
Thus, can anyone help me with these two questions or give me any references to read?
linear-algebra matrix-decomposition matrix-analysis
New contributor
The statement on the wiki is saying that if $A A^T=B B^T$ then there exists an orthogonal matrix $Q$ with $A=BQ$.
– Ian
yesterday
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have two symmetric real matrices I am interested in, $A_{ntimes n}$ and $B_{mtimes m}$. If I do the following operations:
$$EAE^{T}=FBF^{T}$$
where $E$ and $F$ are of dimensions $ptimes n$ and $ptimes m$ respectively.
Supposed that the $A$ and $B$ can be eigen-decomposed as $A=Q_ALambda_A Q_A^{T}$, $B=Q_BLambda_B Q_B^{T}$, and thus the previous equation can be written as
$$EQ_ALambda_A Q_A^{T}E^{T}=FQ_BLambda_B Q_B^{T}F^{T}$$
where $Q$ and $Lambda$ are matrices containing eigenvectors and eigenvalues, respectively
or in the form as
$$(EQ_ALambda_A^{1/2}) (EQ_ALambda_A^{1/2} )^T=(FQ_BLambda_B^{1/2}) (FQ_BLambda_B^{1/2} )^T.$$
If I further let $K=EQ_ALambda_A^{1/2}$ and $L=FQ_BLambda_B^{1/2}$, then I obtain
$$KK^T=LL^T.$$
Here come my questions:
- What are the relations between $Q_A$ and $Q_B$?
- To simplify the first question, my strategy is to obtain $KK^{T}=LL^{T}$ as mentioned, and find the relations between $K$ and $L$ first. That is, what are the relations between matrices with the same Gramian matrix?
I found the answer in wiki, which says, "...in finite-dimensions it determines the vectors up to isomorphism, i.e. any two sets of vectors with the same Gramian matrix must be related by a single unitary matrix." But I still can not understand what it exactly means.
Thus, can anyone help me with these two questions or give me any references to read?
linear-algebra matrix-decomposition matrix-analysis
New contributor
I have two symmetric real matrices I am interested in, $A_{ntimes n}$ and $B_{mtimes m}$. If I do the following operations:
$$EAE^{T}=FBF^{T}$$
where $E$ and $F$ are of dimensions $ptimes n$ and $ptimes m$ respectively.
Supposed that the $A$ and $B$ can be eigen-decomposed as $A=Q_ALambda_A Q_A^{T}$, $B=Q_BLambda_B Q_B^{T}$, and thus the previous equation can be written as
$$EQ_ALambda_A Q_A^{T}E^{T}=FQ_BLambda_B Q_B^{T}F^{T}$$
where $Q$ and $Lambda$ are matrices containing eigenvectors and eigenvalues, respectively
or in the form as
$$(EQ_ALambda_A^{1/2}) (EQ_ALambda_A^{1/2} )^T=(FQ_BLambda_B^{1/2}) (FQ_BLambda_B^{1/2} )^T.$$
If I further let $K=EQ_ALambda_A^{1/2}$ and $L=FQ_BLambda_B^{1/2}$, then I obtain
$$KK^T=LL^T.$$
Here come my questions:
- What are the relations between $Q_A$ and $Q_B$?
- To simplify the first question, my strategy is to obtain $KK^{T}=LL^{T}$ as mentioned, and find the relations between $K$ and $L$ first. That is, what are the relations between matrices with the same Gramian matrix?
I found the answer in wiki, which says, "...in finite-dimensions it determines the vectors up to isomorphism, i.e. any two sets of vectors with the same Gramian matrix must be related by a single unitary matrix." But I still can not understand what it exactly means.
Thus, can anyone help me with these two questions or give me any references to read?
linear-algebra matrix-decomposition matrix-analysis
linear-algebra matrix-decomposition matrix-analysis
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edited 9 hours ago
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Charlie
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The statement on the wiki is saying that if $A A^T=B B^T$ then there exists an orthogonal matrix $Q$ with $A=BQ$.
– Ian
yesterday
add a comment |
The statement on the wiki is saying that if $A A^T=B B^T$ then there exists an orthogonal matrix $Q$ with $A=BQ$.
– Ian
yesterday
The statement on the wiki is saying that if $A A^T=B B^T$ then there exists an orthogonal matrix $Q$ with $A=BQ$.
– Ian
yesterday
The statement on the wiki is saying that if $A A^T=B B^T$ then there exists an orthogonal matrix $Q$ with $A=BQ$.
– Ian
yesterday
add a comment |
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The statement on the wiki is saying that if $A A^T=B B^T$ then there exists an orthogonal matrix $Q$ with $A=BQ$.
– Ian
yesterday