Finding $P(Y leq 0.49)$ with standard normal distribution











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The problem is as such below



enter image description here



With the given information:



$P(Y leq 0.49)$ and I am provided a standard normal distribution table (which I think is meant for this question...)



So I believe I have to find $F(0.49)=Phi(frac{0.49-mu}{sigma})=Phi(frac{0.49-0}{frac{1}{100}})$ , central limit theorem, and $Phi(49)$ is wrong as 49 is too big for Z. So did I approach the problem wrong, or did I make a mistake by applying the central limit theorem and standard normal distribution assumptions.






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    up vote
    0
    down vote

    favorite












    The problem is as such below



    enter image description here



    With the given information:



    $P(Y leq 0.49)$ and I am provided a standard normal distribution table (which I think is meant for this question...)



    So I believe I have to find $F(0.49)=Phi(frac{0.49-mu}{sigma})=Phi(frac{0.49-0}{frac{1}{100}})$ , central limit theorem, and $Phi(49)$ is wrong as 49 is too big for Z. So did I approach the problem wrong, or did I make a mistake by applying the central limit theorem and standard normal distribution assumptions.






    probability proof-verification







    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      The problem is as such below



      enter image description here



      With the given information:



      $P(Y leq 0.49)$ and I am provided a standard normal distribution table (which I think is meant for this question...)



      So I believe I have to find $F(0.49)=Phi(frac{0.49-mu}{sigma})=Phi(frac{0.49-0}{frac{1}{100}})$ , central limit theorem, and $Phi(49)$ is wrong as 49 is too big for Z. So did I approach the problem wrong, or did I make a mistake by applying the central limit theorem and standard normal distribution assumptions.






      probability proof-verification







      share|cite|improve this question













      The problem is as such below



      enter image description here



      With the given information:



      $P(Y leq 0.49)$ and I am provided a standard normal distribution table (which I think is meant for this question...)



      So I believe I have to find $F(0.49)=Phi(frac{0.49-mu}{sigma})=Phi(frac{0.49-0}{frac{1}{100}})$ , central limit theorem, and $Phi(49)$ is wrong as 49 is too big for Z. So did I approach the problem wrong, or did I make a mistake by applying the central limit theorem and standard normal distribution assumptions.






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      asked 10 hours ago









      glockm15

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